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tia_tia [17]
2 years ago
9

Who helps recycle nutrients through an ecosystem? A. producers and decomposers B. producers and consumers C. consumers and decom

posers D. producers, consumers, and decomposers
Chemistry
2 answers:
s2008m [1.1K]2 years ago
8 0

D. Producers im sure of it hope im right

Nonamiya [84]2 years ago
3 0
<h2>Answer:</h2>

The correct answer is option A which is producers and decomposers.

<h3>Explanation:</h3>
  • In the food chain of an ecosystem, Producers are the organism which make food taking nutrients from soil and energy from sun like plants.
  • Consumers are organism which consume this food by plants like animal.
  • And decomposers are organism which convert complex food materiel into simple one like bacteria.
  • As recycling is the use and reuse of material in ecosystem.
  • Hence decomposers and producer are using materials again and again with the help of each other.
  • So they both are helping in recycle of materials in ecosystem.
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How many grams of copper (II) nitrate would be produced from 0.80 g of copper metal reacting with excess nitric acid?
zaharov [31]

Answer:

m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2

Explanation:

Hello!

In this case, since the chemical reaction between copper and nitric acid is:

2HNO_3+Cu\rightarrow Cu(NO_3)_2+H_2

By starting with 0.80 g of copper metal (molar mass = 63.54 g/mol) and considering the 1:1 mole ratio between copper and copper (II) nitrate (molar mass = 187.56 g/mol) we can compute that mass via stoichiometry as shown below:

m_{Cu(NO_3)_2}=0.80gCu*\frac{1molCu}{63.54gCu} *\frac{1molCu(NO_3)_2}{1molCu} *\frac{187.56gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2

However, the real reaction between copper and nitric acid releases nitrogen oxide, yet it does not modify the calculations since the 1:1 mole ratio is still there:

4HNO_3+Cu\rightarrow Cu(NO_3)_2+2H_2O+2NO_2

Best regards!

7 0
2 years ago
List the number of each type of atom on the left side of the equation 2C6H14(l)+19O2(g)→12CO2(g)+14H2O(g) Enter your answers sep
murzikaleks [220]

<u>Answer:</u> The number of carbon, hydrogen and oxygen atoms on the left side of the reaction are 12, 28 and 38 respectively

<u>Explanation:</u>

In a chemical equation, the chemical species are termed as reactants or products.

Reactants are defined as the species which react in the reaction and are written on the left side of the reaction arrow.

Products are defined as the species which are produced in the reaction and are written on the right side of the reaction arrow.

For the given chemical equation:

2C_6H_{14}(l)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(g)

On the reactant side:

Number of carbon atoms = (6 × 2) = 12

Number of hydrogen atoms = (14 × 2) = 28

Number of oxygen atoms = (2 × 19) = 38

Hence, the number of carbon, hydrogen and oxygen atoms on the left side of the reaction are 12, 28 and 38 respectively

3 0
2 years ago
What volume of a 0.160 m solution of koh must be added to 450.0 ml of the acidic solution to completely neutralize all of the ac
inna [77]
An  acidic  solution  is 0.1M  in  HCl  and  0.2  H2so4. volume  is  equal  to  no  of  moles  divided  by  molarity.  
number  of  moles  of  HCl is  450ml x 0.1  divided  by 1000  which is equal  to 0.045 moles
volume  of  HCl   is  therefore  0.45  divided  by  0.16  which  is   2.81  litres

Number  of  moles  of  H2so4  is  450ml x 0.2  divided  by  1000  which  is  equal  to  0.09  moles
volume  of  H2SO4  IS  0.09 divided  by  0.16  which  is  equal  to  0.56 litres

4 0
2 years ago
Read 2 more answers
Calculate the internal energy of 2 moles of argon gas (assuming ideal behavior) at 298 K. Suggest two ways to increase its inter
Dominik [7]
I hope this helps you.

5 0
2 years ago
Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What nu
masya89 [10]

Answer : The number placed in front of CuSO_4 should be, three (3).

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of chloride and sulfate ion are not balanced.

In order to balanced the chemical reaction, the coefficient 3 is put before the CuSO_4, the coefficient 2 is put before the AlCl_3 and the coefficient 3 is put before the CaCl_2.

Thus, the balanced chemical reaction will be,

3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3

Therefore, the number placed in front of CuSO_4 should be, three (3).

5 0
2 years ago
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