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soldier1979 [14.2K]
2 years ago
12

Use the table to identify the phase and phase changes of the elements under the given conditions. Write the name of the substanc

e, phase, or phase change.
When the temperature in a room increases from
25°C to 33°C,
______ changes from a solid
to a liquid.
In a lab, methane and nitrogen are cooled from
-170°C to -200°C. The methane freezes and the
nitrogen _____
.
When gold is heated to 2,856°C it changes from a liquid to a ____

Chemistry
2 answers:
saul85 [17]2 years ago
4 0

See attached picture of the right responses to the phase change question.

OLga [1]2 years ago
3 0

<u>Answers:</u>

1. When the temperature in a room increases from25°C to 33°C, <u>galium</u> changes from a solid to a liquid.

2. In a lab, methane and nitrogen are cooled from -170°C to -200°C. The methane freezes and the nitrogen <u>condenses</u>.

3. When gold is heated to 2,856°C it changes from a liquid to a <u>gas</u>

<u>Explanations</u>:

The melting and boiling point of the substances permit to state whether a susbstance will be solid, liquid or gas at certain conditions (temperature in this case).

Melting point: is the temperature at which a solid becomes liquid.

Boiling point is the temperature at which a liquid becomes gas.

Hence:

  • if the temperature is below the melting point, the substance is solid.
  • if the temperature is between the melting and the boiling points, the substance is liquid.
  • if the emperature is above the boiling point the substance is gas.

The names of the phase changes dealt with in this question are:

  • Condenstation: pass from gas to liquid.
  • Boiling (Vaporization): pass from liquid to gas
  • Freezing: pass from liquid to solid.
  • Melting (fusion): pass from solid to liquid

With that let us go through the three statements:

<em>1. When the temperature in a room increases from25°C to 33°C,</em>

<em>______ changes from a solid to a liquid. </em>Answer: galium.

You need to find in the table a substance whose melting point is between 25°C and 33°C.

This is Gallium, whose melting point is indicated to be 30°C, meaning that at 25°C it is solid and at 33°C it is liquid.

<em>2. In a lab, methane and nitrogen are cooled from -170°C to -200°C. The methane freezes and the nitrogen _____</em>. Answer: condenses.

Since the boling point of nitrogen is - 196°C, at  -170°C nitrogen is gas.

Since, the melting point is - 210°C, at -200°C, nitrogen is liquid.

So, nitrogen condenses when it is cooled from - 170°C to - 200°C.

<em>3. When gold is heated to 2,856°C it changes from a liquid to a ____. </em>Answer: gas.

Since, 2856°C is the boiling point of gold, it will start fo pass from liquid to gas at this temperature.

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A 0.500 g sample of C7H5N2O6 is burned in a calorimeter containing 600. g of water at 20.0∘C. If the heat capacity of the bomb c
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22.7

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ΔHC=qrxnn

We can rearrange the equation to solve for qrxn, remembering to convert the mass of sample into moles:

qrxn=ΔHrxn×n=−3374 kJ/mol×(0.500 g×1 mol213.125 g)=−7.916 kJ=−7916 J

The heat released by the reaction must be equal to the sum of the heat absorbed by the water and the calorimeter itself:

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The heat absorbed by the water can be calculated using the specific heat of water:

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The heat absorbed by the calorimeter can be calculated from the heat capacity of the calorimeter:

qbomb=CΔT

Combine both equations into the first equation and substitute the known values, with ΔT=Tfinal−20.0∘C:

−7916 J=−[(4.184 Jg ∘C)(600. g)(Tfinal–20.0∘C)+(420. J∘C)(Tfinal–20.0∘C)]

Distribute the terms of each multiplication and simplify:

−7916 J=−[(2510.4 J∘C×Tfinal)–(2510.4 J∘C×20.0∘C)+(420. J∘C×Tfinal)–(420. J∘C×20.0∘C)]=−[(2510.4 J∘C×Tfinal)–50208 J+(420. J∘C×Tfinal)–8400 J]

Add the like terms and simplify:

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Finally, solve for Tfinal:

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