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miskamm [114]
2 years ago
9

how many moles of potassium would you need to prepare 1200 grams of 5.0% potassium sulfate (m/m) solution

Chemistry
1 answer:
Marianna [84]2 years ago
7 0
The  moles  of  potassium  that  you  would    need  to  prepare  1200 g  of  5% potassium   sulfate solution  is    1.538 moles

calculation
  calculate  the mass  potassium using  the below formula

%M/M =  mass  of the  solute(potassium)/mass of the  solvent (potassium  sulfate solution)

let  the  mass  of  potassium be represented by  Y

then  convert %  into fraction  = 5/100

5/100 =  Y/1200
cross  multiplication
100y =  6000
divide  both side by 100

Y=  60 g

moles of potassium =mass/molar  mass

= 60/39=1.538
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-3.7771 × 10² kJ/mol

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where,

n: moles

ΔG°f(): standard Gibbs free energy of formation

p: products

r: reactants

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5 0
2 years ago
A 45 mL sample of nitrogen gas is cooled from 135ºC to 15C in a container that can contract or expand at constant pressure. Wha
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Answer:

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Mathematical expression:

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V₂ = V₁T₂/T₁  

V₂ = 45 mL × 288 K / 408 k

V₂ = 12960 mL.K / 408 K

V₂ =31.8 mL

8 0
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