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solong [7]
2 years ago
5

A scientist measures the mass of two liquids before and after combining them. The mass after combining the liquids is less then

the sum of the masses before. where is the missing mass? what type of change occured.
Chemistry
1 answer:
Lelu [443]2 years ago
4 0

Answer:

A chemical change occurred and a gas was produced.  

Step-by-step explanation:

If there is no chemical reaction, the <em>Law of Conservation of Mass</em> says that  

Total mass = Mass 1 + Mass 2

However, if the two liquids react and give off a gas, then

Total mass = Mass 1 + Mass 2 + Mass of gas

You are not measuring the mass of the gas, so the mass of the liquids after mixing is less than it was before mixing.

For example, if Liquid 1 was a solution of HCl and Liquid 2 was a solution of Na₂CO₃, they would give off CO₂ on mixing. but you would not be measuring the mass of the CO₂.

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15. Using the information below, calculate ΔHf° for PbO(s)
Svet_ta [14]
ΔH(reaction) = ΔH(formation of products) - ΔH(formation of reactants) 
ΔH(reaction) = ( 1*ΔH(Pb(s)) + 1*ΔH(CO2(g)) ) - ( 1*ΔH(PbO(s)) + 1*ΔH(CO(g)) ) 
ΔH(reaction) = ( 0 + -393.5 ) - ( ΔH(PbO(s)) + -110.5 ) 
ΔH(reaction) = -283 - ΔH(PbO(s)) 
-131.4 = -283 -ΔH(PbO(s)) 
ΔH(PbO(s)) = -151.6 kJ

So, the best answer is A.
5 0
2 years ago
Read 2 more answers
1. Complete the following Data Table as you conduct the lab
miskamm [114]

Answer:

Do to half of the mnairals this can not be made into a lab there is an error

Explanation:

4 0
2 years ago
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A beaker contains a dilute sodium chloride solution at 1 atmosphere. What happens to the number of solute particles in the solut
SCORPION-xisa [38]

Answer:

The number of solute particles increases, and the boiling point increases.

Explanation:

  • It is known from colligative properties that adding solute to the solvent will cause elevation of boiling point.
  • Elevation of boiling point (ΔTb) can be expressed as:

<em>ΔTb = Kb.m,</em>

where, Kb molal boiling point elevation constant.

m is the molal concentration of solute.

  • Adding more sodium chloride to the solution:

will increase the number of solute particles and also will increase the molal concentration of NaCl solute.

<em>∵ ΔTb ∝ m.</em>

  • So, the boiling point increases.

  • Thus, the right choice is:

<em>The number of solute particles increases,</em>

<em></em>

5 0
2 years ago
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Solid calcium carbonate (CaCO3) reacts with hydrochloric acid (HCI) to form carbon dioxide, water, and
Pavlova-9 [17]

Using a more concentrated HCl solution and Crushing the CaCO₃ into a fine powder makes the reaction to occur at a faster rate.

<u>Explanation:</u>

CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(aq) + CO₂(g)

When calcium carbonate reacts with hydrochloric acid, it gives out carbon-dioxide in the form of bubbles and there is a formation of calcium chloride in aqueous medium.

The rate of the reaction can be increased by

  • Using a more concentrated HCl solution
  • Crushing the CaCO₃ into a fine powder

When concentrated acid is used instead of dilute acid then the reaction will occur at a faster rate.

When CaCO₃ is crushed into a fine powder then the surface area will increases thereby increasing the rate of the reaction.

3 0
2 years ago
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Which of the following represents a propagation step in the monochlorination of methylene chloride (CH2Cl2)?a. CHCl3 + Cl. Right
svetlana [45]

Answer:

B = CHCl2 + Cl2 --> CHCl3 + Cl

Explanation:

Free radical halogenation is a chlorination reaction on Alkane hydrocarbons. This involves the splitting of molecules into radicals/ unstable molecules in the presence of sunlight/ U.V light which ensures bonding of the molecules.

Free radical chlorination is divided into 3 steps which are:

The initiation step

The propagation step

The termination step

So in reference to the question, propagation step involves two steps.

The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.

The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.

You would find in the attachment the 2 step mechanism.

3 0
2 years ago
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