First, we write the half equations for the reduction of the chemical species present:
Cu⁺² + 2e → Cu; E° = 0.34 V
Ni⁺² + 2e → Ni; E° = - 0.23 V
In order to determine the potential of the cell, we find the difference between the two values. For this:
E(cell) = 0.34 - (-0.23)
E(cell) = 0.57 V
The second option is correct. (The difference in values is due to different values in literature, and it is negligible)
Q is unlike K value it describes the reaction that is not at equilibrium.
by considering this reaction:
aA+ bB⇄ cC
and our reaction is:
Br2 + Cl2 ⇄ 2 BrCl
According to Q low:
Q= concentration of products/concentration of reactants
but this equation in the gaseous or aqueous states only.
∴ Q = [BrCl]^2 / [Br2] [Cl2]
and we have [Br2] = 0.00366 m [Cl2]= 0.000672 m [BrCl] = 0.00415 m
by substitution:
= [0.00415]^2 / ( [0.00366] * [0.000672])
∴ Q = 7
Answer:
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Explanation:
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<u>1. Dissociation equation</u>
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Assuming 100% dissociation, the equation is:
- Ba(C₂H₃O₂)₂ → Ba²⁺ + 2C₂H₃O₂⁻
↑
acetate ions
<u>2. Molarity</u>
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Calculate the molarity, M, of the solution:
- n = mass in grams / molar mass
- n = 69.g / 255.415g/mol = 0.27015 mol
- M = 0.27015mol / 0.970liter = 0.27850 mol/liter ≈ 0.28M
<u>3. Acetate ions</u>
From the chemical equation, 1 mol of dissolved Ba(C₂H₃O₂)₂ produces 2 acetate ions in solution.
Thus, 0.28 mol/liter × 2 = 0.56 mol/liter = 0.56M ← answer
Answer:
C.12.3%. you need to use pv=nRT (ideal gas law)
