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Alenkinab [10]
1 year ago
13

Copper atoms are heavier than magnesium atoms. So, although each atom of magnesium can produce one atom of copper, the masses wo

n’t be the same. The ratio of the atomic weight of copper to the atomic weight of magnesium is about 2.61. Given this ratio and the initial mass of the magnesium strip (0.38 g) measured in task 1, part A, calculate the mass of copper that can be produced. Recall: Mg + Cu(NO3)2 → Cu + Mg(NO3)2
Chemistry
1 answer:
Ilya [14]1 year ago
8 0

Answer:

m_{Cu}=0.99gCu

Explanation:

Hello!

In this case, considering the given chemical reaction and the mass of the magnesium strip, following the indications of the atomic weight ratio (2.61 g Cu/1 g Mg), and keeping in mind the 1:1 mole ratio one could compute the produced mass of copper as shown below:

m_{Cu}=0.38gMg*\frac{2.61gCu}{1gMg} \\\\m_{Cu}=0.99gCu

Best regards!

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Answer:

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Explanation:

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Primarily, Thomson's experiment led to the discovery of cathode rays, electrons, as subatomic particles.

If the size of the atoms observed at the cathode is the same as that of the rays,we can conclude that the particles of the rays are the simplest form of matter we can have. This would suggest that the atom is indeed the smallest indivisible particle of a matter according to Dalton.

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