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Combustion of 8.652 g of a compound containing c, h, o, and n yields 11.088 g of coz, 3.780 g of h2o, and 3.864 g of no2. How ma

Katyanochek1 [597]

Answer:- C = 3.024 g, H = 0.42 g, N = 1.176 g and O = 4.032 g

Solution:- The compound contains C, H, N and O. On combustion, all the carbon is converted to carbon dioxide, All hydrogen is converted to water and all the nitrogen is converted to nitrogen dioxide.

From the grams of all these, we could calculate their moles and then using mol ratio of these products and the number of moles of C, H and N present in them, we calculate the moles of C, H and N respectively. Further, these moles are converted to grams. On subtracting the sum of grams of C, H and N from the mass of the sample, the mass of oxygen is calculated.

The calculations are as follows:

Calculations for the grams of C:-

$11.088gCO_2(\frac{1molCO_2}{44gCO_2})(\frac{1molC}{1molCO_2})(\frac{12gC}{1molC})$

= 3.024 g C

Calculations for the grams of H:-

$3.780gH_2O(\frac{1molH_2O}{18gH_2O})(\frac{2molH}{1molH_2O})(\frac{1gH}{1molH})$

= 0.42 g H

Calculations for the grams of N:-

$3.864gNO_2(\frac{1molNO_2}{46gNO_2})(\frac{1molN}{1molNO_2})(\frac{14gN}{1molN})$

= 1.176 g N

Mass of the compound is given as 8.652 g. Now we could calculate the grams of oxygen as:

mass of oxygen = 8.652 - (3.024 + 0.42 + 1.176)

= 8.652 - 4.62

= 4.032 g

So, 8.652 grams of the compound contains 3.024 g of C, 0.42 g of H, 1.176 g of N and 4.032 g of O.

7 0

2 years ago

Compartments A and B are separated by a membrane that is permeable to K+ but not to Na+ or Cl-. At time zero, a solution of KCl

nikklg [1K]

Answer:

Incomplete question

Complete question:

8. Compartments A and B are separated by a membrane that is permeable to K+ but not to Na+ or Cl-. At time zero, a solution of KCl is poured into compartment A and an equally concentrated solution of NaCl is poured into compartment B. Which would be true once equilibrium is reached?

A. The concentration of Na+ in A will be higher than it was at time zero.

B. Diffusion of K+ from A to B will be greater than the diffusion of K+ from B to A.

C. There will be a potential difference across the membrane, with side B negative relative to side A.

D. The electrical and diffusion potentials for K+ will be equal in magnitude and opposite in direction.

E. The concentration of Cl- will be higher in B than it was at time zero.

Answer: D. The electrical and diffusion potentials for K+ will be equal in magnitude and opposite in direction.

Explanation:

Diffusion is the movement of molecules from region of higher concentration to lower concentration through a semipermeable membrane.

Since the k+ is the permeable membrane, the k+ ion in the KCl would move in equal magnitude and direction in the solution.

5 0

1 year ago

The gaseous product of a reaction is collected in a 25.0-l container at 27

nataly862011 [7]

To find the number of moles of gas we can use the ideal gas law equation, we dont need to use the mass of gas given as we only have to find the number of moles
PV = nRT
P - pressure - 300.0 kPa
V - volume - 25.0 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 27 °C + 273 = 300 K
substituting these values in the equation
300.0 kPa x 25.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K
n = 3.01 mol
number of mols of gas - 3.01 mol

4 0

2 years ago

How much heat is released during the formation of 3.18 mol HCl(g) in this reaction: H2(g)+Cl2(g) → 2HCl(g) with a H of -184.6 kJ

Vikentia [17]

The given thermochemical reaction is between hydrogen gas and chlorine gas to form hydrogen chloride.

This can be represented as:

$H_{2}(g)+Cl_{2}(g)-->2HCl(g)$ Δ $H_{reaction}^{0}$ =-184.6 kJ/mol

So when two moles of HCl is formed, 184.6 kJ of energy is released.

Calculating the heat released when 3.18 mol HCl (g) is formed in the reaction:

$3.18 molHCl*\frac{184.6kJ}{2molHCl} =293.5 kJ$

Therefore, 293.5 kJ of heat is released when 3.18 mol HCl is formed in the reaction between hydrogen and chlorine.

4 0

2 years ago

Read 2 more answers

Be sure to answer all parts. There are three different dichloroethylenes (molecular formula C2H2Cl2), which we can designate X,

sertanlavr [38]

Answer:

Explanation:Since the compound X has no net-dipole moment so we can ascertain that this compound is not associated with any polarity.

hence the compound must be overall non-polar. The net dipole moment of compound is zero means that the vector sum of individual dipoles are zero and hence the two individual bond dipoles associated with C-Cl bond must be oriented in the opposite directions with respect to each other.]

So we can propose that compound X must be trans alkene as only in trans compounds the individual bond dipoles cancel each other.

If one isomer of the alkene is trans then the other two isomers may be cis .

Since the two alkenes give the same molecular formula on hydrogenation which means they are quite similar and only slightly different.

The two possibility of cis structures are possible:

in the first way it is possible the one carbon has two chlorine substituents and the carbon has two hydrogens.

Or the other way could be that two chlorine atoms are present on the two carbon atoms in cis manner that is on the same side and two hydrogens are also present on the different carbon atoms in the same manner.

Kindly refer the attachments for the structure of compounds:

7 0

2 years ago