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Stella [2.4K]
2 years ago
8

jin has four colorful glass bottles on his windowsill. one is red, one is violet, one is green, and one is yellow. the light tha

t passes through which bottle has the lowest frequency? red violet green yellow

Chemistry
2 answers:
Over [174]2 years ago
4 0
The red bottle would have the lowest frequency because red light has the longest wavelengths. The light passing through the violet would have the highest frequency because its wavelengths are the shortest.
Sloan [31]2 years ago
3 0

Answer: The light passing through Red bottle will have the lowest frequency.

Explanation: Relation between wavelength and frequency follows:

\nu =\frac{c}{\lambda }

As, from the above relation, it is clear that the wavelength and frequency follows inverse relation, so the light having highest wavelength will have the lowest frequency.

From the spectra of visible region, the wavelength of Red light is maximum and hence, it will have the lowest frequency.

Therefore, the light passing through the bottle which is red in color will have the lowest frequency.

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An element with the electron configuration [xe] 6s24f145d7 would belong to which class on the periodic table?
Alinara [238K]
If the atom is neutral then, the total number of electrons is the same as the number of protons. We calculate for the total number of electrons given the compressed electron configuration,
   number of electrons of Xenon (Xe) = 54
The total number of electrons after Xenon,
   = 2 + 14 + 7 = 23

Adding up all the number of electrons, we have,
   total number of electrons = 54 + 23 = 77

The identity of this element is Iridium (Ir). This element belongs to the class of Group 9. This is the transition metal. 
8 0
2 years ago
Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if an excess of pentane (C5H12) were supplied, but only 4 moles of o
ser-zykov [4K]
Answer: 3 <span>moles of water would be produced in present case.
</span>
Reason:
Reaction involved in present case is:
<span>                            C5H12 + 8O2 </span>→<span> 5CO2 + 6H2O

In above reaction, 1 mole of C5H12 reacts with 8 moles of oxygen to give 6 moles of water.

Thus, 4 moles of oxygen will react with 0.5 mole of C5H12, to generate 3 moles of H2O.</span>
7 0
2 years ago
Read 2 more answers
(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW
Aleonysh [2.5K]

Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = <em>2.3x10⁻³M  InF₃. </em>Thus:

[In⁺³] = 2.3x10⁻³M  InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M  In⁺³

[F⁻] = 2.3x10⁻³M  InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M  In⁺³] × [7.0x10⁻³M F⁻]³ = <em>7.9x10⁻¹⁰</em>

<em></em>

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, <em>solubility is 6.31x10⁻⁶M</em>

3 0
2 years ago
A researcher suspects that the pressure gauge on a 54.3-L gas cylinder containing nitric oxide is broken. An empty gas cylinder
mixer [17]

Answer:

Number of moles nitric acid in the cylinder is 400.539g/mol.

Explanation:

From the given,

Weight of empty gas cylinder W_{1}= 90.0 lb= 40823.3 gramsWeight of full cylinder[tex]W_{2} = 116.5 lb= 52843.511 gramsThe critical temperature = 287 KThe critical pressure 54.3 LMolar mass of nitric acid = [tex]M_{NO} = 30.01 g/mol

Number of moles nitric acid = n_{NO} =?

The mass of nitric acid in the cylinder = W_{NO}=W_{2}-W_{1}

=52843.511-40823.3 =12,020.2g

Number of moles of nitric acid =

\frac{Given\,mass}{Molar\,mass}=\frac{12,020.2}{30}=400.539g/mol

Therefore, number of moles nitric acid in the cylinder is 400.539g/mol.

3 0
2 years ago
The flame produced by the burner of a gas (propane) grill is a pale blue color when enough air mixes with the propane (C3H8) to
adelina 88 [10]

Answer:

At the burner temp. and pressure, 18.85 litres of air is needed to completely combust each gram of propane

Explanation:

The combustion stoichiometry is as follows:

      C₃H₈ + 5O₂  = 4 H₂O + 3CO₂      The molecular weights (g/mol) are:

MW  44    5x32      4x18    3x44

So each gram of propane is 1/44 = 0.02272 mol propane

and will need 5 x 0.02272 = 0.1136 mol oxygen

At 0.21 mol fraction oxygen in air, 0.1136 / 0.21 = 0.54 mol air is needed to burn the propane.

At the low pressure in the burner we can use the Ideal Gas Law

PV=nRT, or V = nRT/P

P = 1.1 x 101325 Pa = 111457 Pa

T = 195°C + 273 = 468 K

R = 8.314

and we calculated n = number of moles air = 0.54 mol

So V m³ = 0.54 x 8.314 x 468 / 111457 = 0.0188 m³ = 18.85 litres air.

6 0
2 years ago
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