1. I think you chose the right answer, the equation has the states of the reactants and products.
2. I think you chose the right answer.
3. I think you also chose the right answer. Assuming that the Hrxn is written as kJ per mol CH4
4. Heat of solution is the enthalpy change associated with dissolving a solute in a solvent. I think the first choice is the right one.
5. I think you chose the right answer.
Answer:
There were 0.00735 moles Pb^2+ in the solution
Explanation:
Step 1: Data given
Volume of the KI solution = 73.5 mL = 0.0735 L
Molarity of the KI solution = 0.200 M
Step 2: The balanced equation
2KI + Pb2+ → PbI2 + 2K+
Step 3: Calculate moles KI
moles = Molarity * volume
moles KI = 0.200M * 0.0735L = 0.0147 moles KI
Ste p 4: Calculate moles Pb^2+
For 2 moles KI we need 1 mol Pb^2+ to produce 1 mol PbI2 and 2 moles K+
For 0.0147 moles KI we need 0.0147 / 2 = 0.00735 moles Pb^2+
There were 0.00735 moles Pb^2+ in the solution
Answer:
See answer and picture below
Explanation:
In this case, the key to get an idea of how is the starting ether is with the final product and the empirical formula of the ether.
First, the empirical formula of the ether gives us information of the structure of the ether. This ether could be either an alkene, alkane or cycloalkane.
Alkane cannot be because alkane's formula is CnH(2n+2), so it's either an alkene or cycloalcane (CnH2n).
However, as we can see, it reacts with HI in excess, so, it cannot be an alkene because in this case the acid will react with the double bond of the ether too forming another product. This discart the fact that the ether has a double bond. So it has to be a cycloalkane.
As the innitial structure it's an ether, it should be either a cyclohexane or cyclopentane with a methyl group attached. So, how can we know which of these structures is? well, we can actually do the reaction with both reactants and see which match. In the attached picture you have the answer.
Hope this helps.
Answer:
The balanced reaction is:-

expression is:-
![K_{b}=\frac {\left [ C_6H_5COOH \right ]\left [ {OH}^- \right ]}{[C_6H_5COO^-]}](https://tex.z-dn.net/?f=K_%7Bb%7D%3D%5Cfrac%20%7B%5Cleft%20%5B%20C_6H_5COOH%20%5Cright%20%5D%5Cleft%20%5B%20%7BOH%7D%5E-%20%5Cright%20%5D%7D%7B%5BC_6H_5COO%5E-%5D%7D)
Explanation:
Benzoate ion is the conjugate base of the benzoic acid. It is a Bronsted-Lowry base and the dissociation of benzoate ion can be shown as:-

The expression for dissociation constant of benzoate ion is:
![K_{b}=\frac {\left [ C_6H_5COOH \right ]\left [ {OH}^- \right ]}{[C_6H_5COO^-]}](https://tex.z-dn.net/?f=K_%7Bb%7D%3D%5Cfrac%20%7B%5Cleft%20%5B%20C_6H_5COOH%20%5Cright%20%5D%5Cleft%20%5B%20%7BOH%7D%5E-%20%5Cright%20%5D%7D%7B%5BC_6H_5COO%5E-%5D%7D)
Answer: The Answer should be B. 0.887 (:
Explanation: