answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FromTheMoon [43]
2 years ago
15

1. Bailey wants to find out which frozen solid melts the fastest: soda, gatorade, or orange juice. She pours each of the three l

iquids into the empty cubes of an ice tray, along with a forth liquid, plain water. She then places the ice tray in the freezer over night. The next day, she pulls the ice tray out and sets each cube on its
own plate. She then waits and watches for them to melt. When the last part of the frozen liquid melts, she records the time.

Independent Variable:
Dependent Variable:
Control(s):
Constants:

--

2. Jack wants to find out which laundry detergent cleans the best. So, he takes a cotton sheet and cuts it up into equal squares. He stains four squares with chocolate. He washes one of each of the squares in each of the 3 detergents, and the final square is washed in plain water. For each wash load, he used: the same amount of water, the same amount of detergent, and the same temperature of water.

Independent Variable:
Dependent Variable:
Control(s):
Constants:

---

Maverick wants to find out whether or not Miracle Grow really makes plants grow faster. He takes two identical pots, puts ½ cup of dirt into each one, puts 3 pea plant seeds into each one, and tops each off with ½ cup more dirt. He waters the plants the same amount at the same time each day. The only difference is that one plant is watered with regular water, while the other is watered with water that has Miracle Grow in it.

Independent Variable:
Dependent Variable:
Controls(s):
Constants:
Chemistry
2 answers:
Vanyuwa [196]2 years ago
8 0

Answer:

The scientific experiments are performed to test the hypothesis which comprises of three kinds of variables: independent, dependent and constant variables.

1. Independent variables: are the variables which can be manipulated that is controlled and can be changed.

2. Dependent variables: are the variables which are tested in the experiment.

3. Constant variable: the variable which is kept constant throughout the experiments but can affect the dependent variable.

4. Control: The sample which does not contain the dependent variable.

On the basis of this in the given cases the identified variables are:

Case I

Independent variables-Time and night time.

Dependent variables- melting state of liquid  

Constant variable- freezer, and ice tray

Control- plain water  

Case II

Independent variables- chocolate, type of cloth, squares of cloth

Dependent variables- the type of laundry detergent

Constant variable- the same amount of water, detergent and temperature.

Control- square washed with plain water.

Case III

Independent variables- Time

Dependent variables- plant growth

Constant variable-  pots and an equal amount of water provided

Control- pots which were not watered by Miracle

vesna_86 [32]2 years ago
4 0

First situation:

IV: soda, gatorade, orange juice, and water

DV: state of IV listed above

Control: freezer, and ice tray

Second Situation:

IV: laundry detergent, water

DV: result of the squares after being washed

Control: chocolate, type of cloth, squares of cloth

Third Situation:

IV: Water used, pea plant

DV: growth of pea plant

Control: pots and amount of water plant gets each day

You might be interested in
Two weak acids, A and B, have pKa values of 4 and 6, respectively. Which statement is true?A) Acid A dissociates to a greater ex
zalisa [80]

Answer:

A) Acid A dissociates to a greater extent in water than acid B

Explanation:

A) Acid A dissociates to a greater extent in water than acid B

We are given the pKa for both acids, and we know

pKa = - log Ka

Taking antilog to both sides of the equation we can solve for Ka

⇒ -pKa = log Ka

-antilog pKa = Ka

10 ^-pka = Ka

So ka for acid A = 10⁻⁴

and

ka for acid B = 10⁻⁶

True the equilibrium constant for acid A is greater, so it dissociates more.

B) For solutions of equal concentration, acid B will have a lower pH.

We know the stronger acid is A, and it dissociates more. Since pH is the negative log of H₃O⁺ concentration, it follows that at equal concentrations the acid A will have at equilibrium a greater [H₃O⁺] and hence a lower pH

C) B is the conjugate base of A

False:

If B were the conjugate base of A, its  Kb would have been given by:

Ka x Kb = Kw

Kb = 10⁻¹⁴/10⁻⁶ = 10⁻⁸ for the conjugate base of acid B

Kb = 10⁻¹⁴/10⁻⁴ = 10⁻¹⁰ for the conjugate base of acid A

which are not equal.

D) Acid A is more likely to be a polyprotic acid than acid B.

False

Just having the pkas for both acids one cannot know if any of the acids is polyprotic. We will need the formula for the acids.

E) The equivalence point of acid A is higher than that of acid B

False

The equivalence point depends on the the concentration of the acids  and their volumes.

The equivalence point is reached in the titration when the number of equivalents of base equals the number of equivalents of acid:

# equivalents acid = # equivalents of base  @ end point

and

# equivalents acid = Molarity of acid x Volume of acid

4 0
2 years ago
What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2?
Anna11 [10]
Molar mass  CaCl₂ =  110.98 g/mol

Number of moles:

1 mole CaCl₂ ---------> 110.98 g
n mole CaCl2 ---------> 85.3 g

n = 85.3 / 110.98

n = 0.7686 moles of CaCl₂

Volume = ?

M = n / V

0.788 =  0.7686 / V

V = 0.7686 / 0.788

V = 0.975 L

hope this helps!
5 0
2 years ago
Consider the dissolution of MnS in water (Ksp = 3.0 × 10–14). MnS(s) + H2O(l) Mn2+(aq) + HS–(aq) + OH–(aq) How is the solubility
Mademuasel [1]

Answer:

The solubility of MnS will decrease on addition of KOH solution.

Explanation:

As per the equation given:

MnS(s)+H_{2}O(l) -->Mn^{+2}(aq)+HS^{-}(aq)+OH^{-}(aq)

On dissolution of MnS in water it gives a basic solution as it gives hydroxide ions.

Now when the we are adding aqueous KOH solution, it will dissociate as:

KOH(aq)--->K^{+}(aq)+OH^{-}(aq)

Thus it will further furnish more hydroxide ion,

This will increase the concentration of hydroxide ions (present of product side), the system will try to decrease its concentration by shifting towards reactant side.

Thus the solubility of MnS will decrease on addition of KOH solution.

7 0
2 years ago
Nuclear power plants produce energy using fission. One common fuel, uranium-235, produces energy through the fission reaction 23
Vikentia [17]

Answer:

mass of U-235  = 15.9 g (3 sig. figures)

Explanation:

1 atom can produce -------------------------> 3.20 x 10^-11 J energy

x atoms can produce ----------------------> 1.30 x 10^12 J energy

x = 1.30 x 10^12 / 3.20 x 10^-11

x = 4.06 x 10^22 atoms

1 mol ----------------------> 6.023 x 10^23 atoms

y mol ----------------------> 4.06 x 10^22 atoms

y = 0.0675 moles

mass of U-235 = 0.0675 x 235 = 15.8625

mass of U-235  = 15.9 g (3 sig. figures)

7 0
2 years ago
Sea water's density can be calculated as a function of the compressibility, B, where p = po exp[(p - Patm)/B]. Calculate the pre
vaieri [72.5K]

Answer:

The pressure 10,000 m below the surface of the sea is 137.14 MPa.

The density 10,000 m below the surface of the sea is 2039 kg/m3

Explanation:

P0 and ρ0 are the pressure and density at the sea level (atmosferic condition). As the depth of the sea increases, both the pressure and the density increase.

We can relate presure and density as:

\frac{dP}{dy}=\rho*g=\rho_0*g*e^{(P-P_0)/\beta\\\\

Rearranging

\frac{dP}{e^{(P-P_0)/\beta}}= \rho_0*g*dy\\\\\int\limits^{P}_{P_0} {e^{-(P-P_0)/\beta}}dP =\int\limits^y_0 {\rho_0*g*dy}\\\\(-\beta*e^{-(P-P_0)/\beta})-(\beta*e^0)=\rho_0*g*(y-0)\\\\-\beta*(e^{-(P-P_0)/\beta}-1)=\rho_0*g*y\\\\e^{-(P-P_0)/\beta}=1-\frac{\rho_0*g*y}{\beta}\\\\-\frac{P-P_0}{\beta}  =ln(1-\frac{\rho_0*g*y}{\beta})\\\\P-P_0=-\beta*ln(1-\frac{\rho_0*g*y}{\beta})\\

With this equation, we can calculate P at 10,000 m below the surface:

P-P_0=-\beta*ln(1-\frac{\rho_0*g*y}{\beta})\\\\P-P_0=-200MPa*ln(1-\frac{1027kg/m^3*9.81m/s^2*10,000m}{200MPa})\\\\P-P_0=-200MPa*ln(1-\frac{1027*9.81*10,000Pa}{200*10^6Pa})\\\\P-P_0=-200MPa*ln(1-0.5037)\\\\P-P_0=-200MPa*(-0.6857)=137.14MPa

The density at 10,000 m below the surface of the sea is

\rho=\rho_0*e^{(P-P_0)/\beta}\\\rho=1027kg/m^3*e^{(137.14/200)}=1027*e^{0.686}kg/m^3\\\rho=1027*1.985 kg/m^3\\\rho=2039\,kg/m^3

4 0
2 years ago
Other questions:
  • Which statement describes the transfer of heat energy that occurs when an ice cube is added to an insulated container with 100 m
    7·1 answer
  • The mass of a solid copper penny is 3.46 g. how many copper atoms are in the penny?
    9·2 answers
  • An article about half-lives describes a daughter isotope. What is a daughter isotope?
    10·1 answer
  • Write the electronic configurations for mn, mn2+, mn4+, mn6+, and mn7+
    13·1 answer
  • The Karez well system _______. a. was the first known use of wells b. was a postindustrial system c. transported groundwater fro
    6·2 answers
  • The half-life of C-14 is 5470 years. If a particular archaeological sample has one-quarter of its original radioactivity remaini
    15·2 answers
  • Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ 1) H2(g)+12O2(g)⟶H2O
    7·1 answer
  • The pressure and temperature inside a bike tire is 10 atm and 10k respectively. What will the pressure become in the tire when t
    7·1 answer
  • How many grams of Boron can be obtained from 234 grams of B2O3?
    8·1 answer
  • Circle the molecule(s) in the atmosphere that come from animals. (circle all that apply)
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!