A 6.00 g sample of calcium sulfide is found to contain 3.33 g of calcium. what is the percent by mass of sulfur in the compound?
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The empirical formula of the compound : <u><em>RbO₂</em></u>
<h3>Further explanation</h3>Dulong and Petit's rule's rule, which says that the molar heat capacity, Cp, of a solid can be expressed as
Where N is the number of atoms per formula unit and R is the universal gas constant
While the value of R is:
R = 8.3144621 J / K · mol
then:
3R = 24.94 J / K · mol
Heat capactiy per gram of a compound containing rubidium and oxygen is 0.64 J · K⁻¹ · g⁻¹
We try the possible empirical formula from the composition of Rb and O
- Rb₂O
So the number of atoms: 3 (Rb = 2 atoms, O = 1 atom)
Then the value of the Cp:
Molar mass Rb₂O = 2.85.5 + 1.16 = 187 g/mol
Then this empirical formula Rb₂O is not appropriate
- RbO₂
So the number of atoms: 3 (Rb = 1 atom, O = 2 atoms)
Then the value of the Cp:
Molar mass RbO₂ = 1.85.5 + 2.16 = 117.5 g / mol
Then this empirical formula RbO₂ is appropriate
<h3>Learn more </h3>
chemical bond
ionic bonding
electron dots
Keywords: an empirical formula,compound, gas constant, Dulong and Petit's rule,the molar heat capacity
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Answer : Both solutions contain molecules.
Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain molecules.
Avogadro's Number is =
which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.
Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.
Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.
Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.
We can calculate the number of molecules for each;
Number of molecules = ;
∴ Number of molecules = which will be =
Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.