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aniked [119]
1 year ago
11

MUSCLES IN A KANGAROO'S LEGS WORK BECAUSE OF THE CELLS THAT MAKE UP THE MUSCLE. WHICH COMPONENT OF CELL THEORY DOES THIS BEST IL

LUSTRATE? :)

Chemistry
2 answers:
valkas [14]1 year ago
7 0

Answer: OPTION B

Explanation:

Cells are generated from nonliving materials. Muscles in a kangaroo's legs work because of the cells that make up the muscle. The component of cell theory this best illustrate is: Cells are the basic unit of structure and function of all living things

Fed [463]1 year ago
4 0

Answer:

b

Explanation:

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The percentage of silver in a solid sample is determined gravimetrically by converting the silver to Ag+ (aq) and precipitating
Wittaler [7]

Answer:

D

Explanation:

I - You should account the mass of the weighing paper to reduce it from the total mass at the end of the process, having only the mass of the Silver Chloride.

II - The precipitation of the silve chloride will occur independently of the temperature, because the Kps of this salt is very low (Ksp = [Ag+] .[Cl-]).

III - Washing the precipitate will secure the purity of the final product, it won't allow any other contaminant to be in your precipitante which could change your final mass.

IV - You should heat you AgCl precipitate so it will be dry, because of that the mass you will obtain is only the mass of the weighing paper and the silver chloride and nothing else.

8 0
1 year ago
Read 2 more answers
(1.) 163.26 g/mol, C11H17N
qwelly [4]

Answer:

75

Explanation:

4 0
2 years ago
A substance has a density of 4.5gmL. What is this in kgL? Report your answer with two significant figures.
Ipatiy [6.2K]

Answer:

4.5 kg/L

Explanation:

Density is 4.5g/mL and it means that in 1 mL of volume, the mass contained is 4.5 g.

Let's make a rule of three

1L = 1000 mL

1 mL has a mass of 4.5 g

1000 mL would have 4500 g

Our new density would be 4500 g/L, but we may convert the g to kg

1 kg / 1000 g . 4500 g = 4.5 kg

In conclusion 4.5 g/mL = 4.5 kg/L

7 0
2 years ago
In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)
Brrunno [24]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.6 L  

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}

{V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L

{V_2}=0.27\ L

<u>The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.</u>

8 0
2 years ago
Write the expression for the equilibrium constant Kp for the following reaction.Enclose pressures in parentheses and do NOT writ
maxonik [38]

<u>Answer:</u> The expression for K_p is written below.

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as K_p

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_p is written as:

K_p=\frac{P_{C}^c\times P_{D}^d}{P_{A}^a\times P_{B}^b}

The partial pressure for solids and liquids are taken as 1.

For the given chemical equation:

NH_4HS(s)\rightleftharpoons NH_3(g)+H_2S(g)

The expression for K_p for the following equation is:

K_p=\frac{(P NH_3)\times (P H_2S)}{(P NH_4HS)}

The partial pressure of NH_4HS will be 1 because it is solid.

So, the expression for K_p now becomes:

K_p=\frac{(P NH_3)\times (P H_2S)}{1}

Hence, the expression for K_p is written above.

5 0
2 years ago
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