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Scilla [17]
2 years ago
8

For a solar eclipse to occur which of the following alignments is necessary? A. The moon is located along a straight line betwee

n the sun and earth B. the is located along a straight line between the sun and moon C. the moon is located from a line between the sun and earth D. the earth is located from a line 90 degrees between the sun and moon
Chemistry
1 answer:
svlad2 [7]2 years ago
8 0

A. I'm pretty sure, could be C though..

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avogadro's number of representative particles is equal to one___. A) kilogram B)gram C)kelvin D)mole
a_sh-v [17]

D

Avogadro's number allows us to measure the amount of atoms or molecules in one mole of a substance.

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2 years ago
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Student Exploration: Collision Theory Vocabulary: activated complex, catalyst, chemical reaction, concentration, enzyme, half-li
Alika [10]

Answer:

1. Hot water

2. A pile of wood shavings

Explanation:

Sugar can dissolve more quickly in hot water than in cold water because there is more energy in hot water molecules. Because they are moving faster, they have more energy to break the bonds that hold sugar together. There is also more energy available to break the hydrogen bonds that hold water together.

Wood shavings have a greater contact surface than the solid hunk of wood, which is why they have a higher calorific value and then they will catch fire more easily.

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2 years ago
The chemical formula for artificial sweetener is C7H5NO3S. Match the elements with the numbers found in one molecule of artifici
klio [65]

its is 1.hydrogen                   2. oxygen            3. argon 4. carbon

7 0
2 years ago
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Answer:

C4H90H

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6 0
2 years ago
For the reaction below, Kp 5 1.16 at 800.8C. CaCO3(s) 34 CaO(s) 1 CO2(g) If a 20.0-g sample of CaCO3 is put into a 10.0-L contai
Elena L [17]

Answer:

The mass percentage of calcium carbonated reacted is 2.5%.

Explanation:

The reaction is:

CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Thus the Kp of the equilibrium will be:

Kp = partial pressure of carbon dioxide [as the other are solid]

Moles of calcium carbonate initially present = \frac{mass}{molarmass}=\frac{20}{100}=0.2

Let us apply ICE table to the equilibrium given:

                        CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Initial                       0.2                       0          0

Change                 -x                            +x        +x

Equilibrium           0.2-x                         x          x

Kp = partial pressure of carbon dioxide

Kp = Kc(RT)ⁿ

where n = difference in the number of moles of gaseous products and reactants

for given reaction n = 1

R = gas constant = 8.314 J /mol K

T = temperature = 800 ⁰C = 1073 K

Putting values

Kc =\frac{Kp}{RT}=\frac{1.16}{8.314X1073}=1.3X10^{-4}

Kc = \frac{[CO_{2}][CaO]}{[CaCO_{3}]}= \frac{x^{2} }{(0.2-x)}=1.3X10^{-4}

1.3X10^{-4}(0.2-x)=x^{2}

x^{2} = 0.26X10^{-4}-1.3X10^{-4}x

On calculating

x =  0.005

where x = the moles of calcium carbonate dissociated or reacted.

Percentage of the moles or mass reacted = \frac{molesreacted X100}{initialmoles}=\frac{0.005X100}{0.2}=2.5%

7 0
2 years ago
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