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Firlakuza [10]
2 years ago
8

3.4 moles of solid CuSO4 is added to 1.8 L of water and allowed to dissolve. Will all the solid dissolve?

Chemistry
1 answer:
ludmilkaskok [199]2 years ago
8 0

Answer:

                     Yes, all the solid will dissolve.

Explanation:

                    To solve this problem we will first find the solubility of CuSO₄ at given temperature (in this case we will assume the temperature to be 20 °C. According to reported data 37.8 g of CuSO₄ can be dissolved in 100 ml of H2O at 20 °C.

                    While we are provided with moles of CuSO₄ and volume is given in Liters. So, we will convert moles to mass as,

                                   Mass  =  Moles × Molar Mass

                                   Mass  =  3.4 mol × 159.60 g/mol

                                   Mass  =  542.64 g

Secondly, we will convert Liters to milliliters as,

                                  Milliliters  =  Liters × 1000

                                  Milliliters  =  1.8 × 1000

                                  Milliliters  =  1800 ml

Therefore,

According to reference data,

                     37.8 g CuSO₄ dissolves in  =  100 ml of water

So,

            542.64 g CuSO₄ will dissolve in  =  X ml of water

Solving for X,

                      X  =  542.64 g × 100 ml / 37.8 g

                      X =  1435.55 ml of Water

This means that we are provided with greater amount of water (i.e. 1800 m). Hence, the given amount of CuSO₄ will completely dissolve in 1.8 L of water and the solution formed is <em>unsaturated</em> and can dissolve further CuSO₄.

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Hey there!:

Molar mass MgCl2 = 95.2110 g/mol

So:

1 mole MgCl2 -------------- 95.2110 g

moles MgCl2 ---------------- 319 g

moles MgCl2 = 319 * 1 / 95.2110

moles MgCl2 = 319 / 95.2110

=> 3.350 moles of MgCl2


Hope that helps!

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