Answer:
The freezing point will be
Explanation:
The depression in freezing point is a colligative property.
It is related to molality as:
Where
Kf=
the molality is calculated as:
Depression in freezing point =
The new freezing point =
A 0.100 l solution of 0.300 m agno3 is combined with a 0.100 l solution of 1.00 m na3po4. calculate the concentration of ag and
1 answer:
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Answer:
a. 123.9°C
b.
c.
Explanation:
Hello, I'm attaching a picture with the numerical development of this exercise.
a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.
b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.
c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.
** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.
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