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uysha [10]
2 years ago
10

During the lab, you will have access to a range of acids and bases as well as universal pH indicator paper. Think about how you

can use these tools to develop a color chart for the red cabbage indicator. Then, write a hypothesis using the “if/then” format.
Hypothesis:
Chemistry
2 answers:
kobusy [5.1K]2 years ago
6 0

Answer:

Explanation:bxbxbd

Delicious77 [7]2 years ago
6 0

Answer:

Sample Response (Do not copy and paste this is to learn it from the hypothesis, if you copy and paste 1 you wont learn it and 2 you will get marked for plagerism)

Explanation:

If you can measure the pH of a range of acids and bases using a universal pH indicator, then you can use those values to calibrate a cabbage pH indicator.

You might be interested in
Kaia, a chemical engineering graduate, has documented all titration procedures in her project report. She refers to this report
vagabundo [1.1K]

Answer:

The correct option is;

d. Explicit knowledge

Explanation:

Explicit knowledge is the knowledge that can be easily articulated documented stored in a retrieval system accesses, transmitted and shared with others

Tacit knowledge is the skill developed by an individual based on actual experience such that such knowledge comprise of both facts and perspectives

Hence explicit knowledge and tacit knowledge are complementary

The operations performed by Kaia include documentation, storing in a retrieval system (her project report) and accessing what she documented, this is an example of explicit knowledge.

7 0
2 years ago
A student titrates 10.00 milliliters of hydrochloric acid of unknown molarity with 1.000 m naoh. it takes 21.17 milliliters of b
Dima020 [189]
Mole ratio for the reaction is 1:1
no of moles in NaOH that reacted= 1*21.17/1000=0.02117mols
 molarity of HCl=0.02117*10/1000
                         =2.117M
4 0
2 years ago
What is the molality of sodium chloride in solution that is 13.0% by mass sodium chloride and that has a density of 1.10 g/ml?
8090 [49]
Answer is: molality od sodium chloride is 2,55 mol/kg.
V(solution) = 100 ml.
m(solution) = d(solution) · V(solution).
m(solution) = 1,10 g/ml · 100 ml.
m(solution) = 110 g.
ω(NaCl) = 13,0% = 0,13.
m(NaCl) = ω(NaCl) · m(solution).
m(NaCl) = 0,13 · 110 g.
m(NaCl) = 14,3 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 14,3 g ÷ 58,5 g/mol.
n(NaCl) = 0,244 mol.
m(H₂O) = 110 g - 14,3 g.
m(H₂O) = 95,7 g = 0,0957 kg.
b(NaCl) = n(NaCl) ÷ m(H₂O).
b(NaCl) = 0,244 mol ÷ 0,0957 kg.
b(NaCl) = 2,55 mol/kg.
3 0
2 years ago
A poisoned pill contains 0.00048 moles of KCN. How many molecules are in this sample?
mario62 [17]

Answer:

2.89 \times  {10}^{20}  \:  \: molecules

Explanation:

The number of molecules of KCN can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.00048 × 6.02 × 10²³

We have the final answer as

2.89 \times  {10}^{20}  \:  \:  \: molecules

Hope this helps you

7 0
1 year ago
If different atoms can come together to form all living and nonliving things, why is there a limit to different combinations we
prohojiy [21]

Answer: gas dissolved in liquid

Explanation:

3 0
2 years ago
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