answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
posledela
2 years ago
6

Question 2: Phase Changes (14 points) a. Rewrite each of the following equations for phase changes, to include the heat required

for the phase change. Use values from latent heat and specific heat constant tables when necessary. Indicate whether each phase change is endothermic or exothermic. (2 points) i. H2O(l) H2O(s) (1 point) ii. H2O(l) H2O(g) (1 point)
Chemistry
1 answer:
lilavasa [31]2 years ago
5 0

Explanation:

(i)  The equilibrium reaction equation will be as follows.

              H_{2}O(l) \rightleftharpoons  H_{2}O(s)

A reaction in which there will be absorption of heat energy is known as endothermic reaction.

A reaction in which there will be release of heat energy is known as exothermic reaction.

As liquid state of water is changing into solid state. So, it means that molecules of water came close to each other. Hence, there will be release of heat this means that reaction is exothermic in nature.

Hence, phase change from liquid to solid will be exothermic in nature.

Latent heat of fusion is defined as the amount of energy necessary to convert 1 gram of a solid into liquid state at its melting point.

So, when solid state of water changes into liquid state then it means energy is absorbed by the molecules of ice due to which they have gained kinetic energy. Hence, they moved away from each other leading to formation of liquid state of water.

Latent heat of freezing of liquid water is 334 J/g.

Specific heat of liquid water is 4.186 J/g ^{o}C

Specific heat of steam is 1.996 kJ/kg/^{o}K

Specific heat of ice is 2.1 kJ/kg/^{o}K

(ii)  The equilibrium reaction equation will be as follows.

              H_{2}O(l) \rightleftharpoons H_{2}O(g)

As liquid state of water is changing into gaseous or vapor state. So, it means molecules of liquid water has gained kinetic energy hence, they colloid more rapidly with each other.

As a result, heat will be absorbed by the liquid state of water. Hence, heat will be absorbed. Therefore, phase change from liquid to gas will be endothermic in nature.

Whereas when gaseous state of water will change into liquid state then heat will be released during this process of condensation. As a result, in that case reaction will be exothermic in nature.

You might be interested in
LOOK AT THE IMAGE ABOVE CAN SOMEONE PLEASE HELP ME AND SHOW FULL STEPS PLEASE
Tju [1.3M]

answer:

no

explanation:

cause you dumb

5 0
2 years ago
One mole of an ideal gas in a closed system, initially at 25°C and 10 bar, is first expanded adiabatically, then heated isochori
Igoryamba

Answer:

P_2=0.398bar=39800Pa

T_2=118.7K\\

Q=-3729.9J

W=-61753.24J

ΔU_T=0J

ΔH_T=0J

Explanation:

Hello,

At the first state, the molar volume is:

v_1=\frac{RT}{P_1} =\frac{8.314\frac{Pa*m^3}{molK}*298.15}{1x10^6Pa}=2.48x10^{-3}m^3

The volume in both the second and third state:

v_2=v_3=\frac{RT}{P_1} =\frac{8.314\frac{Pa*m^3}{molK}*298.15}{1x10^5Pa}=2.48x10^{-2}m^3

Now, as it is about an adiabatic process, one remembers the following relationships:

PV^\alpha =K\\TV^{\alpha-1}\\\alpha=\frac{Cp}{Cv}=\frac{7/2R}{5/2R}=1.4

- Next, for the aforesaid volumes and the first pressure, one computes the second pressure as:

P_2=\frac{P_1V_1^\alpha }{V_2^\alpha} =\frac{10bar*(2.48x10^{-3}m^3)^{1.4}}{(2.48x10^{-2}m^3)^{1.4}} =0.398bar=39800Pa

- And the temperature:

T_2=\frac{T_1V_1^{\alpha-1}}{V_2^{\alpha-1}} =\frac{298.15K*(2.48x10^{-3}m^3)^{1.4-1}}{(2.48x10^{-2}m^3)^{1.4-1}} =118.7K\\

- Q:

It is clear that the heat for the first process is 0 as it is adiabatic, but for the second one, it is computed as:

Q_2=nCv(T_2-T_1)=1mol*\frac{5}{2}(8.314\frac{J}{mol*K})*(118.7K-298.15K)=-3729.9J

Then the total heat:

Q=Q_1+Q_2=0-3729.9J=-3729.9J

- The work for the first process is:

W_1=\frac{P_2V_2-P_1V_1}{1-\alpha }=\frac{39800Pa*2.48x10^{-3}m^3-1x10^6Pa*2.48x10^{-2}m^3}{0.4} \\W_1=-61753.24J

It is clear that the second process is isochoric, so the work here is zero, thus, the total work is:

W=W_1+W_2=-61753.24J+0J=-61753.24J

- For the two processes, ΔU becomes the same value since the system returns to the initial temperature, so ΔU total is 0, thus, for each process, one's got:

U_1=nCv(T_2-T_1)=1mol*\frac{5}{2}(8.314\frac{J}{mol*K})*(118.7K-298.15K)=-3729.9J\\U_2=nCv(T_3-T_2)=1mol*\frac{5}{2}(8.314\frac{J}{mol*K})*(298.15K-118.7K)=3729.9J\\

- Finally, the total enthapy is also 0 due to same aforesaid reason, thus, each enthalpy is:

H_1=nCp(T_2-T_1)=1mol*\frac{7}{2}(8.314\frac{J}{mol*K})*(118.7K-298.15K)=-5221.86J\\H_2=nCv(T_3-T_2)=1mol*\frac{7}{2}(8.314\frac{J}{mol*K})*(298.15K-118.7K)=5221.86J\\

Best regards.

8 0
2 years ago
Approximately 220 million tires are discarded in the U.S. each year. These tires present a disposal problem because they take up
Andreas93 [3]

Answer:

2667 tires are needed to meet the demand of ten homes for one year.

Explanation:

According to the Second Law of Thermodynamics, only a part of generated energy when tires are burned can be utilized due to irreversibilities associated with finite temperature differences. The energy from a tire that can be transformed into electricity (E_{out}), measured in kilowatt-hours, is estimated by definition of efficiency:

E_{out} = \eta \cdot E_{in}

Where:

\eta - Efficiency, dimensionless.

E_{in} - Energy liberated by burning, measured in kilowatt-hours.

Given that \eta = 0.5 and E_{in} = 75\,kWh, the amount of energy per year generated by a tire is:

E_{out} = 0.5\cdot (75\,kWh)

E_{out} = 37.5\,kWh

Now, the amount of tires needed to meet the demand of then homes for one year is:

n = \frac{(10\,homes)\cdot \left(10000\,\frac{kWh}{home} \right)}{37.5\,\frac{kWh}{tire} }

n = 2666.667\,tires

2667 tires are needed to meet the demand of ten homes for one year.

8 0
2 years ago
Synthesis of disubstituted benzenes involves two steps, each introducing one of the functional groups. For the synthesis of p-ch
Setler79 [48]

Answer:

The synthesis of p-chlorobenzenesulfonic acid with the reagents for each step and the structure of the monosubstituted intermediate compound is shown in the drawing below.

Explanation:

Benzenesulfonic acid is obtained from the sulfonation of benzene, using concentrated smoking sulfuric acid.

Chlorination of benzenesulfonic acid with chlorine without catalyst requires a polar solvent, such as acetic acid to obtain the selectivity in the position for and the ortho derivative in a low proportion.

7 0
2 years ago
The small intestine shown below contains lymphatic vessels but no capillaries. Which nutrient will be absorbed by this small int
Bumek [7]

Answer:

fatty acids

Explanation:

8 0
2 years ago
Read 2 more answers
Other questions:
  • What changes if the degree (amount) of intermolecular bonds of a substance are changed?
    7·2 answers
  • How many grams are in 2.5 pound sample
    14·1 answer
  • A mysterious white powder could be powdered sugar (C12H22O11), cocaine (C17H21NO4), codeine (C18H21NO3), norfenefrine (C8H11NO2)
    12·2 answers
  • Consider a triprotic acid like phosphoric acid or citric acid. which expression correctly describes the relative magnitudes of t
    11·1 answer
  • Which part of experimental design is most important to a scientist when replicating an experiment? Having exactly the same data
    11·2 answers
  • A generic element, Z, has two isotopes, 45Z and 47Z, and an average atomic mass of 45.36 amu. The natural abundances of the two
    8·1 answer
  • If PbI2(s) is dissolved in 1.0MNaI(aq) , is the maximum possible concentration of Pb2+(aq) in the solution greater than, less th
    13·1 answer
  • 5. Rubbing alcohol is a commonly used disinfectant and has a cooling effect when applied to the skin. The active ingredient in r
    12·1 answer
  • The structures of TeF4 and TeCl4 in the gas phase have been studied by electron diffraction (S. A. Shlykov, N. I. Giricheva, A.
    15·1 answer
  • balance the following reaction using LCM method by showing each steps Pb (N3)2 + Cr(MnO4)2  Cr2O3 + MnO2 + Pb3O4+ NO​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!