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Sati [7]
2 years ago
7

In some chemical reactions, electrons are transferred from one substance to another, but there is no net gain or loss of electro

ns during the reaction. These reactions involve the oxidation, or loss of electrons, of one substance, and the reduction, or gain of electrons, of another. This type of reaction is called a redox reaction. In neutral atoms, such as A and X, the number of protons equals the number of electrons. When atom A loses an electron, the positive charge of the nucleus becomes greater than the negative charge of the electrons, and the resulting ion has a net positive charge, forming a cation. In a reaction, the electron must be taken up by another atom, X , which results in more electrons than protons and a net negative charge on the atom, forming an anion. Mnemonic devices can help in remembering the definitions of oxidation and reduction. Two common mnemonic devices are LEO (Losing Electrons: Oxidation) says GER (Gaining Electrons: Reduction), and OIL (Oxidation Is Losing) RIG (Reduction Is Gaining). Identify the equations that show the oxidation of neutral atom A and the reduction of neutral a

Chemistry
1 answer:
Natali [406]2 years ago
4 0

Answer and Explanation:

The equation that depicts oxidation of neutral atom A is  shown below:

\rightarrow A^+ + e^-

This is because one species is losing electrons due to oxidation. The species possesses positively charged after losing electrons, the magnitude of which is proportional to the number of electrons lost.

The net charge will be equivalent on both sides of the equation, too.

Therefore all other options are not correct

The equation that depicts the decline of neutral atom X is

X + e^-  \rightarrow  X^-

It is how a cell gains electrons by reduction. The species obtains a negative charge upon possessing electrons, whose magnitude is equivalent to the amount of electrons gained.

The net charge will be equivalent on both sides of the equation, too.

Therefore all other options are not correct

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Write an equation that represents the action in water of rubidium hydroxide as an Arrhenius base.
Anika [276]

Answer:

RbOH  → Rb⁺ +  OH⁻

As the hydroxide can gives the OH⁻ in water, it is considered as an Arrhenius's base

Explanation:

Arrhenius theory states that a compound is considered a base, if the compound can generate OH⁻ ions in aqueous solution.

Our compound is the RbOH.

When it is put in water, i can dissociate like this:

RbOH  → Rb⁺ +  OH⁻

As the hydroxide can gives the OH⁻ in water, it is considered as an Arrhenius's base

3 0
1 year ago
Which of the following concerning second ionization energies is true?
Dennis_Churaev [7]

Answer:

D

Explanation:

The fact is that the both elements belong to different groups in the periodic table. Mg is in group 12 while Al is in group 13. The outer most electron configuration for Mg2+=[Ne]3s0

Al+= [Ne]3s13p0

It is evident that in Al+, the second electron is to be removed from a filled 3s subshell which is energetically unfavourable. Unlike In Mg2+ where the two electrons are removed. There is always a tendency towards a quick loss of all the valence electrons in the valence shell. It will be more difficult to remove an electron from a filled shell.

5 0
1 year ago
A mineral sample is analyzed for its cobalt and calcium content. A sample is dissolved, and then the cobalt and calcium are prec
bekas [8.4K]

Answer:

9.88

Explanation:

As higher is the Ksp, more soluble is the compound. So, Co(OH)₂ is the less soluble hydroxide.

The maximum concentration of it must be 1x10⁻⁶ M, and the reaction is:

Co(OH)₂(s) ⇄ Co⁺²(aq) + 2OH⁻(aq)

So, [Co⁺²] = 1x10⁻⁶M

Ksp =  [Co⁺²] *[OH⁻]²

[OH⁻]² = 5.9x10⁻¹⁵/1x10⁻⁶

[OH⁻] = √(5.9x10⁻⁹)

[OH⁻] = 7.6811x10⁻⁵

pOH = -log[OH⁻]

pOH = -log(7.6811x10⁻⁵)

pOH = 4.11

Knowing that pH + pOH = 14

pH = 14 - 4.11

pH = 9.88

7 0
1 year ago
Read 2 more answers
Which compound would be expected to show intense IR absorption at 2710 and 1705 cm-1? (Ph = phenyl group)
Serhud [2]

Answer:

B. PhCHO

Explanation:

Every organic group shows a characteristic IR absorption at certain wavelength . With the help of these absorption spectra we can identify the group present on organic molecules .

The wave number of 2710 cm⁻¹ is absorbed by aldehyde bond stretching .

The wave number of 1705 cm⁻¹ is shown by conjugated aldehyde . So the most likely compound among given compounds is PhCHO .

7 0
2 years ago
Use the following half-reactions to design a voltaic cell: Sn4+(aq) + 2 e− → Sn2+(aq) Eo = 0.15 V Ag+(aq) + e−→ Ag(s) Eo = 0.80
AVprozaik [17]

Answer:

E° = 0.65 V

Explanation:

Let's consider the following reductions and their respective standard reduction potentials.

Sn⁴⁺(aq) + 2 e⁻ → Sn²⁺(aq) E°red = 0.15 V

Ag⁺(aq) + e⁻ → Ag(s) E°red = 0.80 V

The reaction with the highest reduction potential will occur as a reduction while the other will occur as an oxidation. The corresponding half-reactions are:

Reduction (cathode): Ag⁺(aq) + e⁻ → Ag(s) E°red = 0.80 V

Oxidation (anode): Sn²⁺(aq) → Sn⁴⁺(aq) + 2 e⁻ E°red = 0.15 V

The overall cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an = 0.80 V - 0.15 V = 0.65 V

4 0
2 years ago
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