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1 year ago

Describe an electron cloud. Then, name and explain a particular atomic model that used the concept of the electron cloud.

Chemistry

1 answer:

pochemuha1 year ago

3 0

Electron cloud is the region around the nucleus in an atom where we can locate an electron.

The concept of electron cloud model was introduced by the Schrodinger and Heisenberg. According to this model, it would be difficult to know the position of the electrons in an atom and they are not particles that orbit around the nucleus. We can only expect the electrons to be present in specific areas called the electron clouds around the nucleus. It is the quantum mechanical model that used the concept of electron clouds. According to the model, the electron cloud or an orbital is a space around the nucleus in an atom where the probability of finding an electron is 90%. It explains that electrons show wave nature. It is difficult to determine the exact position and momentum of an electron in an atom.

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One mole of h2s gas escapes from a container by effusion in 77 seconds how long would it take one mole of nh3 gas to escape from

gizmo_the_mogwai [7]

The molar masses of H2S and NH3 are 34 and 17 g/mol, respectively. The equation that would best represent the given is,
Rate A/Rate B = √(molar mass B/molar mass A)
Substituting,
x/77 = √(17 /34 )
x = 54.4
Thus, it will take 54.4 seconds for NH3 to travel through the container.

3 0

2 years ago

Read 2 more answers

A sample of copper with a mass of 63.5g contains 6.02 x10^23 atoms calculate the mass of an average copper atom

m_a_m_a [10]

Answer:

The mass of an average copper atom is $1.0548\times 10^{-22}\ g$

Explanation:

Given:

The total mass of copper atoms, $m = 63.5\ g$

Number of atoms, $N=6.02\times 10^{23}$

Now, we are asked to find the mass of 1 copper atom.

We use unitary method to find the mass of 1 copper atom.

Mass of $N$ atoms = m

∴ Mass of 1 atom = $\frac{m}{N}$

Plug in 63.5 for 'm', $6.02\times 10^{23}$ for 'N' and simply.

Mass of 1 atom = $\dfrac{63.5}{6.02\times 10^{23}}=1.0548\times 10^{-22}\ g$

Therefore, the mass of an average copper atom is $1.0548\times 10^{-22}\ g$

5 0

2 years ago

Determine the concentration of an aqueous solution that has an osmotic pressure of 3.9 atm at 37°C if the solute is sodium chlor

Snowcat [4.5K]

Answer:

Concentration for the solution is 0.153 mol/L

Explanation:

Formula for the osmotic pressure is π = M . R . T . i

where M is molarity (concentration), R the universal constant for gases and T is Absolute T° (T°C + 273)

π = Osmotic pressure.

Let's replace the data given:

3.9 atm = M . 0.082L.atm/mol.K . 310K

3.9 atm / 0.082 mol.K/L.atm . 310K = 0.153 mol/L (M)

i = Van't Hoff factor (ions from the solute dissolved in solution)

In this case, we assumed no ion pairing, so i = 1

8 0

2 years ago

Calculate the theoretical yield if 100.0 g p4o10 react with 200.0 g h2o

Lina20 [59]

The reaction of Phosphorous Pentaoxide with water yield Phosphoric Acid as shown below,

P₄O₁₀ + 6 H₂O → 4 H₃PO₄

According to balance equation,

283.88 g (1 mole) P₄O₁₀ requires = 108 g (6 mole) of H₂O
So,
100 g P₄O₁₀ will require = X g of H₂O

Solving for X,

X = (100 g × 108 g) ÷ 283.88 g

X = 38.04 g of H₂O

So, 100 g P₄O₁₀ requires 38.04 g of H₂O, while we are provided with 200 g of H₂O which means that water is in excess and P₄O₁₀ is limiting reagent. Therefore, P₄O₁₀ will control the yield of H₃PO₄. So,
As,
283.88 g (1 mole) P₄O₁₀ produced = 391.96 g (4 mole) of H₃PO₄
So,
100 g P₄O₁₀ will produce = X g of H₃PO₄

Solving for X,
X = (100 g × 391.96 g) ÷ 283.88 g

X = 138.07 g of H₃PO₄

Result:
Theoretical Yield of this reaction is 138.07 g.

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2 years ago

A 2.0-g sample of washing soda, Na CO • 10H O, has carbon atoms. How many oxygen atoms are present in 2.0g of washing soda?

vovikov84 [41]

Description is on the picture in attachment

7 0

2 years ago