NH₃, being a basic gas neutralizes the HNO₃ forming a salt NH₄NO₃
Therefore the correct answer is NH₃ and NH₄NO₃
The solution of which only 32% dissociates to release OH⁻ ions is a weak base. This is because some of the energy is used when the substance reacts with the solution thus some bonds are not broken.
HCl is an acid. This is because it dissociates in water to give H⁺ as the only positively charged ions.
Arrhenius acid increases the concentration of hydrogen ions because it dissociates to release hydrogen ions as the only positively charged ions in the acid. So the answer is TRUE
Arrhenius base dissociates in water to release hydroxide ions as the only negatively charged ions.
NaOH⁺aq⇒Na⁺ ₍aq₎+ OH⁻₍aq₎
Answer:
Explanation:
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In this case, since these calorimetry problems are characterized by the fact that the calorimeter absorbs the heat released by the combustion of the substance, we can write:
Thus, given the temperature change and the total heat capacity, we obtain the following total heat of reaction:
Now, by dividing by the moles in 1.04 g of cyclopropane (42.09 g/mol) we obtain the enthalpy of combustion of this fuel:
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Answer:
Explanation:
Burning fossil fuels releases the carbon dioxide stored millions of years ago. ... The concentration of carbon dioxide in the atmosphere has increased more in the northern hemisphere where more fossil fuel burning occurs. Since the Industrial Revolution the concentration globally has increased by about 40 % .
So solve
this we must know the amount of sugar per gram of coffee
<span>i.
</span>10 g sugar /100 g coffee = 0.1 g sugar/ 1 g coffee
<span>ii.
</span>10 g sugar / 200 g coffee = 0.05 g sugar / 1 g coffee
<span>iii.
</span>4 g sugar / 200 g coffee = 0.02 g sugar / 1 g coffee
<span>iv.
</span>4 g sugar / 100 g coffee = 0.04 g sugar / 1 g coffee
So the ranking from sweetest so the least is:
<span> i, ii, iv, iii</span>
Answer:
Here's what I get
Explanation:
1. Balanced equation
HQ⁻ + CH₃-Br ⟶ HQ-CH₃ + Br⁻
(I must use HQ because the Brainly Editor thinks the O makes a forbidden word)
2. Mechanism
HQ⁻ + CH₃-Br ⟶[HQ···CH₃···Br]⁻⟶ HQ-CH₃ + Br⁻
A C B
The hydroxide ion attacks the back side of the carbon atom in the bromomethane (A).
At the same time as the Q-H bond starts to form, the C-Br bond starts to break.
At the half-way point, we have a high-energy intermediate (C) with partially formed C-O and C-Br bonds.
As the reaction proceeds further, the Br atom drops off to form the products — methanol and bromide ion (B).
3. Energy diagram
See the diagram below.
