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-BARSIC- [3]
2 years ago
8

What is empirical formula if compound consists of 21.2%N, 6.1%H, 24.2% and 48.5%O?

Chemistry
1 answer:
vichka [17]2 years ago
5 0

Answer:

                      Empirical Formula  =  N₂H₈SO₄   Or    (NH₄)₂SO₄

Explanation:

Step 1: Calculate Moles of each Element;

                     Moles of N  =  %N ÷ At.Mass of N

                     Moles of N  = 21.20 ÷ 14.01

                     Moles of N  =  1.5132 mol

                     Moles of H  =  %H ÷ At.Mass of H

                     Moles of H  = 6.10 ÷ 1.01

                     Moles of H  =  6.0396 mol

                     Moles of S  =  %S ÷ At.Mass of S

                     Moles of S  = 24.20 ÷ 32.06

                     Moles of S  =  0.7548 mol

                     Moles of O  =  %O ÷ At.Mass of O

                     Moles of O  = 48.50 ÷ 16.0

                     Moles of O  =  3.0312 mol

Step 2: Find out mole ratio and simplify it;

               N                                        H                                     S

           1.5132                              6.0396                             0.7548

    1.5132/0.7548                  6.0396/0.7548                 0.7548/0.7548

              <u>2</u>                                        <u>8</u>                                       <u>1</u>

                                                    O

                                                  3.0312

                                           3.0312/0.7548

                                                     <u>4</u>

Result:

       Empirical Formula  =  N₂H₈SO₄   Or    (NH₄)₂SO₄

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6 0
2 years ago
The volume of a single strontium atom is 4.15×10-23 cm3. What is the volume of a strontium atom in microliters
Ivenika [448]

Answer:-  4.15*10^-^2^0\mu L

Solution:- It is a volume unit conversion problem where we are asked to convert the volume from cm^3 to microliters.

We know that:

1cm^3 = 1 mL

1mL=10^-^3L

and, 1L=10^6\mu L

Let's use these conversions factors for the desired conversion using dimensional as:

4.15*10^-^2^3cm^3(\frac{1mL}{1cm^3})(\frac{10^-^3L}{1mL})(\frac{10^6\mu L}{1L})

= 4.15*10^-^2^0\mu L

So, the answer is  4.15*10^-^2^0\mu L .

7 0
2 years ago
22. How many atoms are there in 344.75 g of gold nugget? a. 1.05 x 10 to the power of 24 atoms b. 1.05 x 10 to the power of 23 a
mixas84 [53]

Answer:

1.053×10²⁴ atoms of gold

Explanation:

Hello,

Gold nugget are usually the natural occurring gold and they contain 85% - 90% weight of pure gold.

In this question, we're required to find the number of atoms in 344.75g of a gold nugget.

We can use mole concept relationship between Avogadro's number and molar mass.

1 mole = molar mass

Molar mass of gold = 197 g/mol

1 mole = Avogadro's number = 6.022 × 10²³ atoms

Number of mole = mass / molar mass

Mass = number of mole × molar mass

Mass = 1 × 197

Mass = 197g

197g is present in 6.022×10²³ atoms

344.75g will contain x atoms

x = (344.75 × 6.022×10²³) / 197

X = 1.053×10²⁴ atoms

Therefore 344.75g of gold nugget will contain 1.053×10²⁴ atoms of gold

5 0
2 years ago
Which mass of gas would occupy a volume of 3dm3 at 25°C and 1 atmosphere pressure?
balu736 [363]

Answer:

C 8.09 SO2 gas

Explanation:

As we have the volume (3dm³ = 3L), temperature (25°C + 273 = 298K), and pressure (1atm), we can solve to moles of gas using:

PV = nRT

PV / RT = n

1atm*3L / 0.082atmL/molK*298K =¨

0.123 moles of gas you have.

Now, to convert these moles to mass we use molar mass (32g/mol for O2, 28g/mol for N2, 64g/mol for SO2, and 44g/mol for CO2).

Mass of 0.123 moles of these gases is:

O2 = 0.123 moles * 32g/mol = 3.94g of O2. A is wrong

N2 = 0.123 moles * 28g/mol = 3.4g of N2. B is wrong

SO2 = 0.123 moles * 64.1g/mol = 7.9g of SO2≈ 8.09g of SO2, C is possible

CO2 = 0.123 moles * 44g/mol = 5.4g of CO2. D is wrong

Right answer is:

<h3>C 8.09 SO2 gas </h3>

8 0
2 years ago
In Philip’s French class, the students are learning how to pronounce closed vowels and open vowels. The students are most likely
Sladkaya [172]

Answer:

It sounds like they are studying French phonemes

Explanations:

I just learned this.

7 0
2 years ago
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