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VARVARA [1.3K]
1 year ago
12

One reason spectroscopists study excited states is to gain information about the energies of orbitals that are unoccupied in an

atom’s ground state. Each of the following electron configurations represents an atom in an excited state. Identify the element, and write its condensed ground-state configuration:
(a) 1s²2s²2p⁶3s¹3p¹
(b) 1s²2s²2p⁶3s²3p⁴4s¹
(c) 1s²2s²2p⁶3s²3p⁶4s²3d⁴4p¹
(d) 1s²2s²2p⁵3s¹
Chemistry
1 answer:
Tanya [424]1 year ago
5 0

Answer:

a) Mg

b) Cl

c) Mn

d) Ne

Explanation:

This electron configuration for the atom in its excited state violates the Aufbau principle or rule like we have above.

Aufbau principle states "that in the ground state of an atom or ion, electrons fill atomic orbitals of the lowest available energy levels before occupying higher levels."

We however can know and identify which element is in the excited state by knowing the sum of the electron that spread across the orbital and matching it up with the atomic number of the element in the periodic table.

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When 500.0 g of water is decomposed by electrolysis and the yield of hydrogen is only 75.3%, how much hydrogen chloride can be m
Evgen [1.6K]

The amount of hydrogen chloride that can be made is 1064 g

Why?

The two reactions are:

2H₂O → 2H₂ + O₂ 75.3 % yield

H₂ + Cl₂ → 2HCl 69.8% yield

We have to apply a big conversion factor to go from grams of water (The limiting reactant), to grams of HCl, the final product. We have to be very careful with the coefficients and percentage yields!

500.0gH_2O*\frac{1moleH_2O}{18.01 gH_2O}*\frac{2 moles H_2}{2 moles H_2O}*\frac{2.015g H_2}{1 mole H_2}*\frac{75.3 actual g}{100 theoretical g}=42.12 g H_2

42.12H_2*\frac{1 mole H_2}{2.015gH_2}*\frac{2 moles HCl}{1 mole H_2}*\frac{36.46g}{1 mole HCl}*\frac{69.8 actualg}{100 theoreticalg} =1064gHCl

Have a nice day!

#LearnwithBrainly

7 0
2 years ago
Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution
Aliun [14]

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}

or,

\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}

First we have to calculate the equivalent weight of solute.

Molar mass of solute PO_4^{3-} = 94.97 g/mole

\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq

Now we have to calculate the normality of solution.

\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L

Therefore, the normality of the solution is, 30.006 N

5 0
1 year ago
Wade thinks it would be really cool to become a radiologist. Which two skills are important for him to have in order to excel in
zlopas [31]

ANSWER: The two skills that Wade will need to excel in the career of a Radiologist are:

1. Interpersonal skills to talk to patients and help them feel comfortable: This skill important because patients often are afraid of getting detected by a disease. Few patients also fear of getting tested by the heavy and complicated machineries. A radiologist's interpersonal skill will calm the patient and his attendant and will make them feel relieved.

2. Technical skills to know how to use the machinery and equipment needed for the job: Radiologist's primary duty is to operate the machineries in order to diagnose a patient correctly. A radiologist can not afford to be an amateur as he will either not be able to detect a disease or may raise a false alarm of a person having a disease.

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2 years ago
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What do pH and conductivity have in common?
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PH and conductivity have no common rekationship
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After recrystallization, the final weight of biphenyl is found to be 0.02 g. Assume that all steps were carried out correctly, n
Lubov Fominskaja [6]

Explanation:

From the source, The student recrystallized biphenyl by using benzene. Biphenyl is non polar and so is benzene. Biphenyl is very soluble in benzene at low as well as high temperature. Thus, it do not recrystallize as like dissolves like and gives a very poor yield.

The good recovery of the product is dependent on compound having high solubility at the high temperatures and having low solubility at the low temperatures.

6 0
2 years ago
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