answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elodia [21]
2 years ago
8

The diagram shows the scales used for recording temperatures. The labels for the scales are missing. 3 thermometers are oriented

vertically labeled W, X, Y from left to right. The label Water Boils is connected by a dotted line to 212 degrees on W, 100 degrees on X, 373 degrees on Y. The label Water freezes is connected by a dotted line to 32 degrees on W, 0 degrees on W, 273 degrees on Y. The label Absolute Zero is connected by a dotted line to negative 460 degrees on W, negative 273 degrees on X, and 0 degrees on Y. Which labels complete the diagram? W: Fahrenheit X: Celsius Y: Kelvin W: Kelvin X: Celsius Y: Fahrenheit W: Celsius X:Fahrenheit Y: Kelvin W:Celsius X: Kelvin Y: Fahrenheit
Chemistry
2 answers:
QveST [7]2 years ago
8 0

Answer d

Explanation:

Andrews [41]2 years ago
3 0

Answer:

W:Celsius

X: Kelvin

Y: Fahrenheit

Explanation:

You might be interested in
If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct
MA_775_DIABLO [31]

Answer:

1. sp  = XY₂

2. sp²  = XY₂Z, XY₃

3. sp3³ = XY₄, XY₂Z₂, XY₃Z

4. sp³d  = XY₅, XY₂Z₃, XY₃Z₂, XY₄Z

5. sp³d² = XY₆, XY₄Z₂, XY₅Z

Explanation:

this is quite dicey, so it should be looked into carefully.

we would classify each of the abbreviation according to their  hybridization and it electron domain.

⇒ sp hybridization = XY₂

in this, we can see that the central atom X is bonded to two outer atoms Y.

this makes the no of hybrid orbitals and the no of sigma bonds both 2.

electron domain = 2.

⇒ sp² hybridization = XY₂Z, XY₃

Here we can see the central atom X bonded with three outer atoms Y in XY₂Z and in XY₃. For XY₂Z molecule, the no of sigma bonds is 2 and the no of hybrid orbitals is 3. While for XY₃ molecule, the no of sigma bonds is 3 while the no of hybrid orbital is 3.

electron domain = 3.

⇒ sp³ hybridization = XY₄, XY₂Z₂, XY₃Z

for XY₄ molecule, the central atom X is bonded with four outer atoms Y. It has 4 numbers of both the sigma and orbital atoms.

In XY₂Z₂, the central atom X is bonded to 2 outer atoms Y, and has 2 lone pairs Z. From this, the no of hybrid orbitals is 4 and the no of sigma bonds is 2, with 2 lone pairs causing the sp³ hybridization.

⇒ sp³d hybridization = XY₅, XY₂Z₃, XY₃Z₂, XY₄Z

for all the molecules listed above, the sum of both the lone pairs and the outer atoms both give a total of 5, hence have the sp³d structure, viz;

XY₂Z₃:

total electron domain = 2+3 = 5  

XY₃Z₂:

total electron domain = 2+3 = 5

XY₄Z:

total electron domain = 1+4 = 5

⇒ sp³d² hybridization = XY₆, XY₄Z₂, XY₅Z

Same thing goes for the above molecule, where the sum of both the outer atoms and the lone pairs gives a total of 6 as can be seen in the example below.

XY4Z2:

total electron domain = 2+4 = 6

cheers, i hope this helps.

5 0
2 years ago
A student heats a sample of Copper (II) sulfate in a crucible and records the data shown in the table. What is the complete form
liberstina [14]

Explanation:

Copper (II) sulfate is usually present as a hydrous state, which is of the form CuSO4 * nH2O, where n is a whole number.

Mass of sample (CuSO4 * nH2O)

= 152.00g - 128.10g = 23.90g.

Mass of water loss during heating

= 152.00g - 147.60g = 4.40g.

Molar mass of H2O = 18g/mol

Moles of H2O in sample

= 4.40g / (18g/mol) = 0.244mol.

Mass of anhydrous sample (CuSO4)

= 23.90g - 4.40g = 19.50g

Molar mass of CuSO4 = 159.61g/mol

Moles of CuSO4 in sample

= 19.50g / (159.61g/mol) = 0.122mol.

Since mole ratio of CuSO4 to H2O

= 0.122mol : 0.244mol = 1:2, n = 2.

Hence we have CuSO4 * 2H2O.

6 0
2 years ago
Read 2 more answers
When 1.00 g of boron is burned in o2(g) to form b2o3(s), enough heat is generated to raise the temperature of 733 g of water fro
Bas_tet [7]
<span>Answer: For this problem, you would need to know the specific heat of water, that is, the amount of energy required to raise the temperature of 1 g of water by 1 degree C. The formula is q = c X m X delta T, where q is the specific heat of water, m is the mass and delta T is the change in temperature. If we look up the specific heat of water, we find it is 4.184 J/(g X degree C). The temperature of the water went up 20 degrees. 4.184 x 713 x 20.0 = 59700 J to 3 significant digits, or 59.7 kJ. Now, that is the energy to form B2O3 from 1 gram of boron. If we want kJ/mole, we need to do a little more work. To find the number of moles of Boron contained in 1 gram, we need to know the gram atomic mass of Boron, which is 10.811. Dividing 1 gram of boron by 10.811 gives us .0925 moles of boron. Since it takes 2 moles of boron to make 1 mole B2O3, we would divide the number of moles of boron by two to get the number of moles of B2O3. .0925/2 = .0462 moles...so you would divide the energy in KJ by the number of moles to get KJ/mole. 59.7/.0462 = 1290 KJ/mole.</span>
7 0
2 years ago
Which postulate of Dalton's theory is consistent with the following observation concerning the weights of reactants and products
hram777 [196]

<u>Answer:</u> This illustrates law of conservation of mass.

<u>Explanation:</u>

Dalton's theory is based on mainly two laws which are law of conservation of mass and law of constant proportion.

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The chemical equation for the decomposition of calcium carbonate follows:

CaCO_3\rightarrow CaO+CO_2

We are given:

Mass of calcium carbonate = 100 grams

Mass of calcium oxide = 56 grams

Mass of carbon dioxide = 44 grams

Total mass on reactant side = 100  g

Total mass on product side = 56 + 44 = 100 g

As, the total mass on reactant side is equal to the total mass on product side.

Thus, this illustrates law of conservation of mass.

6 0
2 years ago
Iron (Fe) undergoes an allotropic transformation at 912°C: upon heating from a BCC (α phase) to an FCC (γ phase). Accompanying t
Alex

Answer:

false thought ia ion of neon = clarity active

Explanation:

x = 81254 \: and \: y = 91284

8 0
2 years ago
Read 2 more answers
Other questions:
  • How many moles of libr are contained in 347 g of water in a 0.175 m libr solution?
    7·1 answer
  • Calculate the heat change in calories for melting 65 g of ice at 0 ∘c.
    8·1 answer
  • Carbon dating of small bits of charcoal used in cave paintings has determined that some of the paintings are from 10000 to 30000
    14·1 answer
  • H2PO4-(aq) ⇆ H+(aq) + HPO42-( which ion plays the role of hydrogen ion donor and which one plays the hydrogen ion acceptor in BP
    14·1 answer
  • Molten gallium reacts with arsenic to form the semiconductor, gallium arsenide, GaAsGaAs, used in light emitting diodes and sola
    11·1 answer
  • You are given 100.0 ml of a 2.0 M solution of KOH. What would be the molarity of the solution if it is diluted to a volume of 10
    14·1 answer
  • Write a hypothesis about the pH level of common household solutions based on what you know about their physical and chemical pro
    8·2 answers
  • If PbI2(s) is dissolved in 1.0MNaI(aq) , is the maximum possible concentration of Pb2+(aq) in the solution greater than, less th
    13·1 answer
  • When 13.6 g of calcium chloride, CaCl2, was dissolved in 100.0 mL of water in a coffee cup calorimeter, the temperature rose fro
    7·1 answer
  • When collecting temperature as a function of time for the reaction of KOH with HCL, which time is most significant
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!