(~26grams/mole) and Avogadros # (6.022x10^23) 84.3grams x 1mole/26grams x 6.022x10^23 molecules/mole = 1.95x10^24 molecules of C2H2
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The balanced equation for the reaction is,
N₂(g) + 3H₂(g) ⇄ 2NH₃(g)
Since the given concentrations are taken at the equilibrium state, we can use those directly for the calculation.
Kc = [NH₃(g)]² / ([N₂(g)] x [H₂(g)]³)
Kc = (0.75 M)² / ((0.31 M) x (<span>1.51 M</span>)³)
Kc = 0.527 M⁻²
The molality of a substance is the moles of the substance present in 1000mL or 1L or 1Kg of water. 1L of water is equivalent to 1Kg of water as the density of water is 1g/mL. The molecular mass of a substance is represent the amount of the substance present in 1 mole of the compound. Here the molar mass of glucose is 180 daltons thus 1 mole of glucose is equivalent to 180 daltons. To prepare 1 molar glucose solution 180 daltons of glucose have to dissolve in 1L of water. So to prepare 2 molar glucose solution (180×2) = 360 daltons of glucose have to dissolve in 1000mL or 1L or 1Kg of water.
Answer:
The volume required for complete neutralize is 32.29 mL
Explanation:
The computation of the volume required for complete neutralize is shown below:
As we know that, the balanced equation is

Now
The number of moles of
= n_1 = 1
And, the number of moles of Hcl = n_2 = 2
Therefore
The equation i.e. to be used to find out the volume is given below:


= 32.29 mL
Hence, the volume is 32.29mL