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IgorC [24]
2 years ago
11

List the number of each type of atom on the left side of the equation C5H12(g)+8O2(g)→5CO2(g)+6H2O(g) C 5 H 12 ( g ) + 8 O 2 ( g

) → 5 C O 2 ( g ) + 6 H 2 O ( g ) Enter your answers separated by commas (the order of the numbers is the same as the order of the elements on the left side of the equation).
Chemistry
2 answers:
Gala2k [10]2 years ago
5 0

Answer:

Carbon=5, hydrogen=12, oxygen=16

Explanation:

Carbon=5, hydrogen=12, oxygen=16

In order to effectively count the number of atoms, we look at the equation closely and take note of the stoichiometric coefficients of each reactant as this influences the number of atoms of that element present.

For instance, oxygen is diatomic and has a stoichiometric coefficient of 8. This implies the there are sixteen atoms of oxygen altogether.

Note that the left hand side refers to the reactants side.

slega [8]2 years ago
4 0

Answer:

Explanation:

Equation of the reaction:

C5H12(g) + 8O2(g) → 5CO2(g) + 6H2O(g)

1. Ensure the equation of the reaction is balanced properly.

2. Pick any side of the reaction a d List the atoms present.

Carbon, C = 5 atoms

Oxygen, O = (8 × 2)

= 16 atoms

Hydrogen, H = 5 atoms

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The reaction between sulfur dioxide and oxygen is reversible.
RUDIKE [14]

Explanation:

the correct answer is

D) 0.636 mol/dm³

3 0
2 years ago
A gold wire has a diameter of 1.00 mm. What length of this wire contains exactly 1.00 mol of gold? (density of Au = 17.0 g/cm3)
allochka39001 [22]

Answer:

The answer to your question is 7160 cm

Explanation:

Data

diameter = 1 mm

length = ?

amount of gold = 1 mol

density = 17 g/cm³

Process

1.- Get the atomic mass of gold

Atomic mass = 197 g

then, 197g ------------ 1 mol

2.- Calculate the volume of this wire

density = mass/volume

volume = mass/density

volume = 197/17

volume = 5.7 cm³

3.- Calculate the length of the wire

Volume = πr²h

solve for h

h = volume /πr²

radius = 0.05 cm

substitution

h = 5.7/(3.14 x 0.05²)

h = 5.7 / 0.0025

h = 7159.2 cm ≈ 7160 cm

8 0
2 years ago
Read 2 more answers
When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6
Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

Explanation:

Wavelength of the photon emitted = \lambda =646.3 nm =646.3\times 10^{-9} m

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

E=\frac{hc}{\lambda }

h = Planck's constant = 6.626\tiomes 10^{-34} Js

c = Speed of the light = 3\times 10^8 m/s

E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}

E=3.07\times 10^{-19} J

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

3 0
2 years ago
a compound contain 8.57g of carbon and 1.43g of hydrogen. The relative formula mass is 70 calculate the empirical formula of the
yanalaym [24]

Answer:

Empirical formula: CH2

Molecular formula: C5H10

5 0
1 year ago
Which of the following species contains manganese with the highest oxidation number?
ioda

In NaMnO₄, Mn has the highest oxidation number.

The question is incomplete, the complete question is;

Which of the following species contains manganese with the highest oxidation number?

A) Mn

B) MnF₂

C) Mn₃(PO₄)₂

D) MnCl₄

E) NaMnO₄

In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.

1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.

2) For MnF₂;

Mn has an oxidation number of +2

3) For Mn₃(PO₄)₂

Mn has an oxidation number of +2

4) For MnCl₄

Mn has an oxidation number of +4

5) For NaMnO₄

Mn has an oxidation number of +7

Hence in NaMnO₄, Mn has the highest oxidation number.

Learn more: brainly.com/question/10079361

7 0
2 years ago
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