If 36.0 g of NaOH (MM = 40.00 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the
1 answer:
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I first converted the given grams of the reactants into moles, and then divided the moles by the coefficients in front of each of the reactant. The result with the smallest value will be the limiting reactant, and the value of CuO was the smallest, so it's the limiting reactant.
After figuring out which reactant is the limiting one, I took their given grams and converted it into moles, the divided it by the ratio of N2 to CuO (it's in the equation) to obtain the moles of N2, and then multiply it with the molar mass of N2 to get its mass in grams.
The Lewis structure of Diimide (N₂H₂) is shown below.
In this molecule two Nitrogen atoms attached to each other through a double bond are further attached to one one Hydrogen atom. Also, each Nitrogen atom carries one non-binding electron pair (Lone Pair) (Highlighted RED).
Result:
Option-C (<span>each nitrogen has one nonbinding electron pair) is the correct answer.</span>
In this molecule two Nitrogen atoms attached to each other through a double bond are further attached to one one Hydrogen atom. Also, each Nitrogen atom carries one non-binding electron pair (Lone Pair) (Highlighted RED).
Result:
Option-C (<span>each nitrogen has one nonbinding electron pair) is the correct answer.</span>
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Next, we identify the limiting reactant by computing the moles of magnesium oxide yielded by 3.86 g of magnesium and 155 mL of oxygen at the given conditions via their 2:1:2 mole ratios and the ideal gas equation:
It means that the limiting reactant is the oxygen as it yields the smallest amount of magnesium oxide. Next, we compute the mass of magnesium consumed the oxygen only:
Thus, the mass in excess is:
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