how many moles of potassium would you need to prepare 1200 grams of 5.0% potassium sulfate (m/m) solution

1 answer:

7 0

The moles of potassium that you would need to prepare 1200 g of 5% potassium sulfate solution is 1.538 moles

calculation
calculate the mass potassium using the below formula

%M/M = mass of the solute(potassium)/mass of the solvent (potassium sulfate solution)

let the mass of potassium be represented by Y

then convert % into fraction = 5/100

5/100 = Y/1200
cross multiplication
100y = 6000
divide both side by 100

Y= 60 g

moles of potassium =mass/molar mass

= 60/39=1.538

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