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1 year ago

3. Mercury is a liquid metal that has a density of 13.58 g/mL. Calculate the volume of mercury

Chemistry

1 answer:

Alona [7]1 year ago

5 0

Answer:

0.03682 mL of mercury

Explanation:

We know the density of the mercury which is 13.58 g/mL

density = mass / volume

volume = mass / density

Now we can calculate the volume of 0.5 g of mercury:

volume = 0.5 / 13.58 = 0.03682 mL of mercury

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Determine the molar solubility of CuCl in a solution containing 0.050 KCl. Ksp of CuCl is 1.0 x 10-6

Volgvan

Answer:

$2.0x10^{-5}\frac{mol}{L}$

Explanation:

Hello!

In this case, since the dissolution of copper (I) chloride is:

$CuCl(s)\rightarrow Cu^++Cl^-$

And its equilibrium expression is:

$Ksp=[Cu^+][Cl^-]$

We can represent the molar solubility via the reaction extent as $x$ , however, since there is 0.050 M KCl we immediately add such amount to the chloride ion concentration since KCl is readily ionized; therefore we write:

$1.0x10^{-6}=(x)(0.050+x)$

Thus, solving for $x$ , we obtain:

$1.0x10^{-6}=0.050x+x^2\\\\x^2+0.050x-1x10^{-6}=0$

By using the quadratic equation, we obtain:

$x_1=2.0x10^{-5}M\\\\x_2=-0.05M$

Clearly, the solution is $x_1=2.0x10^{-5}M$ because no negative results are

allowed. Therefore, the molar solubility is:

$2.0x10^{-5}\frac{mol}{L}$

Best regards!

5 0

1 year ago

How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation? 2HBr(aq)+

Mkey [24]

Full Question:

A flask containing 420 Ml of 0.450 M HBr was accidentally knocked to the floor.?

How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation?

2HBr(aq)+K2CO3(aq) ---> 2KBr(aq) + CO1(g) + H2O(l)

Answer:

13.1 g K2CO3 required to neutralize spill

Explanation:

2HBr(aq) + K2CO3(aq) → 2KBr(aq) + CO2(g) + H2O(l)

Number of moles = Volume * Molar Concentration

moles HBr= 0.42L x .45 M= 0.189 moles HBr

From the stoichiometry of the reaction;

1 mole of K2CO3 reacts with 2 moles of HBr

1 mole = 2 mole

x mole = 0.189

x = 0.189 / 2 = 0.0945 moles

Mass = Number of moles * Molar mass

Mass = 0.0945 * 138.21 = 13.1 g

3 0

1 year ago

a 15.0 kg chunk of ice falls off the top of an iceberg if the chunk of ice Falls 8.00 to the surface of the water what is the ki

kvv77 [185]

When we can get the Kinetic energy from this formula KE= 1/2 M V^2and we can get the potential energy from this formula PE = M g H
we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so, KE = PE
1/2 MV^2 = M g H
1/2 V^2 = g H
when V is the velocity, g is an acceleration of gravitational force (9.8 m^2/s) and H is the height of the fall (8 m).
∴ v^2 = 2 * 9.8 * 8 = 156.8
∴ v= √156.8 = 12.5 m/s

8 0

1 year ago

At the beginning of the school year, a chalk company receives an order for 2000 boxes which is the largest order ever placed. Ea

lys-0071 [83]

Answer:

259,000 g of chalk.

Explanation:

1) Data:

a) 2000 boxes

b) 175 g / box

c) % yield = 74%

2) Formula:

% yield = (theoretical yield / actual yield) × 100

3) Solution:

a) Calcualte the actual yield:

mass of product = 2000 box × 175 g/ box = 350,000 g

b) Solve for the theoretical yield from the % yield formula:

% yield = (theoretical yield / actual yield) × 100

⇒ theoretical yield = % yield × actual yield / 100

theoretical yield = 74% × 350,000g / 100 = 259,000 g

6 0

1 year ago

Which quantity can vary among atoms of the same element?

Wewaii [24]

There is this thing called isotopes
it means that atoms of the same element can have a different number of neutrons.
if there is a change in the no. of neutrons, there will definitely be a change in the mass number.

so the answer is A) mass number

7 0

1 year ago