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2 years ago

Which of the following pairs lists a substance that can neutralize HNO3 and the salt that would be produced from the reaction?

Chemistry

1 answer:

Nutka1998 [239]2 years ago

5 0

NH₃, being a basic gas neutralizes the HNO₃ forming a salt NH₄NO₃

Therefore the correct answer is NH₃ and NH₄NO₃

The solution of which only 32% dissociates to release OH⁻ ions is a weak base. This is because some of the energy is used when the substance reacts with the solution thus some bonds are not broken.

HCl is an acid. This is because it dissociates in water to give H⁺ as the only positively charged ions.

Arrhenius acid increases the concentration of hydrogen ions because it dissociates to release hydrogen ions as the only positively charged ions in the acid. So the answer is TRUE

Arrhenius base dissociates in water to release hydroxide ions as the only negatively charged ions.

NaOH⁺aq⇒Na⁺ ₍aq₎+ OH⁻₍aq₎

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Boron - 10 emits alpha particles and cesium - 137 emits beta particles. Write balanced nuclear

anzhelika [568]

Answer:

B10 5N +5P= Li6 3N +3P

Cs 137 82N+55P = I 133 80N + 53P

Explanation:

8 0

2 years ago

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How many moles of lead (ii) chromate are in 51 grams of this substance? answer in units of mol?

maria [59]

Mass of lead (II) chromate is 51 g. The molecular formula is $PbCrO_{4}$ and its molar mass is 323.2 g/mol

Number of moles can be calculated using the following formula:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass.

Putting the values,

$n=\frac{(51 g}{323.1937 g/mol}=0.1578 mol$

Therefore, number of moles of lead (II) chromate will be 0.1578 mol.

5 0

1 year ago

For nitrogen gas the values of Cv and Cp at 25°C are 20.8 J K−1 mol−1 and 29.1 J K−1 mol−1, respectively. When a sample of nitro

kifflom [539]

Answer:

The fraction of energy used to increase the internal energy of the gas is 0.715

Explanation:

Step 1: Data given

Cv for nitrogen gas = 20.8 J/K*mol

Cp for nitrogen gas = 29.1 J/K*mol

Step 2:

At a constant volume, all the heat will increase the internal energy of the gas.

At constant pressure, the gas expands and does work., if the volume changes.

Cp= Cv + R

⇒The value needed to change the internal energy is shown by Cv

⇒The work is given by Cp

To find what fraction of the energy is used to increase the internal energy of the gas, we have to calculate the value of Cv/Cp

Cv/Cp = 20.8 J/K*mol / 29.1 J/K*mol

Cv/Cp = 0.715

The fraction of energy used to increase the internal energy of the gas is 0.715

3 0

1 year ago

Read 2 more answers

Describe an electron cloud. Then, name and explain a particular atomic model that used the concept of the electron cloud.

pochemuha

Electron cloud is the region around the nucleus in an atom where we can locate an electron.

The concept of electron cloud model was introduced by the Schrodinger and Heisenberg. According to this model, it would be difficult to know the position of the electrons in an atom and they are not particles that orbit around the nucleus. We can only expect the electrons to be present in specific areas called the electron clouds around the nucleus. It is the quantum mechanical model that used the concept of electron clouds. According to the model, the electron cloud or an orbital is a space around the nucleus in an atom where the probability of finding an electron is 90%. It explains that electrons show wave nature. It is difficult to determine the exact position and momentum of an electron in an atom.

3 0

1 year ago

Consider the reaction H2(g) + Cl2(g) → 2HCl(g)ΔH = −184.6 kJ / mol If 2.00 moles of H2 react with 2.00 moles of Cl2 to form HCl,

zalisa [80]

Answer:

ΔU=-369.2 kJ/mol.

Explanation:

We start from the equation:

Δ(H)=ΔU+Δ(PV), which is an extension of the well known relation: H=U+PV.

If Δ(PV) were calculated by ideal gas law,

PV=nRT

Δ(PV)=RTΔn.

Where Δn is the change of moles due to the reaction; but, this reaction does not give a moles change (Four moles of HCl produced from 4 moles of reactants), so Δ(PV)=0.

So, for this case, ΔH=ΔU.

The enthalpy of reaction given is for one mole of reactant, so the enthalpy of reaction for the reaction of interest must be multiplied by two:

$2 reactant moles*\frac{-184.6kJ}{mol}$

ΔU=-369.2 kJ/mol.

4 0

2 years ago