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2 years ago

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For each reaction, identify the element that gets reduced and the element that gets oxidized. 2AgCl+Zn⟶2Ag+ZnCl2 Identify the el

ement that gets reduced. chlorine zinc silver Identify the element that gets oxidized. chlorine silver zinc 4NH3+3O2⟶2N2+6H2O Identify the element that gets reduced. hydrogen oxygen nitrogen Identify the element that gets oxidized. nitrogen oxygen hydrogen Fe2O3+2Al⟶Al2O3+2Fe Identify the element that gets reduced. oxygen aluminum iron Identify the element that gets oxidized. aluminum oxygen iron

1 answer:

PolarNik [594]2 years ago

7 0

Answer:

Explanation:

Oxidation no is equal to charge on each atomic ion. If it is increased , element is oxidised and if it is decreased , element is reduced .

2AgCl+Zn⟶2Ag+ZnCl2

Zinc is oxidised , Ag is reduced .

Ag⁺ converts to Ag . ( oxidation number is reduced ) so Ag is reduced.

Zn converts to Zn⁺² ( oxidation number is increased ) so Zn is oxidised .

4NH₃+3O₂⟶2N₂+6H₂O

oxidation number of nitrogen in ammonia is - 3

oxidation no of nitrogen in nitrogen is zero.

Oxidation no of nitrogen is increased so it is oxidised.

oxidation no of oxygen is zero in oxygen and its oxidation no in water is -2 . So oxidation no is reduced so oxidation is reduced.

Fe₂O₃+2Al⟶Al₂O₃+2Fe

oxidation no of Fe in Fe₂O₃ is + 3 and it is zero in Fe so iron is reduced.

oxidation no of Al in Al is zero and it is +3 in Al₂O₃ so it is oxidised .

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Why a slow growing forest can have a very low NPP and yet store a massive amount of biomass.

drek231 [11]

Net Primary Productivity ... the amount of biomass present in an ecosystem at a particular time .... Explain why a slow growing forest can have a very low NPP and yet store a massive amount of biomass.

8 0

2 years ago

What is the change in enthalpy in kilojoules when 3.24 g of CH3OH is completely reacted according to the following reaction 2 CH

vodka [1.7K]

Answer:

12.78 kJ

Explanation:

The correct balanced reaction would be

$2CH_3OH\rightarrow 2CH_4+O_2\Delta H=252.8\ \text{kJ}$

Mass of methanol = $3.24\ \text{g}$

Moles of methanol can be obtained by dividing the mass of methanol with its molar mass $(32.04\ \text{g/mol})$

$\dfrac{3.24}{32.04}=0.10112\ \text{moles}$

Enthalpy change for the number of moles is given by

$\dfrac{\text{Number of moles of methanol in the reaction}}{\text{Enthalpy change in the reaction}}=\dfrac{\text{Number of moles in 3.24 g of methanol}}{\text{Enthaply in change in the mass of methanol}}$

$\\\Rightarrow\dfrac{2}{252.8}=\dfrac{0.10112}{\Delta H}\\\Rightarrow \Delta H=\dfrac{0.10112\times 252.8}{2}\\\Rightarrow \Delta H=12.781568\approx 12.78\ \text{kJ}$

The change in enthalpy is 12.78 kJ.

5 0

2 years ago

Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.

KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

$Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}$

Now put all the given values in this formula, we get the mass of solute KOH.

$0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}$

$\text{Mass of KOH}=5.292g$

Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0

2 years ago

Read 2 more answers

In an experiment, a scientist compares the effect of adding acid rain to

lilavasa [31]

Lake Minnetonka in Southern Minneosta is buffer solution

Explanation:

One can conclude from the observation that Lake Minnetonka is a buffer solution. A buffer solution is a special solution that resist changes in pH or pOH when a small amount of an acid or base is added.

Buffers are solutions in equilibrium with a fairly constant pH.
They are aqueous solutions containing weak acids and their salts or weak bases and their salts.
Since the pH of water sample from Lake Minnetonka did not change, it is a buffer.

Learn more:

buffer brainly.com/question/4431162

blood as a buffer brainly.com/question/12855542

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2 years ago

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4. a) The enthalpy change of combustion of hexane was measured using a calorimeter containing 200 cm3 of water; 0.5g of hexane (

mamaluj [8]

Answer:

The heat of combustion of hexane is -4324kjmol-1

Explanation:

Heat of combustion is the heat evolved when a mole of a substance is burned completely in oxygen under standard conditions.

To solve this problem, all the required values have been given.

Change in temperature ΔT = 30K

Mass of water =200cm3= 200g

Mass of Hexane burned = 0.5g

Step 1:

Find the amount of hear given off

Heat evolved= mass * specific eat capacity of water* temperature change

= 200 * 4.18 * 30

= 25080J

Step 2:

Calculate the relative molecular mass of hexane

RMM of C6H14 = 86g/mole.

Step 3:

Calculate the number of moles of Hexane burned

Numbrt of mole of hexane = mass / molar mass

n = 0.5 / 86

n = 0.0058mole

Step 4:

Calculate the enthalpy change of combustion for 1mole

Combustion of 0.0058mole hexane produces 25080J of heat energy

I mole hexane produces 25080 /0.0058

= 4324kJ of heat energy.

The enthalpy change of combustion of Hexane is -4,324kJmol-1.

There is no need to do anything else for the question.

7 0

2 years ago