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2 years ago

What is empirical formula if compound consists of 21.2%N, 6.1%H, 24.2% and 48.5%O?

Chemistry

1 answer:

vichka [17]2 years ago

5 0

Answer:

Empirical Formula = N₂H₈SO₄ Or (NH₄)₂SO₄

Explanation:

Step 1: Calculate Moles of each Element;

Moles of N = %N ÷ At.Mass of N

Moles of N = 21.20 ÷ 14.01

Moles of N = 1.5132 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 6.10 ÷ 1.01

Moles of H = 6.0396 mol

Moles of S = %S ÷ At.Mass of S

Moles of S = 24.20 ÷ 32.06

Moles of S = 0.7548 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 48.50 ÷ 16.0

Moles of O = 3.0312 mol

Step 2: Find out mole ratio and simplify it;

N H S

1.5132 6.0396 0.7548

1.5132/0.7548 6.0396/0.7548 0.7548/0.7548

2 8 1

3.0312

3.0312/0.7548

4

Result:

Empirical Formula = N₂H₈SO₄ Or (NH₄)₂SO₄

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C6H12O6 + 6O2 ---> 6H2O + 6CO2

Ivahew [28]

Answer:

24e⁻ are transferred by the reaction of respiration.

Explanation:

C₆H₁₂O₆ + 6O₂ → 6 H₂O + 6CO₂

This is the reaction for the respiration process.

In this redox, oxygen acts with 0 in the oxidation state on the reactant side, and -2 in the product side - REDUCTION

Carbon acts with 0 in the glucose (cause it is neutral), on the reactant side and it has +4, on the product side - OXIDATION

6C → 6C⁴⁺ + 24e⁻

In reactant side we have a neutral carbon, so as in the product side we have a carbon with +4, it had to lose 4e⁻ to get oxidized, but we have 6 carbons, so finally carbon has lost 24 e⁻

6O⁻² + 6O₂ + 24e⁻ → 6O₂²⁻ + 6O⁻²

In reactant side, we have 6 oxygen from the glucose (oxidation state of -2) and the diatomic molecule, with no charge (ground state), so in the product side, we have the oxygen from the dioxide with -2 and the oxygen from the water, also with -2 at the oxidation state. Finally the global charge for the product side is -36, and in reactant side is -12, so it has to win 24 e⁻ (those that were released by the C) to be reduced.

3 0

2 years ago

Given the following unbalanced chemical reaction: As + NaOH Na3AsO3 + H2 What would be the coefficient of the NaOH molecule in t

barxatty [35]

Answer: -

Explanation: -

The given unbalanced chemical equation is As + NaOH -- > Na3AsO3 + H2

We see there 3 sodium on the right side from Na3AsO3.

But there are only 1 sodium on the left from NaOH.

So we multiply NaOH by 3.

As + 3 NaOH -- > Na3AsO3 + H2

Now we see the number of Hydrogen on the left is 3.

But the number of hydrogens is 2 on the left.

So, we multiply to get both sides 6 hydrogen.

As + 6NaOH -- > Na3AsO3 + 3 H2

Rebalancing for Na,

As + 6NaOH -- > 2Na3AsO3 + 3 H2.

Finally balancing As,

2 As + 6 NaOH -- > 2Na3AsO3 + 3H2

The coefficient of the NaOH molecule in the balanced reaction is thus 6

7 0

2 years ago

3. A 0.500 g sample of nitrogen gas combines with 1.140 g of oxygen gas to form NO2. If the atomic mass of oxygen is 16.000, cal

DedPeter [7]

Answer;

= 18.24

Explanation;

The ratio of N and O in the formula NO2 IS 1:2

Mass of nitrogen gas is 0.500 g

Moles of nitrogen will be;

= 0.500/16 = 0.03125 moles

Therefore;

The moles of Oxygen from the ratio will be;

= 0.03125 × 2 = 0.0625 moles

But; 0.0625 moles is equal to 1.140 g of Oxygen

The atomic number (mass in 1 mole) will be;

= 1.140 /0.0625

= 18.24

Thus the atomic number of Oxygen from the data is 18.24

6 0

2 years ago

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Which of the reagents listed below would efficiently accomplish the transformation of ethyl-3-pentenoate into 3-penten-1-ol?

Mandarinka [93]

Reactions of Ethyl-3-pentenoate with all given reagents are given below.

Reaction with H₂ / Pd:
The non-polar double bond present in Ethyl-3-pentenoate is reduced to saturated chain. This reagent can not reduce the carbonyl group.

Reaction with NaBH₄:
Sodium Borohydride is a weak reducing agent at compared to LiAlH₄. It can only reduce aldehydes and Ketones to corresponding alcohols.

Reaction with LiAlH₄:
Lithium Aluminium hydride is a strong reducing agent. It can reduce all types of carbonyl compounds to corresponding alcohols, But, it can not reduce non-polar double bonds like alkenes and alkynes.

Result:
The correct answer is Option-A (Highlighted RED below).

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2 years ago

Write a balanced equation for the reaction of nach3coo (also written as nac2h3o2) and hcl. express your answer as a chemical equ

sammy [17]

NaCH3COO (s) + HCl (aq) ---> HCH3COO (aq) + NaCl (s)

4 0

2 years ago

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