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Sati [7]
2 years ago
7

In some chemical reactions, electrons are transferred from one substance to another, but there is no net gain or loss of electro

ns during the reaction. These reactions involve the oxidation, or loss of electrons, of one substance, and the reduction, or gain of electrons, of another. This type of reaction is called a redox reaction. In neutral atoms, such as A and X, the number of protons equals the number of electrons. When atom A loses an electron, the positive charge of the nucleus becomes greater than the negative charge of the electrons, and the resulting ion has a net positive charge, forming a cation. In a reaction, the electron must be taken up by another atom, X , which results in more electrons than protons and a net negative charge on the atom, forming an anion. Mnemonic devices can help in remembering the definitions of oxidation and reduction. Two common mnemonic devices are LEO (Losing Electrons: Oxidation) says GER (Gaining Electrons: Reduction), and OIL (Oxidation Is Losing) RIG (Reduction Is Gaining). Identify the equations that show the oxidation of neutral atom A and the reduction of neutral a

Chemistry
1 answer:
Natali [406]2 years ago
4 0

Answer and Explanation:

The equation that depicts oxidation of neutral atom A is  shown below:

\rightarrow A^+ + e^-

This is because one species is losing electrons due to oxidation. The species possesses positively charged after losing electrons, the magnitude of which is proportional to the number of electrons lost.

The net charge will be equivalent on both sides of the equation, too.

Therefore all other options are not correct

The equation that depicts the decline of neutral atom X is

X + e^-  \rightarrow  X^-

It is how a cell gains electrons by reduction. The species obtains a negative charge upon possessing electrons, whose magnitude is equivalent to the amount of electrons gained.

The net charge will be equivalent on both sides of the equation, too.

Therefore all other options are not correct

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If water’s density is 1.0 g/mL, then would the perfume be more or less dense than water? Would the perfume float on top or sink
Alex17521 [72]

Answer:

usually the perfumes are made of aromatic hydrocarbons invloving

cetone, ethanol, benzaldehyde, formaldehyde, limonene, methylene chloride, camphor, ethyl acetate, linalool and benzyl alcohol. which have density lower than the water hence they will float on the top of the water.

Hope this helps you

Explanation:

5 0
2 years ago
Explain why c6h5ch2ch2br is not formed during the radical bromination of c6h5ch2ch3. select the single best answer.
gtnhenbr [62]
Hi!

The radical bromination reaction of C₆H₅CH₂CH₃ is performed through a mechanism in which radical reactions are involved. This compound is an alkylbenzene compound, and the carbon that is more reactive towards radical bromination is the carbon bonded to the aromatic ring because in the reaction mechanism the intermediaries are stabilized by resonance in the aromatic ring. 

A terminal substitution will not occur because substitution there will not be stabilized by resonance. The compound that will be formed in this reaction would be:

C₆H₅CH₂CH₃ + Br₂ → C₆H₅CH₂(Br)CH₃ + HBr
7 0
2 years ago
How many moles of lead (ii) chromate are in 51 grams of this substance? answer in units of mol?
maria [59]

Mass of lead (II) chromate is 51 g. The molecular formula is PbCrO_{4} and its molar mass is 323.2 g/mol

Number of moles can be calculated using the following formula:

n=\frac{m}{M}

Here, m is mass and M is molar mass.

Putting the values,

n=\frac{(51 g}{323.1937 g/mol}=0.1578 mol

Therefore, number of moles of lead (II) chromate will be 0.1578 mol.

5 0
1 year ago
Imagine if during the cathode ray experiment, the size of the particles of the ray was the same as the size of the atom forming
Yakvenalex [24]

Answer:

This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.

Explanation:

Experiment using the gas discharge tube by J.J Thomson led to the discovery of cathode rays which are now known as electrons.

Primarily, Thomson's experiment led to the discovery of cathode rays, electrons, as subatomic particles.

If the size of the atoms observed at the cathode is the same as that of the rays,we can conclude that the particles of the rays are the simplest form of matter we can have. This would suggest that the atom is indeed the smallest indivisible particle of a matter according to Dalton.

7 0
2 years ago
Read 2 more answers
During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.
Brrunno [24]

Answer: 19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.

0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2

3 0
1 year ago
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