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prohojiy [21]
2 years ago
5

Which number represents runoff on the hydrologic cycle diagram?

Chemistry
2 answers:
Olegator [25]2 years ago
8 0

4

Explanation:

The number 4 in the hydrologic cycle depicts surface runoff.

The hydrologic cycle depicts the cyclic movement of water between different earth components.

It shows water in all its phases.

  • From the attached image, runoff is depicted 4.
  • Runoff is water that moves on the surface after precipitation.
  • Number 1 is evaporation where water changes to vapor.
  • Number 2 is condensation where the vapor cools back to liquid.
  • Number 3 is precipitation where the liquid water is forced down under gravity.
  • On the surface, the water runs as runoff.

learn more:

Biogeochemical cycle brainly.com/question/3509510

#learnwithBrainly

kirill [66]2 years ago
4 0

Hi! <u>your answer should be 4</u>

I took the test hope this helps :)

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Calculate the number of oxygen atoms in 2.00 moles of Mn2O7
cluponka [151]
First you should know that there is seven oxygen atoms in one Mn2O7
So 
2.00 moles of Mn2O7 contain 14.00 moles of oxygen...
Then you multiply this no. with Avagadro no....
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Number of moles= no. of particles/avagadro's no..
14.00×6.02×10²³=84.28 atoms of oxygen... 
7 0
2 years ago
. Calculate the mass of O2 produced if 3.450 g potassium chlorate is completely decomposed by heating in presence of a catalyst
Vesnalui [34]
 <span>2 KClO3(s) → 3 O2(g) + 2 KCl(s) 

</span><span>Note: MnO2 (Manganese Dioxide) is not part of the reaction. A catalyst lowers the activation energy and increases both forward and reverse reactions at equal rates. 
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molar mass of KClO3 = 122.5
Moles of KClO3 =  3.45 / 122.55 = 0.028

Moles of O2 produce = \frac{3}{2} \times 0.028

= 0.042 moles

molar mass of O2 = 32

so, mass of O2 = 32 x 0.042  = 1.35 g



5 0
2 years ago
The plastic straws were placed under the wooden block to
Sveta_85 [38]
Answer: C
I hope this helped you
6 0
2 years ago
One of the most important chemical reactions is the Haber process, in which N2 and H2 are converted to ammonia which is used in
Lera25 [3.4K]

Answer:

c) 22

Explanation:

Let's consider the following balanced equation.

N₂(g) + 3 H₂(g) ----> 2 NH₃(l)

According to the balanced equation, 34.0 g of NH₃ are produced by 1 mol of N₂. For 170 g of NH₃:

170gNH_{3}.\frac{1molN_{2}}{34.0gNH_{3}} =5.00molN_{2}

According to the balanced equation, 34.0 g of NH₃ are produced by 3 moles of H₂. For 170 g of NH₃:

170gNH_{3}.\frac{3molH_{2}}{34.0gNH_{3}} =15.0molH_{2}

The total gaseous moles before the reaction were 5.00 mol + 15.0 mol = 20.0 mol.

We can calculate the pressure (P) using the ideal gas equation.

P.V = n.R.T

where

V is the volume (50.0 L)

n is the number of moles (20.0 mol)

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (400.0 + 273.15 = 673.2K)

P=\frac{n.R.T}{V} =\frac{20.0mol\times (0.08206atm.L/mol.K)\times 673.2K ) }{50.0L} =22.0atm

7 0
2 years ago
How many moles of sodium bicarbonate is needed to neutralize 0.8 ml of sulphuric acid?
svet-max [94.6K]

Answer:

n NaHCO3 = 9.6 E-3 mol

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balanced reaction:

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⇒ mol NaHCO3 = 4.8 E-3 mol H2SO4 * ( 2 mol NaHCO3 / mol H2SO4 )

⇒ ,mol NaHCO3 = 9.6 E-3 mol

So 9.6 E-3 mol NaHCO3,  are the minimun moles necessary to neutralize the acid.

6 0
2 years ago
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