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2 years ago

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For each reaction, identify the element that gets reduced and the element that gets oxidized. 2AgCl+Zn⟶2Ag+ZnCl2 Identify the el

ement that gets reduced. chlorine zinc silver Identify the element that gets oxidized. chlorine silver zinc 4NH3+3O2⟶2N2+6H2O Identify the element that gets reduced. hydrogen oxygen nitrogen Identify the element that gets oxidized. nitrogen oxygen hydrogen Fe2O3+2Al⟶Al2O3+2Fe Identify the element that gets reduced. oxygen aluminum iron Identify the element that gets oxidized. aluminum oxygen iron

1 answer:

PolarNik [594]2 years ago

7 0

Answer:

Explanation:

Oxidation no is equal to charge on each atomic ion. If it is increased , element is oxidised and if it is decreased , element is reduced .

2AgCl+Zn⟶2Ag+ZnCl2

Zinc is oxidised , Ag is reduced .

Ag⁺ converts to Ag . ( oxidation number is reduced ) so Ag is reduced.

Zn converts to Zn⁺² ( oxidation number is increased ) so Zn is oxidised .

4NH₃+3O₂⟶2N₂+6H₂O

oxidation number of nitrogen in ammonia is - 3

oxidation no of nitrogen in nitrogen is zero.

Oxidation no of nitrogen is increased so it is oxidised.

oxidation no of oxygen is zero in oxygen and its oxidation no in water is -2 . So oxidation no is reduced so oxidation is reduced.

Fe₂O₃+2Al⟶Al₂O₃+2Fe

oxidation no of Fe in Fe₂O₃ is + 3 and it is zero in Fe so iron is reduced.

oxidation no of Al in Al is zero and it is +3 in Al₂O₃ so it is oxidised .

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Which of the following types of molecules always has a dipole moment? Linear molecules with two identical bonds. Trigonal pyrami

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Answer:

Trigonal pyramid molecules (three identical bonds)

Explanation:

In trigonal pyramidal molecule like molecule of ammonia , the vector some of intra- molecular dipole moment is not zero because the bonds are not symmetrically oriented . In other molecules , bonds are symmetrically oriented in space so the vector sum of all the internal dipole moment vectors cancel each other to make total dipole moment zero.

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2 years ago

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A) 5.2 x 10^2
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How many atoms of zirconium are in 0.3521 mol of zirconium?

lora16 [44]

Answer:

2.12×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.

Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:

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Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.

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A magnesium ion, Mg2+, with a charge of 3.2×10−19C and an oxide ion, O2−, with a charge of −3.2×10−19C, are separated by a dista

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Explanation:

Formula for work done is as follows.

W = $-k \frac{q_{1}q_{2}}{d}$

where, k = proportionality constant = $8.99 \times 10^{9} Jm/C^{2}$

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$q_{2} = charge of O_{2-} = -3.2 \times 10^{-19} C$

d = separation distance = 0.45 nm = $0.45 \times 10^{-9} m$

Now, we will put the given values into the above formula and calculate work done as follows.

W = $-k \frac{q_{1}q_{2}}{d}$

= $\frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}$

= $3.68 \times 10^{-18} J$

Thus, we can conclude that work required to increase the separation of the two ions to an infinite distance is $3.68 \times 10^{-18} J$ .

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Answer:

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