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d1i1m1o1n [39]
2 years ago
8

Which MOST CLOSELY identifies a theme in this passage?

Chemistry
1 answer:
Delicious77 [7]2 years ago
8 0

Answer:

B)

Explanation:

It is the theme of the passage.

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Add electron dots and charges as necessary to show the reaction of potassium and bromine to form an ionic compound
S_A_V [24]

Explanation: Electron dot structures are the lewis dot structures which represent the number of valence electrons around an atom in a molecule.

The electronic configuration of potassium is [Ar]4s^1

Valence electrons of potassium are 1.

The electronic configuration of Bromine is [Ar]4s^24p^5

Valence electrons of bromine are 7.

These two elements form ionic compound.

Ionic compound is defined as the compound which is formed from the complete transfer of electrons from one element to another element.

Here, one electron is released by potassium which is accepted by bromine element. In this process, Potassium becomes cation having +1 charge and Bromine become anion having (-1) charge.

The ionic equation follows:

K^++Br^-\rightarrow KBr

The electron dot structure is provided in the image below.

8 0
2 years ago
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What is the result of adding KF to an equilibrium mixture of the weak acid HF?
blagie [28]
Answer D. Follow Le Chatelier's principle.
5 0
2 years ago
4.1 kg of a plastic, used to make plastic bottles, has a carbon footprint of 6.0 kg of carbon dioxide.
Debora [2.8K]

Answer:

The carbon footprint of one plastic bottle of mass 23.5 g is 34.390 g.

Explanation:

The carbon footprint of one plastic bottle can be estimated by simple rule of three. That is:

x = \frac{23.5\,g}{4100\,g}\times 6000\,g

x = 34.390\,g

The carbon footprint of one plastic bottle of mass 23.5 g is 34.390 g.

4 0
2 years ago
If radioactive caesium was reacted with chlorine, would you expect the caesium chloride produced to be radioactive? Explain you
aniked [119]
Yes due to the radioactivity having nothing to do with the chemical equation given it will release radiation at a rate determined by it's half life.
3 0
2 years ago
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How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH4NO3 in order to prepare a 0.452 m solution?
Vanyuwa [196]

Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

Molality=\frac{n\times 1000}{W_s}

where,

n= moles of solute

Moles of NH_4NO_3=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{27.8g}{80.0g/mol}=0.348moles  

W_s = weight of the solvent in g = ?

0.452=\frac{0.348\times 1000}{W_s}

W_s=770g

Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

5 0
2 years ago
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