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2 years ago

How will the following changes affect the mole fraction of chlorine gas, χcl2, in the equilibrium mixture.?

1 answer:

4 0

If the reaction is represented by:
PCl₃ + Cl₂ <-> PCl₅ (exothermic)

the mole fraction of chlorine in the equilibrium mixture will change according to the following:
Decrease the volume: decrease
Increase the temperature: increase
Increase the volume: increase
Decrease the temperature: decrease

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2.00 g of an unknown gas at STP fills a 500. mL flask. What is the molar mass of the gas?

otez555 [7]

Answer:

100g/mol

Explanation:

Given parameters:

Mass of unknown gas = 2g

Volume of gas in flask = 500mL = 0.5dm³

Unknown:

Molar mass of gas = ?

Solution:

Since we know the gas is at STP;

1 mole of substance occupies 22.4dm³ of space at STP

Therefore,

0.5dm³ will have 0.02mole at STP

Now;

Number of moles = $\frac{mass}{molar mass}$

Molar mass = $\frac{mass}{number of moles}$ = $\frac{2}{0.02}$ = 100g/mol

4 0

2 years ago

Describe how to prepare the solution using a 250.0 mL volumetric flask by placing the steps in the correct order. Not all of the

padilas [110]

Answer:

The correct order will be

a. Transfer the measured amount of NaCl to the volumetric flask.

e. Dissolve the NaCl in less than 250 mL of water and mix well.

b. Dilute the solution with water to the 250.0 mL mark.

Explanation:

Preparation of NaCl solution in 250.0 ml volumetric flask:

Add the weighed NaCl directly to volumetric flask and add small amount of water to it and mix it will until all NaCl gets dissolved( if not add small water amount of water more)

After dissolving NaCl add the water upto the mark.

The correct order will be

a. Transfer the measured amount of NaCl to the volumetric flask.

e. Dissolve the NaCl in less than 250 mL of water and mix well.

b. Dilute the solution with water to the 250.0 mL mark.

6 0

2 years ago

A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s

Mama L [17]

Use the formula, Q= mcT

Q= heat
m= mass= 1.900Kg= 1.900 x 10^3 grams
c= specific heat= 3.21
T= 4.542 K

Q= (1.900 x10^3g)(3.21)(4.542K)= 14.6 Joules.

7 0

2 years ago

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The nitrogen content of organic compounds can be determined by the Dumas method. The compound in question is first reacted by pa

MAVERICK [17]

Answer:

Mass percent of nitrogen in the compound is 13,3%

Explanation:

Dumas method is an analytical method to determine nitrogen content in samples, thus:

CₐHₓNₙ + (2a+x/2) CuO → aCO₂ + ˣ/₂ H₂O + ⁿ/₂ N₂ + (2a+x/2) Cu

As the CO₂ is removed with KOH, in the mixture you have H₂O and N₂

At 25°C. the vapor pressure of water is 23,8 torr, that means that the pressure due to N₂ is:

726torr - 23,8torr = 702,2 torr.

Using gas law:

n = PV/RT

Where:

P is pressure (702,2torr≡ 0,924 atm)

V is volume (0,0318L)

R is gas constant (0,082atmL/molK)

And T is temperature (25°C≡298,15K)

Replacing, number of moles of N₂, n, are:

n = 1,20x10⁻³moles of N₂. In grams:

1,20x10⁻³moles of N₂× $\frac{28g}{1mol}$ = 0,0336 g of N₂.

Thus, mass percent of nitrogen in the compound is:

$\frac{0,0336g N}{0,253gSample}$ ×100= 13,3%

I hope it helps!

7 0

2 years ago

a compound consists of 17.6% of hydrogen and 82.4% nitrogen. Determine the empirical formula of the compound

Wewaii [24]

17,6% + 82,6% = 100%

mass of N = 14g
mass of H = 1g

17,6% H = 17,6g H
82,4% N = 82,4g N

17,6g : 1g = 17,6 moles of H
82,4g : 14g = 5,89 moles of N

N : H = 5,89 : 17,6 ||:5,89
N : H = 1 : 2,99≈3

the empirical formula of the compound = NH₃ (ammonia)

6 0

2 years ago

Read 2 more answers