Answer:
Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.
Explanation:
Volume of NaOH = 1.7 ml = 0.0017 L
Molarity of NaOH = 0.0811 M
Moles of NaOH = n
n = 0.0001378 mol
According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.
Then 0.0001378 mol of NaOH will neutralize:
of sulfuric acid.
Concentration of sulfuric acid in the acid rain sample: x
Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.
Explanation:
The given data is as follows.
= 253.4 nm =
(as 1 nm =
)
= 5,
= ?
Relation between energy and wavelength is as follows.
E =
=
= J
=
Hence, energy released is .
Also, we known that change in energy will be as follows.
where, Z = atomic number of the given element
0.02 + 0.04 =
=
= 4
Thus, we can conclude that the principal quantum number of the lower-energy state corresponding to this emission is n = 4.