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2 years ago

Is iron bromide magnetic if no why

Chemistry

2 answers:

Nataly_w [17]2 years ago

4 0

Iron bromide isn't considered magnetic because all iron compounds are not magnetic

Mila [183]2 years ago

3 0

Answer:

Yes, Iron bromide is magnetic.

Explanation:

Iron bromide is a chemical compound with chemical formula FeBr2. It is a anhydrous compound with yellow and brownish color paramagnetic solid. Iron is magnetic. So, any metal with iron will be attracted to a magnet. Some metals like copper, gold and aluminium are non-magnetic.

Not all iron is magnetic. Iron is a ferromagnetic which is attracted to the magnets like nickel and cobalt. It is non-magnetic because they have net dipole moment of zero and have partially field electron shell.

Iron bromide is magnetic because it possses the strong magnetism at 4.2 degree kelvin.

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Answer:

Salts and acids are examples of inorganic compounds called electrolytes.

Explanation:

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2 years ago

A student uses a dye to change the colour of his tee-shirt. he fills a metal bucket with water. When the bucket is heated, what

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The particles begin to vibrate faster and more.

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2 years ago

The solubility of N2 in blood can be a serious problem (the "bends") for divers breathing compressed air (78% N2 by volume) at d

OLga [1]

Answer:

The volume is 19.7 mL

Explanation:

Step 1: Given data

Pressure at sea level = 1.00 atm

Pressure at 50 ft = 2.47535 atm

kH for N2 in water at 25°C is 7.0 × 10−4 mol/L·atm

Molarity (M) = kH x P

Step 2: Calculate molarity

M at sea level:

M = 7.0*10^-4 * (1.00atm * 0.78) = 5.46*10^-4 mol/L

M at 50ft:

M = 7.0*10^-4 * (2.47535atm * 0.78) = 13.5*10^-4 mol/L

We should find the volume of N2. To find the volume whe have to find the number of moles first. This we calculate by calculating the difference between M at 50 ft and M at sea level.

13.5*10^-4 mol/L - 5.46*10^-4 mol/L = 8.04*10^-4 mol/L

Step 3: Calculate volume

P*V=nRT

with P = 1.00 atm

with V = TO BE DETERMINED

with n = 8.04*10^-4 mol/L *1L = 8.04*10^-4

with R= 0.0821 atm * L/ mol *K

with T = 25 °C = 273+25 = 298 Kelvin

To find the volume, we re-organize the formula to: V=nRT/P

V= (8.04*10^-4 mol * 0.0821 (atm*L)/(mol*K)* 298K ) / 1.00atm = 0.0197L = 19.7ml

The volume is 19.7 mL

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2 years ago