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blondinia [14]
2 years ago
15

Write the name of flame used In charcoal cavity test.why?

Chemistry
1 answer:
Kryger [21]2 years ago
8 0

Answer:

the reducing flame also called the carburizing flame.

Explanation:

because it gets the oxides of the unknown salts

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A wave hits a wall as shown. A brick wall with a green arrow pointing to the wall from below and right at a shallow angle. Anoth
Dominik [7]

Answer:

A wave reflection interaction (reflected by the wall)

Explanation:

In a reflection, the propagating wave is bounced off the reflecting surface because the medium of the surface prevents the propagation of the wave through it, such that wave is redirected at an angle equal to the angle of incident on the reflecting surface

Reflection takes place with the different forms of waves, such as sound wave, water waves, and light wave

The objects around us are seen with the aid of reflection of light from a light source such that the reflected light enters our eyes after being reflected on the surface of the object, and the object is seen.

3 0
2 years ago
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The correct answer(reported to the proper number of significant figures)to the following is
LenKa [72]
to the proper number of significant figures) to the following? (12.67+19.2)(3.99)/(1.36+ 11.366).
8 0
2 years ago
An excess of hydrogen ions in the body fluids can have disastrous results because
natita [175]

excess hydrogen ions can break chemical bonds

, can change the shape of large complex molecules, rendering them nonfunctional and can disrupt tissue function.

3 0
1 year ago
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A magnesium ion, Mg2+, with a charge of 3.2×10−19C and an oxide ion, O2−, with a charge of −3.2×10−19C, are separated by a dista
baherus [9]

Explanation:

Formula for work done is as follows.

           W = -k \frac{q_{1}q_{2}}{d}    

where,  k = proportionality constant = 8.99 \times 10^{9} Jm/C^{2}

            q_{1} = charge of Mg^{2+} = 3.2 \times 10^{-19} C

            q_{2} = charge of O_{2-} = -3.2 \times 10^{-19} C

            d = separation distance = 0.45 nm = 0.45 \times 10^{-9} m

Now, we will put the given values into the above formula and calculate work done as follows.

         W = -k \frac{q_{1}q_{2}}{d}    

           = \frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}  

           = 3.68 \times 10^{-18} J

Thus, we can conclude that work required to increase the separation of the two ions to an infinite distance is 3.68 \times 10^{-18} J.

7 0
2 years ago
Select all true statements about hybridization, of a second-row element, changing from sp2 to sp3. (max of 3 choices) a. The ato
Neko [114]

Answer:

a. The atom will go from a two-dimensional configuration to a three dimensional configuration.

d. The bond angle will increase.

f. The number of unhybridized p orbitals will decrease.

Explanation:

Sp2 is the atomic bond in which orbitals mixes with only two orbitals. These orbitals form three sp2. When two carbon atoms are overlapped they form sigma bond by overlapping of sp2 bonds. Sp3 bond is created when there is one lone molecule available for combination. When the bonding is updated from sp2 to sp3 then unhybridized orbitals will decrease causing the bond angle to increase.

8 0
2 years ago
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