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2 years ago

When one atom loses an electron and another atom accepts that electron a(n) bond between the two atoms results?

1 answer:

8 0

When an element losses its electron its called a cation. When an element accepted that electron it called anion. This is called an ionic bond.

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A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti

zysi [14]

<span> Mg(OH)2(s) + 2HCl(aq) yield MgCl2(aq) + 2H2O(l)

grams HCl required = (50.6 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 63.26 grams HCl required

Since there are only 45.0 grams HCl, then HCl is the limiting reactant.

theoretical yield MgCl2 = (45.0 grams HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 58.6 grams MgCl2 </span>

7 0

2 years ago

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A white powder is known to be a mixture of magnesium oxide and aluminum oxide. 100cm3 of 2moldm-3 NaOH(aq) is just sufficient to

Effectus [21]

Answer: D.Aluminium Oxide 0.10, Magnesium Oxide 0.50

Explanation:

Number of moles of NaOH= number of moles × volume

Number of moles= 100/1000 × 2 = 0.2 moles

Since;

2 moles of NaOH yield 1 mole of Al2O3

0.2 moles of NaOH will yield 0.2 × 1/2 = 0.1 moles of Al2O3.

Number of moles of HCl= 800/1000 × 2 = 1.6 moles

If 1 mole of Al2O3 requires 6 moles of HCl

0.1 moles of Al2O3 requires 0.1 × 6 = 0.6 moles of HCl.

Number of moles of HCl left after reaction with Al2O3 = 1.6- 0.6 = 1 mole

This leftover reacts with MgO

But;

1 mole of MgO reacts with 2 moles of HCl

x moles of MgO reacts with 1 mole of HCl

Thus; x= 0.5 moles of MgO

8 0

2 years ago

How many moles of calcium chloride (CaCl2) are needed to react completely with 6.2 moles of silver nitrate (AgNO3)? 2AgNO3 + CaC

nexus9112 [7]

Here we have to choose the right option which tells the moles of CaCl₂ will react with 6.2 moles of AgNO₃ in the reaction

2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

6.2 moles of silver nitrate (AgNO₃) will react with B. 3.1 moles of calcium chloride (CaCl₂).

From the reaction: 2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

Thus 2 moles of AgNO₃ reacts with 1 mole of CaCl₂

Henceforth, 6.2 moles of AgNO₃ reacts with $\frac{6.2}{2}$ = 3.1 moles of CaCl₂.

1 mole of CaCl₂ reacts with 2 moles of AgNO₃. Thus-

A. 2.2 moles of CaCl₂ will react with 2.2×2 = 4.4 moles of AgNO₃.

C. 6.2 moles of CaCl₂ will reacts with 6.2×2 = 12.4 moles of AgNO₃.

D. 12.4 moles of CaCl₂ will reacts with 12.4 × 2 = 24.8 moles of AgNO₃

Thus the right answer is 6.2 moles of AgNO₃ will react with 3.1 moles of CaCl₂.

6 0

2 years ago

Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.

Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

$2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}$

Converting moles of boric acid to mass:

$0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}} = 6.183 g$

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.

5 0

2 years ago

The process of joining many small molecules into larger molecules is called(1) neutralization (3) saponification(2) polymerizati

yulyashka [42]

(2) polymerization. polymerization<span> is a process of reacting monomer molecules together in a chemical reaction to form polymer chains or three-dimensional networks.</span>

8 0

2 years ago

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