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tia_tia [17]
2 years ago
9

Who helps recycle nutrients through an ecosystem? A. producers and decomposers B. producers and consumers C. consumers and decom

posers D. producers, consumers, and decomposers
Chemistry
2 answers:
s2008m [1.1K]2 years ago
8 0

D. Producers im sure of it hope im right

Nonamiya [84]2 years ago
3 0
<h2>Answer:</h2>

The correct answer is option A which is producers and decomposers.

<h3>Explanation:</h3>
  • In the food chain of an ecosystem, Producers are the organism which make food taking nutrients from soil and energy from sun like plants.
  • Consumers are organism which consume this food by plants like animal.
  • And decomposers are organism which convert complex food materiel into simple one like bacteria.
  • As recycling is the use and reuse of material in ecosystem.
  • Hence decomposers and producer are using materials again and again with the help of each other.
  • So they both are helping in recycle of materials in ecosystem.
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The human body can get energy by metabolizing proteins, carbohydrates or fatty acids, depending on the circumstances. Roughly sp
Ede4ka [16]

Answer:

3:1

Explanation:

Stearic acid - C18H36O2

Fructose- C6H12O6

Since the energy content of food is roughly proportional to the carbon content. It means:

C18/C6 = 3 or 3:1

This explains why fats and oil are the major source of energy in the body and not carbohydrates. This is due to Fats and oil having larger amounts of Carbon compared to Carbohydrates.

6 0
2 years ago
A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
Paladinen [302]

The concentration of a solution is the number of moles of solute per fixed volume of solution.

Concentration (C) = number of moles of solute (n) / volume of the solution (v)

we have to find the volume of the solution when 36.0 g of Ca(OH)₂ is added to water to make a solution of concentration 0.530 M

mass of Ca(OH)₂ added - 36.0 g

number of moles of Ca(OH)₂ - 36.0 g / 74.1 g/mol = 0.486 mol

we know the concentration of the solution prepared and the number of moles of Ca(OH)₂ added, substituting these values in the above equation, we can find the volume of the solution

C = n/v

0.530 mol/L = 0.486 mol / V

V = 0.917 L

answer is 0.917 L

6 0
2 years ago
Read 2 more answers
Recording station x has determined that the epicenter of a recent earthquake was 250 km away. no information is available yet fr
KatRina [158]
The epicenter was located somewhere on a circle centered at Recording station X, with a radius of 250 km.<span>
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7 0
2 years ago
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If one starts with pure NO2(g) at a pressure of 0.500 atm, the total pressure inside the reaction vessel when 2NO2(g) 2NO(g) + O
natulia [17]

Answer:

The partial pressure of NO2  = 0.152 atm

Explanation:

Step 1: Data given

Pressure NO2 = 0.500 atm

Total pressure at equilibrium = 0.674 atm

Step 2: The balanced equation

2NO2(g) → 2NO(g) + O2(g)

Step 3: The initial pressure

pNO2 = 0.500 atm

pNO = 0 atm

p O2 = 0 atm

Step 4: Calculate pressure at the equilibrium

For 2 moles NO2 we'll have 2 moles NO and 1 mol O2

pNO2 = 0.500 - 2x atm

pNO =2x atm

pO2 = xatm

The total pressure = p(total) = p(NO2) + p(NO) + p(O2)

p(total) = (0.500 - 2x) + 2x + x= 0.674 atm

0.500 + x = 0.674 atm

x = 0.174 atm

This means the partial pressure of NO2 = 0.500 - 2*0.174 = 0.152 atm

6 0
2 years ago
Nitrogen dioxide decomposes to nitric oxide and oxygen via the reaction: 2NO2 → 2NO + O2 In a particular experiment at 300 °C, [
serious [3.7K]

Answer: The rate of disappearance of NO_2 is 3.5\times 10^{-5}M/s

Explanation:

The given chemical reaction is:

2NO_2\rightarrow 2NO+O_2

The rate of the reaction for disappearance of NO_2 is given as:

\text{Rate of disappearance of }NO_2=-\frac{\Delta [NO_2]}{\Delta t}

Or,

\text{Rate of disappearance of }NO_2=-\frac{C_2-C_1}{t_2-t_1}

where,

C_2 = final concentration of NO_2 = 0.00650 M

C_1 = initial concentration of NO_2 = 0.0100 M

t_2 = final time = 100 minutes

t_1 = initial time = 0 minutes

Putting values in above equation, we get:

\text{Rate of disappearance of }NO_2=-\frac{0.00650-0.0100}{100-0}\\\\\text{Rate of disappearance of }NO_2=3.5\times 10^{-5}M/s

Hence, the rate of disappearance of NO_2 is 3.5\times 10^{-5}M/s

6 0
2 years ago
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