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Makovka662 [10]

2 years ago

14

Selena is learning about how engineers choose metals for spacecraft. She discovers that spacecraft engineers often mix other met

als with titanium. Titanium is a metal that is both lightweight and strong. It also resists corrosion. Selena wants to compare titanium with other metals. She looks at the cell from the periodic table that represents titanium.
Explain what each of the four items in the cell represents. Then, classify titanium as an alkali, alkali earth, or transition metal.

1 answer:

Elena-2011 [213]2 years ago

7 0

Ti is a transition metal.

<h3>Further explanation</h3>

Chemical symbol represent element or compound

The elements are arranged in the periodic system

1. 22

This is the atomic number of Titanium

The Atomic Number (Z) indicates the number of protons of an element

2. Ti

This is the symbol (chemical formula) of titanium

3. 47.90

This is the mass number of Titanium

Mass Number (A) = Number of protons + Number of Neutrons

Atomic Number (Z) = Mass Number (A) - Number of Neutrons

4. Titanium

This is the name of the element

To determine which group, alkaline, alkaline earth or transition it can be seen from the electron configuration

alkali and alkali earth : configuration from orbital 1s-7s

transition : configuration from orbital 3d-6d (Block d)

Electron configuration from Ti : [Ar] 3d²4s²

if we look at the configuration, then Ti is in the d block which is included in the transition metal

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Rank the following acids in order of increasing acid strength. Key: Weakening of hydrogen bond and stability of resulting anion.

raketka [301]

Explanation:

The given compounds are oxyacids and in these compounds more is the electronegativity of the central atom more will be its acidic strength.

This is because more is the electronegativity of the central atom more will be the polarity of OH bond. As a result, the compound can readily lose $H^{+}$ ion.

Also, more is the electronegativity of central atom more will be the stability of conjugate base formed.

Thus, we can conclude that given compounds are arranged in increasing acid strength as follows.

HOI < $HOBr_{2}$ < $HOCl_{3}$ < HOF

8 0

2 years ago

In the chemical equation 3c2h4 how many atoms of carbon are represented

Scorpion4ik [409]

An example.
water is H2O

2 hydrogen, 1 oxygen

so the number to the right means how much of what is on the left.

so it looks like 2, because C2, but look at the 3 at the beginning. that means
3 (c2h4)

so 6 carbons, 12 hydrogen

the ratio of c2 to h4 doesn't change it's always 1:2.

but the 3 at the front is a different number relating to how much you have

5 0

2 years ago

Which of the following is a valid conversion factor?

VMariaS [17]

Answer:

100 cg/1g

Step-by-step explanation:

1 cg = 0.01 g Multiply by 100

100 cg = 1 g

(a) is <em>wrong</em>. The correct conversion factor is 1000 cm³/1 L.

(b) is <em>wrong</em>. The correct conversion factor is 1000 mL/1 L.

(c) is <em>wrong</em>. The correct conversion factor is 1 m/10 dm.

7 0

2 years ago

Read 2 more answers

How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})$

$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

$[CH_3COONa]=?mol$

$[CH_3COOH]=0.200mol$

pH = 5.00

Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

$[CH_3COONa]=0.364mol$

To calculate the mass of sodium acetate for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0

2 years ago

Complete the equation for the dissociation of cdcl2(aq). omit water from the equation because it is understood to be present.

mixas84 [53]

Cadmium chloride is a highly soluble compound. The equation for its dissolution is:

CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

This dissociation in water allows for the cadmium and chlorine ions to take part in reactions. This is the reason that solutions of chemicals are prepared when a reaction needs to take place.

3 0

2 years ago