What substance is used in the industrial preparation of methyl diantilis to reduce the aldehyde group of 3-ethoxy-4-hydroxybenza
ldehyde?
1 answer:
Answer:
Sodium Borohydride (NaBH₄)
Explanation:
Methyl diantilis (2-Ethoxy-4-(methoxymethyl)phenol) is a fragrance compound which smells like Vanilla. This compound is being synthesized from 3-ethoxy-4-hydroxybenzaldehyde also known as Ethyl Vanillin in two steps.
Step 1: Reduction of Aldehydic Group on Ethyl Vanillin:
The benzaldehyde derivative is treated with a mild reducing agent i.e. NaBH₄ (Sodium Borohydride). NaBH₄ is a source of Hydride (H⁻) ion and undergoes nucleophilic substitution reaction yielding 2-ethoxy-4-(hydroxymethyl)phenol.
Step 2: Etherification of 2-ethoxy-4-(hydroxymethyl)phenol:
In the second step 2-ethoxy-4-(hydroxymethyl)phenol is treated with Methanol in the presence of strong acidic polymeric resin known as Amberlyst-15-wet resulting in the formation of Methyl diantilis as shown in attached figure.
You might be interested in
<u>Answer:</u> The pH of the solution in the beginning is 1.89 and the pH of the solution after the addition of base is
<u>Explanation:</u>
- <u>For 1:</u> At the beginning
To calculate the pH of the solution, we use the equation:
We are given:
Nitric acid is a monoprotic acid and it dissociates 1 mole of hydrogen ions. So, the concentration of hydrogen ions is 0.013 M
Putting values in above equation, we get:
- <u>For 2:</u>
To calculate the number of moles, we use the equation:
- <u>For nitric acid:</u>
Molarity of nitric acid solution = 0.013 M
Volume of solution = 15 mL
Putting values in above equation, we get:
- <u>For methylamine:</u>
Molarity of methylamine solution = 0.017 M
Volume of solution = 10 mL
Putting values in above equation, we get:
- The chemical equation for the reaction of nitric acid and methylamine follows:
As, the mole ratio of nitric acid and methyl amine is 1 : 1. So, the limiting reagent will be the reactant whose number of moles are less, which is methyl amine.
By Stoichiometry of the reaction:
1 mole of methyl amine produces 1 mole of
So, of methyl amine will produce =
To calculate the of base, we use the equation:
where,
= base dissociation constant =
Putting values in above equation, we get:
- To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:
We are given:
Putting values in above equation, we get:
To calculate pH of the solution, we use the equation:
Hence, the pH of the solution is 4.59