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mamaluj [8]
2 years ago
12

__________ is one of many factors that can determine the rate of alcohol absorption.

Chemistry
1 answer:
12345 [234]2 years ago
6 0
Food consumption affects the rate of alcohol absorption in the bloodstream.

Explanation:

The type of food and therefore the amount<span> of food that </span>is a gift<span> in your </span>epithelial duct once you<span> consume alcohol have </span>the foremost<span> direct </span>impact<span> on </span>the speed<span> of alcohol absorption.</span>

<span>When you consume alcohol on </span>the associate<span> empty </span>abdomen<span>, the alcohol </span>is sometimes<span> absorbed </span>within the<span> blood </span>among<span> fifteen minutes to two-and-a-half hours. If </span>you have got<span> a moderate </span>quantity<span> of food in your </span>abdomen once you<span> drink, that speed slows </span>all the way down to<span> thirty minutes </span>to a few<span> hours. If you’re drinking on a full </span>abdomen<span>, alcohol absorption ranges from </span>3 to 6<span> hours.</span>
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Zinc has a specific heat capacity of 0.390 J/goC. What is its molar heat capacity? Enter your answer numerically to three signif
ch4aika [34]

Answer:

The answer to your questions is  Cm = 25.5 J/mol°C  

Explanation:

Data

Heat capacity = 0.390 J/g°C

Molar heat capacity = ?

Process

1.- Look for the atomic number of Zinc

     Z = 65.4 g/mol

2.- Convert heat capacity to molar heat capacity

       (0.390 J/g°C)(65.4 g/mol)

- Simplify and result

   Cm = 25.5 J/mol°C  

3 0
2 years ago
How many grams of methane gas (CH4) occupy a volume of 11.2 liters at STP
Vsevolod [243]
11.2L/22.4L (STP value) x 1 mol of CH4 x 16.04 g of CH4 = 8.2 g
7 0
2 years ago
Read 2 more answers
What pressure (in atm) would be exerted by 76 g of fluorine gas (f2) in a 1.50 liter vessel at -37oc? (a) 26 atm(b) 4.1 atm(c) 1
nirvana33 [79]

<span>Let's assume that the F</span>₂ gas has ideal gas behavior. 

<span> Then we can use ideal gas formula,
PV = nRT

Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span>⁻¹ K⁻<span>¹) and T is temperature in Kelvin.</span>


Moles = mass / molar mass


Molar mass of F₂ = 38 g/mol

Mass of F₂  = 76 g

Hence, moles of F₂ = 76 g / 38 g/mol = 2 mol

<span>
P = ?
V = 1.5 L = 1.5 x 10</span>⁻³ m³

n = 2 mol

R = 8.314 J mol⁻¹ K⁻<span>¹
T = -37 °C = 236 K

By substitution,
</span>

P x 1.5 x 10⁻³ m³ = 2 mol x 8.314 J mol⁻¹ K⁻¹ x 236 K

                         p = 2616138.67 Pa

                         p = 25.8 atm = 26 atm


Hence, the pressure of the gas is 26 atm.

Answer is "a".

<span>

</span>
5 0
2 years ago
Radioactive elements decay at a know rate known as half-life. Choose all of the correct statements concerning half-life. Carbon-
9966 [12]

Explanation:

Half life is simply the amount of time it takes for half of a substance to decompose.

Options;

- Carbon-14 has a half-life of 5,730 years. A 30 gram sample will be 10 grams after 5,730 years. This is incorrect. After 5730 years, 15g of the sample ought to remain.

- Nickel-59 has a half-life of 76,000 years. A sample would go through 3 half-lives in 228,000 years. This is correct. 3 * 76000 = 228,000

- Hafnium-182 has a half-life of 9 million years. A 38 gram sample would be 4.75 grams in 27 million years. This is incorrect. Mass after 3 half lives (27/9) = 9.5 (38 / 2 / 2)

- Iron-60 has a half-life of 1.5 million years. In 6 million years a 40 gram sample would be reduced to 10 grams. This is incorrect. Mass after 4 half lives (6 / 1.5) = 2.5 gram (40 / 2 / 2 /2 / 2)

- Lead-202 has a half-life of 52,500 years. The original sample must have been 120 grams if you have a 60 gram sample after 105,000 years. This is incorrect. Original sampe = 240 gram. So after 2 half lives (105,000/52500), mass left = 60 (240 / 2 /2)

6 0
2 years ago
Read 2 more answers
A hypothetical AX type of ceramic material is known to have a density of 3.55 g/cm3 and a unit cell of cubic symmetry with a cel
postnew [5]

Explanation:

For AX type ceramic material, the number of formula per unit cells is as follows.

         \rho = \frac{n'(A_{c} + A_{A})}{V_{C}N_{A}}

or,     n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}

where,   n' = no. of formula units per cell

           A_{c} = molecular weight of cation = 90.5 g/mol

           A_{a} = molecular weight of anion = 37.3 g/mol

          V_{c} = volume of cubic cell = 3.55 g/cm^{3}

           a = edge length of unit cell = 3.9 \times 10^{-8} cm

        N_{A} = Avogadro's number = 6.023 \times 10^{23}

          \rho = density = 3.55 g/cm^{3}

Now, putting the given values into the above formula as follows.

           n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}

                      = \frac{3.55 g/cm^{3} \times (3.9 \times 10^{-8})^{3} \times 6.023 \times 10^{23}}{(90.5 + 37.3)}

                     = 0.9

                    = 1 (approx)

Therefore, we can conclude that out of the given options crystal structure of cesium chloride is possible for this material.

3 0
2 years ago
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