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2 years ago

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Which of the following pairs lists a substance that can neutralize HNO3 and the salt that would be produced from the reaction?

1 answer:

Nutka1998 [239]2 years ago

5 0

NH₃, being a basic gas neutralizes the HNO₃ forming a salt NH₄NO₃

Therefore the correct answer is NH₃ and NH₄NO₃

The solution of which only 32% dissociates to release OH⁻ ions is a weak base. This is because some of the energy is used when the substance reacts with the solution thus some bonds are not broken.

HCl is an acid. This is because it dissociates in water to give H⁺ as the only positively charged ions.

Arrhenius acid increases the concentration of hydrogen ions because it dissociates to release hydrogen ions as the only positively charged ions in the acid. So the answer is TRUE

Arrhenius base dissociates in water to release hydroxide ions as the only negatively charged ions.

NaOH⁺aq⇒Na⁺ ₍aq₎+ OH⁻₍aq₎

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What mass of solid NaOH (97.0 % by mass) is required to prepare 1.00 L of a 10.0% solution of NaOH by mass? The density of the 1

Lelechka [254]

<u>Answer:</u> The mass of 97 % of NaOH solution required is 114.33 g

<u>Explanation:</u>

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of 10 % solution = 1.109 g/mL

Volume of 10% solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1.109g/mL=\frac{\text{Mass of }10\%\text{ solution}}{1000mL}\\\\\text{Mass of }10\%\text{ solution}=1109g$

The mass of 10 % solution is 1109 g.

To calculate the mass of concentrated solution, we use the equation:

$c_1m_1=c_2m_2$

where,

$c_1\text{ and }m_1$ are the concentration and mass of concentrated solution.

$c_2\text{ and }m_2$ are the concentration and mass of diluted solution.

We are given:

$c_1=97\%\\m_1=?g\\c_2=10\%\\m_2=1109g$

Putting values in above equation, we get:

$97\times m_1=10\times 1109\\\\m_1=114.33g$

Hence, the mass of 97 % of NaOH solution required is 114.33 g

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2 years ago

Acidosis is a human body disorder caused by too much acid in the stomach. If a patient was tested for this using their saliva an

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In Philip’s French class, the students are learning how to pronounce closed vowels and open vowels. The students are most likely

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2 years ago

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A gas occupies 72.1 at stp. At what temperature would the gas occupy 85.9 L at a pressure of 93.6 kPa?

Alika [10]

Answer:

328.1 K.

Explanation:

To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT</em>.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in.

If n is constant, and have two different values of (P, V and T):

<em>P₁V₁T₂ = P₂V₂T₁</em>

<em></em>

P₁ = 1.0 atm (standard P), V₁ = 72.1 L, T₁ = 25°C + 273 = 298 K (standard T).

P₂ = 93.6 kPa = 0.924 atm, V₂ = 85.9 L, T₂ = ??? K.

<em>T₂ = P₂V₂T₁/P₁V₁ = </em>(0.924 atm)(85.9 L)(298 K)/(1.0 atm)(72.1 L) <em>= 328.1 K.</em>

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2 years ago

`suppose you were tasked with producing some nitrogen monoxide (a.k.a. nitric oxide). i'm sure this is often requested of you. y

Umnica [9.8K]

N(H₂O):n(NO)=6:4(3:2), n(NO)=2·3,5mol÷3=2,33mol
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2 years ago

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