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Digiron [165]
2 years ago
9

Which substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes? a)CH4 b)H2S c)CO2 d)NaCl

Chemistry
1 answer:
schepotkina [342]2 years ago
8 0

Answer:

H_2S

Explanation:

Given the amount of heat absorbed and the amount of substance in moles, we may calculate the heat of vaporization. Heat of vaporization is defined as the amount of heat per 1 mole of substance required to evaporate that specific substance.

Based on the value of heat of vaporization, we will identify the substance. Firstly, let's calculate the heat of vaporization:

\Delta H^o = \frac{58.16 kJ}{3.11 mol} = 18.7 kJ/mol

Secondly, let's use any table for heat of vaporization values for substances. We identify that the heat of vaporization of H_2S is 18.7 kJ/mol

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Marie and Calvin dissolved 10 grams of KNO3 in 100 grams of water at 25oC. Next they added 5 grams more. Calvin told Marie that
PSYCHO15rus [73]
Hello!

Calvin told Marie that they could continue to add solute until the reached 40 grams because the solution was still unsaturated.

Unsaturated solutions are those in which the solvent (in this case water) can still dissolve more solute (in this case KNO₃) at the given pressure and temperature. This can be seen visually when adding more solute doesn't result in the presence of grains of solids that settle in the bottom of the flask. That happens because the rate of dissolving is higher than the rate of crystallization. 

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8 0
2 years ago
what is 31/50000 If the toxic quantity is 1.5 g of ethylene glycol per 1000 g of body mass, what percentage of ethylene glycol i
Sveta_85 [38]

Answer:

\%m=0.15\%

Explanation:

Hello,

In this case, we are asked to compute the by mass percent representing the toxicity of ethylene glycol in the body mass. In such a way, since the by mass percent is computed with the shown below formula:

\%m=\frac{m_{ethylene \ glycol}}{m_{ethylene \ glycol}+m_{body\ mass}}*100\%

We can use the given masses to obtain:

\%m=\frac{1.5g}{1.5g+1000g}*100\%\\ \\\%m=0.15\%

Best regards.

7 0
2 years ago
2.00 g of an unknown gas at STP fills a 500. mL flask. What is the molar mass of the gas?
otez555 [7]

Answer:

100g/mol

Explanation:

Given parameters:

Mass of unknown gas  = 2g

Volume of gas in flask  = 500mL  = 0.5dm³

Unknown:

Molar mass of gas = ?

Solution:

Since we know the gas is at STP;  

        1 mole of substance occupies 22.4dm³ of space at STP

    Therefore,

            0.5dm³ will have  0.02mole at STP

                     

Now;

   Number of moles  = \frac{mass}{molar mass}  

      Molar mass  = \frac{mass}{number of moles}   = \frac{2}{0.02}   = 100g/mol

4 0
2 years ago
Q 11.20: What is the product of the reaction between t-BuCl and MeOH? A : t-BuOH B : MeOCl C : t-BuOMe D : (CH3)2CCH2
Sholpan [36]

Answer:

C : t-BuOMe

Explanation:

The tert -butanol is a tertiary alcohol and when chloride ion attacks the carbocation, it forms t-BuCl.

The reaction of tert-butyl chloride or t-BuCl ((CH3)3C−Cl) with methanol and MeOH (CH3−OH) gives the product tert-Butyl methyl ether or t-BuOMe (CH3)3C−OCH3:

                   (CH3)3C−Cl + CH3−OH => (CH3)3C−OCH3 + HCl

Hence, the correct asnwer is C : t-BuOMe

5 0
2 years ago
There are three puddles of different sizes on a sidewalk:
nalin [4]

The one property that you can always depend on to change vapor pressure is temperature. So as the water's temperature increases so does the vapor pressure. The warmer the water, the higher the vapor pressure.

Blank one: Hot water

Blank Two: Temperature

7 0
2 years ago
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