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2 years ago

What is empirical formula if compound consists of 21.2%N, 6.1%H, 24.2% and 48.5%O?

Chemistry

1 answer:

vichka [17]2 years ago

5 0

Answer:

Empirical Formula = N₂H₈SO₄ Or (NH₄)₂SO₄

Explanation:

Step 1: Calculate Moles of each Element;

Moles of N = %N ÷ At.Mass of N

Moles of N = 21.20 ÷ 14.01

Moles of N = 1.5132 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 6.10 ÷ 1.01

Moles of H = 6.0396 mol

Moles of S = %S ÷ At.Mass of S

Moles of S = 24.20 ÷ 32.06

Moles of S = 0.7548 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 48.50 ÷ 16.0

Moles of O = 3.0312 mol

Step 2: Find out mole ratio and simplify it;

N H S

1.5132 6.0396 0.7548

1.5132/0.7548 6.0396/0.7548 0.7548/0.7548

3.0312

3.0312/0.7548

Result:

Empirical Formula = N₂H₈SO₄ Or (NH₄)₂SO₄

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1 year ago

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<h3>Answer:</h3>

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<h3>Explanation:</h3>

The reaction is;

N₂(g) + O₂(g) ⇆ 2NO(g)

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2 years ago

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Answer:

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