To solve this problem we will use the following equation:
w = (m of solute) / (m of solution)
w - percentage
It is necessary to mention here that mass of solution is a sum of the mass of solute and mass of water.
<span>w = mass CaCl2/(mass of water + mass of CaCl2)
</span>
mass of water = x
0.35 = 36 / (x + 36)
0.35 × (x + 36) = 36
0.35x + 12.6 = 36
0.35x = 23.4
x = 66.86 g of water is necessary
To determine the number of gas particles in the vessel we add all of the components of the gas. For this, we need to convert the mass to moles by the molar mass. Then, from moles to molecules by the avogadro's number.
1.50x10^-6 ( 1 / 28.01) (6.022x10^23) = 3.22x10^16 molecules CO
6.80x10^-6 ( 1 / 2.02) (6.022x10^23) = 2.03x10 18 molecules H2
Totol gas particles = 2.05x10^18 molecules
Answer:
The essence including its particular subject is outlined in the following portion mostly on clarification.
Explanation:
- The energy throughout the campfire comes from either the wood's latent chemical energy until it has been burned to steam up and launch up across the campfire. The electricity generation for something like a campfire seems to be in the context including its potential chemical energy which is contained throughout the firewood used only to inflame the situation.
- The energy output seems to be in the different types of heat energy radiating across the campfire, laser light generated off by the blaze, and perhaps a little number of electrical waves, registered throughout the firewood cracking whilst they combust throughout the blaze.
and,
chemical energy ⇒ heat energy + light energy + sound energy
SThe missing coefficient for the skeleton equation below is as follows
skeleton equation
Cr(s) + Fe(No3)2(aq) ------> Fe (s) + Cr(NO3)3 (aq)
the missing coefficient are is as follows
2 Cr(s) + 3 Fe(NO3)2 ---> 3 Fe (s) + 2 Cr(NO3)3
This is obtained by making sure all the molecules are balanced in both sides
Answer:
The mass of xenon in the compound is 2.950 grams
Explanation:
Step 1: Data given
Mass of XeF4 = 4.658 grams
Molar mass of XeF4 = 207.28 g/mol
Step 2: Calculate moles of XeF4
Moles XeF4 = mass XeF4 / molar mass XeF4
Moles XeF4 = 4.658 grams / 207.28 g/mol
Moles XeF4 = 0.02247 moles
Step 3: Calculate moles of xenon
XeF4 → Xe + 4F-
For 1 mol xenon tetrafluoride, we have 1 mol of xenon
For 0.02247 moles XeF4 we have 0.02247 moles Xe
Step 4: Calculate mass of xenon
Mass xenon = moles xenon * molar mass xenon
Mass xenon = 0.02247 moles * 131.29 g/mol
Mass xenon = 2.950 grams
The mass of xenon in the compound is 2.950 grams