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barxatty [35]
2 years ago
5

Which statements describe proper use of a filter funnel? Check all that apply.

Chemistry
2 answers:
ElenaW [278]2 years ago
6 0

Answer:

B) Fold the filter paper in fourths before placing it in the funnel.

C) Pour all the liquid through the funnel.

Rashid [163]2 years ago
4 0

Fold the filter paper in fourths before placing it in the funnel.

Pour all the liquid through the funnel.

Is the correct answer...

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Which of the following is a correctly written chemical equation that demonstrates the conservation of mass?
Fantom [35]

Answer:

Option D is correct.

H₂O + CO₂      →    H₂CO₃

Explanation:

First of all we will get to know what law of conservation of mass states.

According to this law, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Example:

6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂

there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

Now we will apply this law to given chemical equations:

A) H₂ + O₂   →    H₂O

There are two hydrogen and two oxygen atoms present on left side while on right side only one oxygen and two hydrogen atoms are present so mass in not conserved. This equation not follow the law of conservation of mass.

B) Mg + HCl   →   H₂ + MgCl₂

In this equation one Mg, one H and one Cl atoms are present on left side while on right side two hydrogen, one Mg and two chlorine atoms are present. This equation also not follow the law of conservation of mass.

C) KClO₃      →     KCl + O₂

There are one K, one Cl and three O atoms are present on left side of chemical equation while on right side one K one Cl and two oxygen atoms are present. This equation also not following the law of conservation of mass.

D)  H₂O + CO₂      →    H₂CO₃

There are two hydrogen, one carbon and three oxygen atoms are present on both side of equation thus, mass remain conserved. Thus is correct option.

6 0
2 years ago
Fatty acid biosynthesis occurs through a series of reactions involving fatty acid synthase (FAS), a polypeptide multienzyme comp
Vesnalui [34]

Answer:

Explanation:

check below for the answer of What saturated fatty acid gives rise to myristoleic acid,

3 0
2 years ago
You evaporate all of the water from 100 mL of NaCl solution and obtain 11.3 grams of NaCl. What was the molarity of the NaCl sol
kicyunya [14]

Answer:

                      Molarity  =  1.93 mol.L⁻¹

Explanation:

             Molarity is the unit of concentration used to specify the amount of solute in given amount of solution. It is expressed as,

                         Molarity  =  Moles / Volume of Solution    ----- (1)

Data Given;

                  Mass  =  11.3 g

                  Volume  =  100 mL  =  0.10 L

First calculate Moles for given mass as,

                   Moles  =  Mass / M.mass

                   Moles  =  11.3 g / 58.44 g.mol⁻¹

                   Moles  =  0.1933 mol

Now, putting value of Moles and Volume in eq. 1,

                        Molarity  =  0.1933 mol ÷ 0.10 L

                        Molarity  =  1.93 mol.L⁻¹

3 0
2 years ago
Find the age t of a sample, if the total mass of carbon in the sample is mc, the activity of the sample is a, the current ratio
kkurt [141]
should be 7.57*10^3 years
4 0
2 years ago
The molar heats of fusion and sublimation of lead are 4.77 and 182.8 kj/mol, respectively. estimate the molar heat of vaporizati
Yakvenalex [24]

Answer:The molar heat of vaporization of molten lead is 178.03 kJ/mol.

Explanation:

The molar heats of fusion of lead

Pb(l)\rightarrow Pb(s),\Delta H_f=-4.77 kJ/mol...(1)

The molar heats of sublimation of lead

Pb(s)\rightarrow Pb(g),\Delta H_s=182.8 kJ/mol...(2)

Adding (1) and (2)

Pb(l)\rightarrow Pb(g),\Delta H_v=?

\Delta H_v=\Delta H_f+\Delta H_s=(-4.77) kJ/mol+182.8 kJ/mol=178.03 kJ/mol

The molar heat of vaporization of molten lead is 178.03 kJ/mol.

6 0
2 years ago
Read 2 more answers
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