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2 years ago

Which number represents runoff on the hydrologic cycle diagram?

Chemistry

2 answers:

Olegator [25]2 years ago

8 0

Explanation:

The number 4 in the hydrologic cycle depicts surface runoff.

The hydrologic cycle depicts the cyclic movement of water between different earth components.

It shows water in all its phases.

From the attached image, runoff is depicted 4.
Runoff is water that moves on the surface after precipitation.
Number 1 is evaporation where water changes to vapor.
Number 2 is condensation where the vapor cools back to liquid.
Number 3 is precipitation where the liquid water is forced down under gravity.
On the surface, the water runs as runoff.

learn more:

Biogeochemical cycle brainly.com/question/3509510

#learnwithBrainly

kirill [66]2 years ago

4 0

Hi! your answer should be 4

I took the test hope this helps :)

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Draw the product(s) obtained when benzoquinone is treated with excess butadiene. using wedges and dashes, indicate the stereoche

Alex17521 [72]

Answer:

The structure can be found on the attached documents

Explanation:

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1 year ago

Which compound lauric acid or sucrose is more soluble in water justify your answers in terms of intermolecular forces?

iogann1982 [59]

Answer is: sucrose is more soluble in water.
Solubility of sucrose (C₁₂H₂₂O₁₁) is about 2000 g in one liter of water (25°C) and solubility of lauric acid (C₁₂H₂₄O₂) is approximately 0,06 g approximately.
That is because sucrose has stronger intermolecular forces (hydrogen bond), Sucrose has more oxygen, more oxygen means more intermolecular bond with hydrogen.

3 0

1 year ago

When 1.57 mol o2 reacts with h2 to form h2o, how many moles of h2 are consumed in the process?

natita [175]

Here we have to get the moles of hydrogen (H₂) consumed to form water (H₂O) from 1.57 moles of oxygen (O₂)

In this process 3.14 moles of H₂ will be consumed.

The balanced reaction between oxygen (O₂) and hydrogen (H₂); both of which are in gaseous state to form water, which is liquid in nature can be written as-

2H₂ (g) + O₂ (g) = 2H₂O (l).

Thus form the equation we can see that 1 mole of oxygen reacts with 2 moles of hydrogen to form 2 moles of water.

So, 1.57 moles of oxygen will consume (1.57×2) = 3.14 moles of hydrogen to form water.

3 0

2 years ago

Read 2 more answers

Iron (Fe) undergoes an allotropic transformation at 912°C: upon heating from a BCC (α phase) to an FCC (γ phase). Accompanying t

-Dominant- [34]

Answer:

The description including its given problem is outlined in the following section on the clarification.

Explanation:

The given values are:

RBCC = 0.12584 nm

RFCC = 0.12894 nm

The unit cell edge length (ABCC) as well as the atomic radius (RBcc) respectively connected as measures for BCC (α-phase) structure:

√3 ABCC = 4RBCC

⇒ ABCC = $\frac{4RBCC}{\sqrt{3} }$

⇒ = $\frac{4\times 0.12584}{\sqrt{3}}$

⇒ = $0.29062 \ nm$

Likewise AFCC as well as RFCC are interconnected by

√2AFCC = 4RFCC

⇒ AFCC = $\frac{4RFCC}{\sqrt{2}}$

⇒ = $\frac{4\times 0.12894}{\sqrt{2} }$

⇒ = $0.36470 \ nm$

Now,

The Change in Percent Volume,

= $\frac{V \ final-V \ initial}{V \ initial}\times 100 \ percent$

= $\frac{(VFCC)unit \ cell-(VBCC)unit \ cell}{(VBCC)unit \ cell}\times 100 \ percent$

= $\frac{(aFCC)^3-(aBCC)^3}{(aBCC)^3}\times 100 \ percent$

= $\frac{(0.36470)^3-(0.29062)^3}{(0.29062)^3}\times 100 \ percent$

= $97.62 \ percent (approximately)$

Note: percent = %

7 0

2 years ago

A compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated

n200080 [17]

Answer:

The empiricial formula of the compound is BaO2

Explanation:

Step 1: Data given

Barium and oxygen dissolved in hydrochloric acid gives a solution of barium ion. This was precipitated with an excess of potassium chromate and gives barium chromate.

The original compound weighs 1.345g and gives 2.012g of BaCrO4

Step 2: Calculate moles of BaCrO4

moles of BaCrO4 = mass of BaCrO4 / molar mass of BaCrO4

moles of BaCrO4 = 2.012g / 253.37 g/mol = 0.0079 moles

Step 3: Calculate moles of Ba

Mole ratio for Ba and BaCrO4 is 1:1 so this means for 0.0079 moles of BaCrO4, there are 0.0079 moles of Ba-ion

Step 4: Calculate mass of Ba-ion

Mass of Ba = Moles of Ba / Molar mass of Ba

Mass of Ba = 0.0079 moles * 137.327g/mole = 1.085 g Ba

Step 5: Mass of oxygen

Since the original compound has barium and oxygen, the mass of oxygen is the difference between the original mass and the mass of the Ba-ion

1.345 g - (1.085 g Ba) = 0.260 g O

Step 6: Calculate moles of Oxygen

moles oxygen = mass of oxygen / Molar mass of oxygen

moles oxygen = 0.260g / 16g/mole = 0.01625 moles O

We divide the number of moles by the smallest number of moles which is 0.0079

Ba → 0.0079/0.0079 = 1

O → 0.01625 / 0.0079 ≈ 2

(1.091 g Ba) / (137.3277 g Ba/mol) = 0.00794450 mol Ba

(0.254 g O) / (15.99943 g O/mol) = 0.0158756 mol O

This gives us the empirical formula of BaO2 for this compound

7 0

2 years ago