Answer:
HOMO of 1,3-butadiene and LUMO of ethylene
HOMO of ethylene LUMO of 1,3-butadiene
Explanation:
1,3 - butadiene underogoes cycloaddition reaction with ethylene to give cyclohexene.
According to Frontier molecular orbital theory HOMO of 1,3 butadiene and LUMO of ethylene and HOMO of ethylene and LUMO of ethylene underoges (4 + 2) in thermal or photochemical condition.
Convert 57.6 L to dm3 and divide it by 24
The moles of oxygen that are produced when 26.5 mol of Al2O3 decomposes is 39.8 mol
<u>calculation</u>
<u> </u> 2Al2O3 + 4Al +3 O2
- use the mole ratio of Al2O3 to O2 to determine the moles of O2.
- that is from the equation above the mole ratio of Al2O3 : O2 is 2:3
- the moles of O2 is therefore=n 26.5 mol x3/2= 39.8 moles
From Charle's law the volume of a fixed mass of a gas is directly proportional to the absolute temperature at constant pressure.
Therefore';
V1/T1=V2/T2
Where; V1 = 2.40 l, T1 = 273 +20= 293 K, V2 = 4.80, and T2= ?
2.4/293= 4.8/T2
T2= (4.8×293)/2.4
= 586 K or 313° C
Answer: 0.0007 moles of 
is released when temperature is raised.
Explanation:
To calculate the number of moles, we use the ideal gas equation, which is:
where,
P = pressure of the gas = 1.01 bar
V = Volume of the gas = 1L
R = Gas constant = 
- Number of moles when T = 20° C
Temperature of the gas = 20° C = (273 + 20)K = 293K
Putting values in above equation, we get:
- Number of moles when T = 25° C
Temperature of the gas = 25° C = (273 + 25)K = 298K
Putting values in above equation, we get:
- Number of moles released =
Hence, 0.0007 moles of is released when temperature is raised from 20° C to 25° C
