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mart [117]
2 years ago
14

0.01 M HCl solution has a pH of 2. Suppose that during the experiment, both the universal pH indicator and the cabbage indicator

turn orange-red for 0.01 M HCl. What can you conclude about the the cabbage indicator key?
Chemistry
4 answers:
evablogger [386]2 years ago
6 0
A) It matches the universal pH indicator and is indicating the proper pH. Yes, this is correct. Have a great day!
NNADVOKAT [17]2 years ago
5 0
It matches the universal pH indicator and is indicating the proper pH
zvonat [6]2 years ago
5 0

Answer:

A ) it matches the universal pH indicator and is indicating the proper pH

Novay_Z [31]2 years ago
4 0
YOU ARE PROBABLY CHEATING RIGHT NOW!!! ... that's cool ig...
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A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL
ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

6 0
2 years ago
Calculate the maximum concentration (in m) of silver ions (ag+) in a solution that contains 0.025 m of co32-. the ksp of ag2co3
Helen [10]
Equilibrium equation is

<span>Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) </span>

<span>From the reaction equation above, the formula for Ksp: </span>

<span>Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 </span>
<span>You know  [CO32-], so you can solve for [Ag+] as: </span>
<span>(8.1 x 10^-12) = [Ag+]^2 (0.025) </span>
<span>[Ag+]^2 = 3.24 x 10^-10 </span>
<span>[Ag+] = 1.8 x 10^-5 M </span>
5 0
2 years ago
Name the region of the atom where protons and neutrons are located. This region is indicated by label B. Name the region of the
11Alexandr11 [23.1K]

Protons and neutrons are located at the nucleus.

Electrons are located on the outer shells, or orbitals.

Subatomic Particles are located inside of the atoms. Protons, neutrons, and electrons.

7 0
2 years ago
Read 2 more answers
How many grams are contained in a 0.893 mol sample of methane, ch4?
irina [24]

We are given with a compound, Methane (CH4), with a molar mass of 0.893 mol sample. We are tasked to solve for it's corresponding mass in g. We need to solve first the molecular weight of Methane, that is

C=12 g/mol

H=1g/mol

 

CH4= 12 g/mol +1(4) g/mol = 16 g/mol

With 0.893 mol sample, its corresponding mass is

g CH4= 0.893 mol x 16g/mol =14.288 g

Therefore, the mass of methane is 14.288 g

6 0
1 year ago
how many moles of potassium would you need to prepare 1200 grams of 5.0% potassium sulfate (m/m) solution
Marianna [84]
The  moles  of  potassium  that  you  would    need  to  prepare  1200 g  of  5% potassium   sulfate solution  is    1.538 moles

calculation
  calculate  the mass  potassium using  the below formula

%M/M =  mass  of the  solute(potassium)/mass of the  solvent (potassium  sulfate solution)

let  the  mass  of  potassium be represented by  Y

then  convert %  into fraction  = 5/100

5/100 =  Y/1200
cross  multiplication
100y =  6000
divide  both side by 100

Y=  60 g

moles of potassium =mass/molar  mass

= 60/39=1.538
7 0
2 years ago
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