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iogann1982 [59]
2 years ago
8

If a typical antacid tablet contains 2.0 g of sodium hydrogen carbonate, how many moles of carbon dioxide should one tablet yiel

d?
Chemistry
2 answers:
Sphinxa [80]2 years ago
7 0

Answer: The 2.0 grams of sodium hydrogen carbonate will yield 0.0238 moles of carbon-dioxide.

Explanation:

Mass of sodium hydrogen carbonate in 1 tablet = 2.0 g

NaHCO_3+ HCl\rightarrow NaCl+H_2O+CO_2

Moles of NaHCO_3=\frac{\text{Mass of }Na_2CO_3}{\text{Molar Mass of }Na_2CO_3}=\frac{2.0 g}{84 g/mol}=0.0238 moles

According to reaction 1 mole ofNa_2CO_3 gives 1 mole of CO_2 then 0.0238 mole ofNa_2CO_3 will give: \frac{1}{1}\times 0.0238 moles of CO_2 that is 0.0238 moles.

So, the 2.0 grams of sodium hydrogen carbonate will yield 0.0238 moles of carbon-dioxide.

ivolga24 [154]2 years ago
6 0
The equation of the chemical reaction is NaHCO3 + H+ --> H2O + CO2 + Na
To determine the total number of moles of carbon dioxide, the given mass of sodium hydrogen carbonate is divided with its own molar mass. Then it is multiplied with the ratio between NaHCO3 and carbon dioxide. The total number of moles of CO2 one tablet should yield is 0.024 mole.
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oee [108]
Moles oxygen = 0.0338 x 11 =0.372
atoms oxygen = 0.372 x 6.02 x 10^23=2.24 x 10^23
<span> moles water = 7 x 0.0338 =0.237 
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3 0
2 years ago
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A piece of antimony with a mass of 17.41 g is submerged in 46.3 cm3 of water in a graduated cylinder. The water level increases
kobusy [5.1K]

Answer:

6.696 g/cm3

Explanation:

From the question;

Mass = 17.41g

Volume of water before = 46.3 cm3

Volume of water after = 48.9 cm3

Volume of antimony = Volume after - Volume before = 48.9 - 46.3 = 2.6 cm3

Density = Mass / Volume

Density = 17.41 / 2.6 = 6.696 g/cm3

8 0
1 year ago
If 89.6 joules of heat are needed to heat 20.0 grams of iron from 30.0°c to 40.0°c, what is the specific heat of the iron in jg?
klasskru [66]
The relation of heat (Q), mass (m), and change of temperature (ΔT) is given by the formula:

Q = m*Cs*ΔT, where Cs is the specific heat of the material.

Then, given than you know Q, m and ΔT, you can solv for Cs:

Cs = Q / (m*ΔT)

Cs = 89.6 J / [20 grams * (40.0°C - 30.0°C)] = 0.448 J / g * °C.
 


6 0
2 years ago
consider the reaction between sulfite and a metal anion, X2-, to form the metal, X, and thiosulfate: 2 X2-(aq) + 2 SO32- + 3 H2O
Dafna11 [192]

Answer:

E_{red}^{0} for X is -1.20 V

Explanation:

Oxidation: 2\times[X^{2-}(aq.)-2e^{-}\rightarrow X(s)]

reduction: 2SO_{3}^{2-}(aq.)+3H_{2}O(l)+4e^{-}\rightarrow S_{2}O_{3}^{2-}(aq.)+6OH^{-}(aq.)

---------------------------------------------------------------------------------------------------

overall:2X^{2-}(aq.)+2SO_{3}^{2-}(aq.)+3H_{2}O(l)\rightarrow 2X(s)+S_{2}O_{3}^{2-}(aq.)+6OH^{-}(aq.)

So, E_{cell}^{0}=E_{red}^{0}(SO_{3}^{2-}\mid S_{2}O_{3}^{2-})-E_{red}^{0}(X\mid X^{2-})

or, 0.63=-0.57-E_{red}^{0}(X\mid X^{2-})

or, E_{red}^{0}(X\mid X^{2-})= -1.20

So, E_{red}^{0} for X is -1.20 V

8 0
2 years ago
Read 2 more answers
Which of the following species contains manganese with the highest oxidation number?
ioda

In NaMnO₄, Mn has the highest oxidation number.

The question is incomplete, the complete question is;

Which of the following species contains manganese with the highest oxidation number?

A) Mn

B) MnF₂

C) Mn₃(PO₄)₂

D) MnCl₄

E) NaMnO₄

In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.

1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.

2) For MnF₂;

Mn has an oxidation number of +2

3) For Mn₃(PO₄)₂

Mn has an oxidation number of +2

4) For MnCl₄

Mn has an oxidation number of +4

5) For NaMnO₄

Mn has an oxidation number of +7

Hence in NaMnO₄, Mn has the highest oxidation number.

Learn more: brainly.com/question/10079361

7 0
1 year ago
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