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frutty [35]
2 years ago
15

g Select the irreversible reactions of glycolysis. conversion of glucose to glucose 6‑phosphate by hexokinase conversion of gluc

ose 6‑phosphate to fructose 6‑phosphate by phosphoglucose isomerase conversion of fructose 6‑phosphate to fructose 1,6‑bisphosphate by phosphofructokinase conversion of phosphoenolpyruvate to pyruvate by pyruvate kinase conversion of phosphoglycerate to phosphoenolpyruvate by enolase
Chemistry
1 answer:
alexdok [17]2 years ago
3 0

Answer:

1) Conversion of glucose to glucose 6-phosphate by hexokinase

2) Conversion of fructose 6-phosphate to fructose 1,6-biphosphate by phosphofructokinase

3) Conversion of phosphoenolpyruvate to pyruvate by pyruvate kinase

Explanation:

There are 10 steps in the glycolysis pathway, three of which are irreversible. The enzymes controlling these reactions have not only catalytic properties but the irreversibility of the reaction gives them regulatory properties as well.  These reactions serve as control points in the pathway.

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certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 40.00 gram sample of the alcohol pro
seraphim [82]

Answer:

The answer to your question is:    C₂H₆O₁   = C₂H₆O

Explanation:

Data

CxHyOz

mass = 40 g  produced 76.40 g of CO2

                                       46.96 g of H2O

Empirical formula = ?

Process

                         CxHyOz    + O2    ⇒    CO2  + H2O

                         44g of CO2 --------------------  12 g of Carbon

                         76.40 g of CO2 --------------- x

                          x = 20.84 g of Carbon

                         12 g of Carbon ---------------  1 mol

                         20.84 g of C    ---------------   x

                         x = (20.84 x 1) / 12

                         x = 1.74 mol of Carbon

                        18 g of H2O --------------------  2 g of H

                        46.96 g of H2O --------------   x

                        x = (46.96 x 2) / 18

                        x = 5.22 g of H

                        1 g of H ------------------------  1 mol of H

                        5.22 g of H -------------------   x

                        x = 5.22 mol of H

Mass of Oxygen = 40 - 20.84 - 5.22g

                           = 13.94 g

                         16 g of Oxygen ----------------  1 mol

                         13.94 g of O --------------------   x

                         x = 0.87 mol of O

Divide by the lowest number of moles

Carbon = 1.74 / 0.87 = 2

Hydrogen = 5.22 / 0.87 = 6

Oxygen = 0.87 / 0.87 = 1

                           

Empirical formula

                                 C₂H₆O₁   = C₂H₆O

                         

3 0
2 years ago
The French chemists, Pierre L. Dulong and Alexis T. Petit, noted in 1819 that the molar heat capacity of many solids at ordinary
natita [175]

The empirical formula of the compound : <u><em>RbO₂</em></u>

<h3>Further explanation</h3>

Dulong and Petit's rule's rule, which says that the molar heat capacity, Cp, of a solid can be expressed as

\large{\boxed{\bold{Cp=N(3R)}}

Where N is the number of atoms per formula unit and R is the universal gas constant

While the value of R is:

R = 8.3144621 J / K · mol

then:

3R = 24.94 J / K · mol

Heat capactiy per gram of a compound containing rubidium and oxygen is 0.64 J · K⁻¹ · g⁻¹

We try the possible empirical formula from the composition of Rb and O

  • Rb₂O

So the number of atoms: 3 (Rb = 2 atoms, O = 1 atom)

Then the value of the Cp:

Molar mass Rb₂O = 2.85.5 + 1.16 = 187 g/mol

\displaystyle Cp=N(3R)\\\\0.64=\frac{3.24.94}{187}\\\\0.64\neq0.4

Then this empirical formula Rb₂O  is not appropriate

  • RbO₂

So the number of atoms: 3 (Rb = 1 atom, O = 2 atoms)

Then the value of the Cp:

Molar mass RbO₂ = 1.85.5 + 2.16 = 117.5 g / mol

\displaystyle Cp=N(3R)\\\\0.64=\frac{3.24.94}{117.5}\\\\0.64=0.64

Then this empirical formula RbO₂  is appropriate

<h3>Learn more </h3>

chemical bond

brainly.com/question/5008811

ionic bonding

brainly.com/question/1603987

electron dots

brainly.com/question/6085185

 

Keywords:  an empirical formula,compound, gas constant, Dulong and Petit's rule,the molar heat capacity

#LearnWithBrainly

7 0
2 years ago
2 horizontal and parallel lines are intersected by 2 diagonal lines to form a triangle with exterior angles. The top angle of th
Sophie [7]

Answer:

x = 63

z = 117

x + z = 180

Explanation:

edg 2020

5 0
2 years ago
Calculate the ratio of effusion rates of cl2 to f2 .
Lelechka [254]
<span>Answer: Graham's law of gaseous effusion states that the rate of effusion goes by the inverse root of the gas' molar mass. râšM = constant Therefore for two gases the ratio rates is given by: r1 / r2 = âš(M2 / M1) For Cl2 and F2: r(Cl2) / r(F2) = âš{(37.9968)/(70.906)} = 0.732 (to 3.s.f.)</span>
4 0
2 years ago
An atom of the element zinc has an atomic number of 30 and a mass number of 65. How many protons does an uncharged zinc atom hav
navik [9.2K]

Answer : The correct option is, 30 protons

Explanation :

Element = Zinc

Atomic number = 30

Atomic mass number = 65

As we know that the atomic number is equal to the number of electrons and number of protons.

Atomic number = Number of electrons = Number of protons = 30

Number of neutrons = Atomic mass - Number of protons = 65 - 30 = 35

Therefore, the number of protons an uncharged zinc atom have 30 protons.

6 0
2 years ago
Read 2 more answers
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