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1 year ago

Determine the percent composition by mass of a 100g salt solution which contains 20g salt

Chemistry

2 answers:

prisoha [69]1 year ago

8 0

Answer:

Mass of solution=100g

mass of salt=20g

so; mass of solute=80g

percentage composition =(mass of salt/total

mass) ×100

= \frac{20}{100} \times 100 \\ = 20\%

glad to help you

hope it helps

lara [203]1 year ago

8 0

The percent composition by mass of a 100g salt solution which contains 20g salt is $\bold{16.6\%}$

Solution:

Percent composition is calculated as, weight of the solute divided by amount of solute added to 100 g is solution multiplied by 100.

$\Rightarrow \frac{\text {weight of solute}(g)}{\text {weight of solute}(g)+\text {weight of solution(g)}} \times 100$

Given, 100 g of salt solution with 20 g of salt

Weight of the solute and solvent is $20 + 100 g = 120 g$

$percent composition=\frac{20}{120} \times 100=\frac{200}{12}=16.6$

$\therefore \text { percent composition } =16.6 \%$

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The neutron capture equation is represented as,

$_Z^A\textrm{X}+_{0}^1\textrm{n}\rightarrow _{Z}^{A+1}\textrm{X}+\gamma$

(A is the atomic mass number and Z is the atomic number)

Beta emission or beta minus decay : It is a type of decay process, in which a neutrons gets converted to proton, an electron and anti-neutrino. In this the atomic mass number remains same.

The beta minus decay equation is represented as,

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0e$

(A is the atomic mass number and Z is the atomic number)

As per question, the cobalt-60 is produced by a three reaction process involving neutron capture, beta-emission, and neutron capture.

Process 1 : Neutron capture.

$_{26}^{58}\textrm{Fe}+_{0}^1\textrm{n}\rightarrow _{26}^{59}\textrm{Fe}+\gamma$

Process 2 : Beta emission.

$_{26}^{59}\textrm{Fe}\rightarrow _{27}^{59}\textrm{Co}+_{-1}^0e$

Process 3 : Neutron capture.

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