Question

In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] = 1.3 M. What is the equilibrium constant Kc for this reaction?

Answer 1

Answer: The equilibrium constant $K_c$ for this reaction is 0.088

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$

For the given chemical reaction:

$NO+NO_2(g)\rightarrow N_2O_3$

The expression for $K_c$ is written as:

$K_c=\frac{[N_2O_3]}{[NO_2][NO]}$

$K_c=\frac{(1.3)}{(3.9)\times (3.8)}$

$K_c=0.088$

The equilibrium constant $K_c$ for this reaction is 0.088