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2 years ago

Which of the following ions is formed when a base is dissolved in a solution? H+ O− OH− SO42+

Chemistry

1 answer:

77julia77 [94]2 years ago

3 0

Answer:

OH⁻

Explanation:

A base is defined as a substance which interacts with water to yield excess hydroxide ions, OH⁻, in an aqeous solution.

Examples are Sodium hydroxide (NaOH)

Potassium hydroxide (KOH)

Bases are generally certain metallic oxides, metallic hydroxides and aqueous ammonia.

An acid is a proton donor, H⁺ and it interacts with water to produce excess hydroxonium ions in an aqueous solution.

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A graduated cylinder holds 100 mL of water. A lead weight is dropped into the cylinder bringing the new volume up to 450 mL. If

dolphi86 [110]

11.43g/mL

Explanation:

Given parameters:

Volume of water in the graduated cylinder = 100mL

Volume of water + lead weight = 450mL

Mass of lead weight = 4000g

Unknown:

Density of the lead weight = ?

Solution:

Density is the mass per unit volume of a body.

Density = $\frac{mass}{volume}$

Volume of the lead weight = volume of water displaced

Volume of lead weight = 450 - 100 = 350mL

Density = $\frac{4000}{350}$ = 11.43g/mL

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2 years ago

Players 1, 2, 3 are playing a tournament. Two of these three players are randomly chosen to play a game in round one, with the w

Anastasy [175]

The answer & explanation for this question is given in the attachment below.

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2 years ago

A group of students are wandering around a room. when their teacher claps, the students sit down wherever they are. this situati

Oksi-84 [34.3K]

an amorphous solid because the particles do not have a regular structure is the answer

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2 years ago

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The pKs of succinic acid are 4.21 and 5.64. How many grams of monosodium succinate (FW = 140 g/mol) and disodium succinate (FW =

Varvara68 [4.7K]

Answer:

9.744g of monosodium succinate.

4.925g of disodium succinate.

Explanation:

To find pH of the buffer produced by the mixture of monosodium succinate-Disodium succinate is obtained from H-H equation:

pH = pKa + log ([Na₂Suc] / [NaHSuc])

As you want a pH of 5.28 and pKa is 5.64:

5.28 = 5.64 + log ([Na₂Suc] / [NaHSuc])

-0.36 = log ([Na₂Suc] / [NaHSuc])

0.4365 = ([Na₂Suc] / [NaHSuc]) (1)

As total concentration of the buffer is 100mM = 0.100M:

0.100M = [Na₂Suc] + [NaHSuc] (2)

Replacing (2) in (1):

0.4365 = (0.100M - [NaHSuc] / [NaHSuc])

0.4365 [NaHSuc] = 0.100M - [NaHSuc]

1.4365 [NaHSuc] = 0.100M

[NaHSuc] = 0.0696M

And:

[Na₂Suc] = 0.0304M

As volume of the buffer is 1L:

[NaHSuc] = 0.0696 moles

[Na₂Suc] = 0.0304 moles

Using molar mass of both substances:

Mass of monosodium succinate:

0.0696moles * (140g / 1mol) = 9.744g of monosodium succinate.

Mass of disodium succinate:

0.0304moles * (162g / 1mol) = 4.925g of disodium succinate.

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2 years ago

"The compound K2O2 also exists. A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O

o-na [289]

Answer:

Yes, the chemist can determine which compound is in the sample.

Explanation:

In 1 mole of K₂O, the mass of K is 2 × 39.1 g = 78.2 g and the mass of K₂O is 94.2 g. The mass ratio of K to K₂O is 78.2 g / 94.2 g = 0.830.

In 1 mole of K₂O₂, the mass of K is 2 × 39.1 g = 78.2 g and the mass of K₂O₂ is 110.2 g. The mass ratio of K to K₂O₂ is 78.2 g / 110.2 g = 0.710.

If the chemist knows the mass of K and the mass of the sample, he or she must calculate the mass ratio of K to the sample.

If the ratio is 0.830, the compound is pure K₂O.
If the ratio is 0.710, the compound is pure K₂O₂.
If the ratio is not 0.830 or 0.710, the sample is a mixture.

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2 years ago