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Alenkinab [10]
1 year ago
13

Copper atoms are heavier than magnesium atoms. So, although each atom of magnesium can produce one atom of copper, the masses wo

n’t be the same. The ratio of the atomic weight of copper to the atomic weight of magnesium is about 2.61. Given this ratio and the initial mass of the magnesium strip (0.38 g) measured in task 1, part A, calculate the mass of copper that can be produced. Recall: Mg + Cu(NO3)2 → Cu + Mg(NO3)2
Chemistry
1 answer:
Ilya [14]1 year ago
8 0

Answer:

m_{Cu}=0.99gCu

Explanation:

Hello!

In this case, considering the given chemical reaction and the mass of the magnesium strip, following the indications of the atomic weight ratio (2.61 g Cu/1 g Mg), and keeping in mind the 1:1 mole ratio one could compute the produced mass of copper as shown below:

m_{Cu}=0.38gMg*\frac{2.61gCu}{1gMg} \\\\m_{Cu}=0.99gCu

Best regards!

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Watch the video to determine which of the following relationships are correct according to Boyle’s law.
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Answer:

Part A

Boyle's Law is given mathematically as

P ∝(1/V) or V ∝(1/P)

Options 4 and 5, if they are properly written.

Part B

At constant temperature, and according to the Boyle's law for an ideal gas,

A. What can cause a Volume increase is a corresponding decrease in pressure.

B. What can cause a Volume decrease is a corresponding increase in pressure.

C. The Volume is unchanged if the pressure of the gas is unchanged too.

Part C

The pressure when the gas occupies a volume of 5.0 L = 40 atm

Part D

The pressure when the gas occupies a volume of 4.5 L = 36 atm

Explanation:

Part A

Boyle's Law states that at constant temperature, the pressure of an ideal gas is inversely proportional to the volume occupied by the gas.

So, mathematically, Boyle's Law is given as

P ∝(1/V) or V ∝(1/P)

Part B

Inverse relationship between two quantities means that the higher the value of one of the quantities go, the lower the value of the other quantity goes and vice versa.

So, at constant temperature, and according to the Boyle's law for an ideal gas.

A. What can cause a Volume increase is a corresponding decrease in pressure.

B. What can cause a Volume decrease is a corresponding increase in pressure.

C. The Volume is unchanged if the pressure of the gas is unchanged too.

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A certain gas occupies a volume of 20 L when the applied pressure is 10 atm, find the pressure when the gas occupies a volume of 5.0 L.

According to Boyle's Law for an ideal gas,

P ∝(1/V)

P = (k/V)

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P₁V₁ = P₂V₂ = k

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V₂ = 5.0 L

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P₂ = 40 atm

Part D

If a certain gas occupies a volume of 18 L when the applied pressure is 9.0 atm , find the pressure when the gas occupies a volume of 4.5 L

P₁V₁ = P₂V₂ = k

P₁ = 9.0 atm

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V₂ = 4.5 L

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P₂ = 36 atm

Hope this Helps!!!

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