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Ulleksa [173]
2 years ago
14

A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu

dent use to make the sample? Use M subscript i V subscript i equals M subscript f V subscript f.. 3.70 mL 16.7 mL 30.0 mL 83.3 mL
Chemistry
2 answers:
Pani-rosa [81]2 years ago
8 0

83.3 mL

Explanation:

M_{i} = 3M

V_{i} = 50mL

M_{f} = 1.80M

Unknown:

V_{f} = ?

Solution:

To solve this problem we must understand that the initial and final number of moles remains the same.

  Number of moles = molarity x volume

Molarity x volume of initial solution = Molarity x volume of final solution

 Therefore:

   M_{i}  x  V_{i}     = M_{f} x   V_{f}

M is the molarity

V is the volume

i = initial state

f = final state

    input the parameters;

  3 x 50 = 1.8 x V_{f}

      V_{f} = 83.3 mL

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

forsale [732]2 years ago
3 0

Answer:

83.3

Explanation:

I’m smart

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Answer:

Option F 6 will be the answer.

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What is the molarity of an h3po4 solution if 15.0 ml is completely neutralized by 38.5 ml of 0.150m naoh?
just olya [345]
The molarity  of H3PO4   solution  if   15.0  ml  is completely    neutralized by  38.5  ml  of   0.15m naoh  is  calculated   as  follows
find  moles of  NaOH  used  =   molarity  x  volume
=  38.5  x  0.15  =    5.775  moles

write   the    reacting  equation
 3NaOH  + H3PO4  =  Na3PO4  + 3H2O

from  the  equation the  reacting   ratio  between  NaOH  to  H3Po4   which  is 3:1  the  moles  of  H3PO4    is  therefore  =  5.775/3  =  1.925  moles

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4 0
2 years ago
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Write a hypothesis for Part II of the lab, which is about the type of material an object is made of, and its ability to absorb o
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Different materials will change temperature at different rates when exposed to the same amount of thermal energy. This is because each substance has its own specific heat.

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that is the answer

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A chemist has 2.0 mol of methanol (CH3OH). The molar mass of methanol is 32.0 g/mol. What is the mass, in grams, of the sample?
rodikova [14]

Answer:

\boxed {\boxed {\sf D. \ 64 \ grams }}

Explanation:

Given the moles, we are asked to find the mass of a sample.

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\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

Multiply by the given number of moles, which is 2.0

2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

The moles of methanol will cancel each other out.

2.0 \ *\frac{32 \ g \ CH_3OH}{1 }

The denominator of 1 can be ignored.

2.0 * 32 \ g\ CH_3OH

Multiply.

64 \ g \ CH_3OH

There are 64 grams of methanol in the sample.

3 0
2 years ago
The ph of a solution that contains 0.818 m acetic acid (ka = 1.76 x 10-5) and 0.172 m sodium acetate is __________.
crimeas [40]
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Acid                    =  Acetic acid (CH₃COOH)
So,
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We are having conc. of acid and acetate but missing with pKa,
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