2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
c₁=2.00 mol/L
v₁=0.25 L
v₂=2.00 L
c₂-?
n(NaOH)=c₂v₂
n(H₂SO₄)=c₁v₁
n(NaOH)=2n(H₂SO₄)
c₂v₂=2c₁v₁
c₂=2c₁v₁/v₂
c₂=2*2.00*0.25/2.00=0.5 mol/L
0.5 M NaOH
Answer:
The answer is Option a, that is "−9kJmole,5kJmole".
Explanation:
Please find the complete question in the attached file.
In the question, it uses the catalyst inside a process, which does not modify the process eigenvalues, however, it decreases the active energy with an enthalpy of -9kJmole, and also the power for activating decreases around 13 to 5 kJ mole, that's why the choice a is correct.
During this phase Change heat energy is being absorbed by the molecules, and as a result the molecules possess a greater ability to move around and possess higher kinetic energy because of this. The molecules also possess a higher potential energy.
Answer:
Avogadro’s number was calculated by determining the number of atoms in 12.00 g of carbon-12.
Explanation:
The number of particles presents in one mole of a substance is known as Avogadro's number.
Avogadro's number is
atoms or molecules or ions or particles present in one mole of a substance. It is denoted by the symbol
or
. It is a dimensionless quantity.
Avogadro's number was proposed by Jean Perrin but named in the honor of italian scientist Amedeo Avogadro.
Avogadro's number is the number of atoms present in 12 grams of carbon-12.