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FrozenT [24]
2 years ago
11

A chemist places a 100 g cube of each of the metals listed in the table on a separate hot plate. All of the hot plates are ident

ical. Each hot plate is set on medium heat, and all of the cubes have the same initial temperature. Based on the specific heat values in the table, rank the metals in terms of how quickly they will reach the target temperature of 80°C. Use "1" to indicate the fastest and "5" to indicate the slowest.
Chemistry
2 answers:
Julli [10]2 years ago
8 0
The lower the specific heat the faster the temperaature will change.


You can learn it from the formula:


Q = m * Cs * ΔT


You can solve for ΔT


ΔT = Q / ( m * Cs)


Given the heat (Q) and m (100 g) are equal for the five samples:


 ΔT = [Q / m] / Cs. = constat / Cs


So you see the inverse relation between the change of temperatura and the specific heat.


So, the order of change of temperature is given by the specific heat: the lower the specific heat the faster the change of temperature. 


With that analysis you can calculate the order in which the cubes will reach the target temperature.
Ludmilka [50]2 years ago
5 0

The answer is

Fe: 4

Al: 5

Cu: 3

Sn: 2

Pb: 1



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You have a 16.0-oz. (473-mL) glass of lemonade with a concentration of 2.66 M. The lemonade sits out on your counter for a coupl
salantis [7]

<u>Answer:</u> The new concentration of lemonade is 3.90 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

Molarity of lemonade solution = 2.66 M

Volume of solution = 473 mL

Putting values in equation 1, we get:

2.66M=\frac{\text{Moles of lemonade}\times 1000}{473}\\\\\text{Moles of lemonade}=\frac{2.66\times 473}{1000}=1.26mol

Now, calculating the new concentration of lemonade by using equation 1:

Moles of lemonade = 1.26 moles

Volume of solution = (473 - 150) mL = 323 mL

Putting values in equation 1, we get:

\text{New concentration of lemonade}=\frac{1.26\times 1000}{323}\\\\\text{New concentration of lemonade}=3.90M

Hence, the new concentration of lemonade is 3.90 M

7 0
2 years ago
In the reaction N2 + 3H2 ⇌ 2NH3, an experiment finds equilibrium concentrations of [N2] = 0.1 M, [H2] = 0.05 M, and [NH3] = 0.00
jasenka [17]
  The   equilibrium  constant  Kc   for  this  reaction    is  calculated  as  follows

from  the  equation   N2  + 3H2 =2 NH3

   qc =   (NH3)2/{(N2)(H2)^3}


Qc   is  therefore  = ( 0.001)2  /{(0.1) (0.05)^3}  = 0.08
3 0
2 years ago
Read 2 more answers
When 200g of AgNO3 solution mixes with 150 g of NaI solution, 2.93 g of AgI precipitates, and the temperature of the solution ri
gizmo_the_mogwai [7]

Answer:

\Delta H=1962.3J

Explanation:

Hello,

In this case, we can compute the change in the solution enthalpy by using the following formula:

\Delta H=mC\Delta T

Whereas the mass of the solution is 350 g, the specific heat capacity is 4.184 J/g °C and the change in the temperature is 1.34 °C, therefore, we obtain:

\Delta H=350g*4.184\frac{J}{g\°C} *1.34\°C\\\\\Delta H=1962.3J

It is important to notice that the mass is just 350 g that is the reacting amount and by means of the law of the conservation of mass, the total mass will remain constant, for that reason we compute the change in the enthalpy as shown above, which is positive due to the temperature raise.

Best regards.

8 0
2 years ago
You are studying a large tropical reptile that has a high and relatively stable body temperature. How would you determine whethe
Vesnalui [34]

Explanation:

Endothermic animals are also known as warm-blooded, they have the capacity to regulate their body temperature independent of the environment. They have mechanisms to compensate if heat loss exceeds heat generation (shivers) Or if heat generation exceeds the heat loss (panting, sweating).

On the other hand, ectothermal animals are known as cold blooded organisms and depend on external sources, like sunlight, to regulate their body temperature, reptiles are ectothermals.

To determine if the animal of interest is endo or ectothermal you’ll have to consider that is a reptile, you’ll also observe that it consumes less food and finally it’ll have more difficulties to adapt to sudden temperature changes.

I hope you find this information useful and interesting! Good luck!

8 0
2 years ago
The partial pressures of CH 4, N 2, and O 2 in a sample of gas were found to be 183 mmHg, 443 mmHg, and 693 mmHg, respectively.
Natasha2012 [34]

Answer:

Mole fraction N₂ = 0.336

Explanation:

Mole fraction of a gas can be determined in order to know the partial pressure of the gas, and the total pressure, in the mixture.

Total pressure in the mixture: Sum of partial pressure from all the gases

Total pressure = 183 mmHg + 443 mmHg + 693 mmHg =1319 mmHg

Mole fraction N₂ = Partial pressure N₂ / Total pressure

443 mmHg / 1319 mmHg = 0.336

Remember that mole fraction does not carry units

8 0
2 years ago
Read 2 more answers
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